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Atoms Test - 36

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Atoms Test - 36
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  • Question 1
    1 / -0
    If in hydrogen atom, radius of $$n^{th}$$ Bohr orbits is $$r_n$$, frequency of revolution of electron in $$n^{th}$$ orbit is $$f_n$$, choose the correct option.
    Solution
    Radius of $$n^{th}$$ orbit $$r_n \infty n^2$$, graph between $$r_n$$ and $$n$$ is a parabola. Also, $$\displaystyle \frac{r_n}{r_1} = \left(\frac{n}{1}\right)^2 \Rightarrow log_e\left(\frac{r_n}{r_1}\right) = 2log_e(n)$$ 
    Comparing this equation with $$y = mx + c$$,
    Graph between $$\displaystyle log_e \left(\frac{r_n}{r_1}\right)$$ and $$log_e(n)$$ will be straight line, passing from origin.
    Similarly it can be proved that graph between $$\displaystyle log_e \left(\frac{f_n}{f_1} \right)$$ and $$log_e(n)$$ is a straight line. But with negative slops.
  • Question 2
    1 / -0
    The specific charge for cathode rays is
    Solution
    Cathode rays (also called an electron beam or e-beam) are streams of electrons observed in vacuum tubes.
    Charge $$=-e$$
    Mass $$=m_e$$
    Specific Charge $$=\cfrac{Charge}{Mass} = \cfrac{e}{m_e}$$= Constant
  • Question 3
    1 / -0
    A photon will have less energy, if its 
    Solution
    Energy of photon = $$\dfrac{hc}{\lambda}$$
    Hence, a photon with longer wavelenght will carry less energy.
  • Question 4
    1 / -0
    Photons have the following characteristics:
    (i) energy of a photon $$E=h\gamma$$
    (ii) photons travel with the velocity of light
    (iii) photons are emitted when light of frequency $$\gamma$$ is emitted by an atom
    Solution
    (i), (ii), (iii)
    A photon is a particle of light defined as discrete bundles or quantum of electromagnetic energy. 
    Properties of photon :
    • Photons always moves with the speed of light. 
    • Photons are electrically neutral 
    • Photons have no mass but they have energy. 
    • $$E= hv$$ where h is the planks constant. 
    • The energy of each photon is inversely proportional to the wavelength of the associated EM wave. 
    • $$E= hv= h\cfrac{c}{\lambda}$$
    • Photons can be created or destroyed. 
  • Question 5
    1 / -0

    Directions For Questions

    A Rydberg hydrogenic atom is one in which the electron possesses a very large quantum number e.g. $$ n = 100 $$ . Take the electron charge to be $$ -e (e > 0) $$ . The binding energy of the Rydberg electron may be taken as $$ E_b = 10_{3} eV $$.

    ...view full instructions

    Let the energy of the electron confined in the atom be $$E$$ . At what $$F_0$$ would the atom ionize?
  • Question 6
    1 / -0
    The Bohr's orbit radius for the hydrogen atom (n = 1) is approximately 0.53 A. The radius for the first excited state (n = 2) orbit is:
    Solution
    Radius of nth orbit of hydrogen atom 
    $$r_m = 0.529 \times n^2$$
    Given n = 2 (where n is no. of orbit)

    $$\therefore r_n = 0.529 \times (2)^2 = 2.12 A$$
  • Question 7
    1 / -0
    To get line spectrum, the substances are excited in their
    Solution
    spectral line is a dark or bright line in an otherwise uniform and continuous spectrum, resulting from emission or absorption of light in a narrow frequency range, compared with the nearby frequencies. Spectral lines are often used to identify atoms and molecules from their characteristic spectral lines. The characteristics spectral is produced by exciting them into atomic state.
  • Question 8
    1 / -0
    For the same kinetic energy, the momentum shall be maximum for
    Solution
    $$ \begin{array}{l} \text { We know that, } \\ \qquad k=\frac{p^{2}}{2 m}\left\{\begin{array}{c} \text { Where, } k=\text { kinetic energy } \\ p \text { =momentum } \\ m=\text { mass } \end{array}\right. \end{array} $$ 
    $$ \begin{array}{l} P=\sqrt{2 m k} \\ P \alpha \sqrt{m}\{K \text { is constant given }\} \end{array} $$
     $$ \begin{array}{l} \therefore \alpha \text { - Particle has greater mass.then proton, neutron } \\ \therefore \text { Momentum of } \alpha \text { -particle is more and maximum } \\ \text { (D) Alpha particle is correct } \end{array} $$
  • Question 9
    1 / -0
    The radius of a nucleus with mass number 16 is 3 fm. The radius of another nucleus with mass number 128 is
    Solution
    We know that the radius of nucleus $$R$$ is related with the mass number $$A$$ by following relation:
                  $$R\propto A ^{1/3}$$ 

                  $$\dfrac{R_{2}}{R_{1}}=(\dfrac{A_{2}}{A_{1}})^{1/3}$$

    Given:   $$A_{1}=16 , A_{2}=128 , R_{1}=3\ fm , R_{2}=?$$ 

    Hence,  $$\dfrac{R_{2}}{3}=(\dfrac{128}{16})^{1/3}$$ 

                  $$\dfrac{R_{2}}{3}=(\dfrac{8}{1})^{1/3}$$ 

                  $$\dfrac{R_{2}}{3}=({2}^{3})^{1/3}$$ 

                  $$\dfrac{R_{2}}{3}=2$$ 

                  $$R_{2}=6fm$$
  • Question 10
    1 / -0
    The spectrum of light emitted by an electric bulb is an example of
    Solution

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