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Atoms Test - 38

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Atoms Test - 38
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  • Question 1
    1 / -0
    An element X has number of protons = 4. What will be its mass number if it has 3 neutrons?
    Solution
    Mass number of any element is equal to sum of number of neutron and number of proton.  
  • Question 2
    1 / -0
    The radius of hydrogen atom in the first excited level is
    Solution

  • Question 3
    1 / -0
    Fraunh offer line of the solar system is an example of:
    Solution
    Fraunhoffer line in the spectrum of solar system arises due to absorption of certain wavelength of sun rays coming from the core. While passing through the outer region, which is at low temperature, certain wavelengths are absorbed which results in dark lines in the spectrum.
  • Question 4
    1 / -0
    In a hydrogen atom, the electron is making $$6.6\times 10^{15} revs^{-1}$$ around the nucleus in an orbit of radius $$0.528 \overset{o}{A}$$. The magnetic moment $$(A-m^2)$$ will be.
    Solution
    Current, $$I=6.6\times 10^{15}\times 1.6\times 10^{-19}$$
    $$=10.5\times 10^{-4}A$$.
    Area $$A=\pi R^2=3.142\times (0.528)^2\times 10^{-20}m^2$$
    so, Magnetic moment
    $$M=IA=10.5\times 10^{-4}\times 3.142\times (0.528)^2\times 10^{-2}$$
    $$=10\times 10^{-24}=10^{-23}$$ units
  • Question 5
    1 / -0
    If an electron is revolving around the hydrogen nucleus at a distance of $$0.1$$nm, what should be its speed?
    Solution
    electrostatic force=centripetal force
    $$\displaystyle\frac{1}{4\pi \varepsilon_0}\frac{Ze^2}{r^2}=\frac{mv^2}{r}$$
    $$\therefore v=\sqrt{\left(\displaystyle\frac{1}{4\pi \varepsilon_0}\frac{Ze^2}{mr}\right)}$$
    $$=\sqrt{\displaystyle\frac{9\times 10^9\times 1\times (1.6\times 10^{-19})^2}{(9.1\times 10^{-31})\times (0.1\times 10^{-9})}} =1.59\times 10^6ms^{-1}$$
  • Question 6
    1 / -0
    Which of the following is not an inherent property of the photons?
    Solution
    A photon is a particle which has zero charge and zero mass and is denoted by $$\gamma$$. The energy of photon is
    $$E = hv$$
    Here,  $$v =$$ frequency and $$h =$$ Planck's constant.
    The momentum of the photon is $${h}/{v}$$ and its velocity is the velocity of light $$\left(c\right)$$.
    So, the charge is not the property of photons.
  • Question 7
    1 / -0
    The angular speed $$(\omega)$$ of an electron revolving in $$n^{th}$$ Bohr orbit and corresponding principal quantum number(n) are related as ____________.
    Solution
    Bohr's Model gives the following conclusions,
    $$v\propto\dfrac{1}{n}$$
    $$\Rightarrow r\propto{n^2}$$
    $$\Rightarrow \omega \propto \dfrac vr \propto \dfrac {1}{n^3}$$
  • Question 8
    1 / -0
    If a cathode ray tube has a potential difference $$V$$ volt between the cathode and anode, then the speed $$v$$ of cathode rays is given by:
    Solution
    $$qV=\cfrac { 1 }{ 2 } m{ v }^{ 2 }$$
    or $$v=\sqrt { \cfrac { 2qV }{ m }  } $$
    ie $$v\propto \sqrt { V } $$
  • Question 9
    1 / -0
    For the Paschen series the values of $${ n }_{ 1 }$$ and $${ n }_{ 2 }$$ in the expression $$\Delta E=Rhc\left( \dfrac { 1 }{ { n }_{ 1 }^{ 2 } } -\dfrac { 1 }{ { n }_{ 2 }^{ 2 } }  \right) $$ are
    Solution
    Paschen series is the third series of hydrogen spectrum and lies in the infrared region, therefore for this series, $${ n }_{ 1 }=3$$ and $${ n }_{ 2 }>{ n }_{ 1 }$$, ie, $$4,5,6,\dots $$
  • Question 10
    1 / -0
    The spectrum obtained from the chromosphere of the sun at the time of total solar eclipse is :
    Solution
    The spectrum obtained is the line emission spectrum of $${ D }_{ 3 }$$ line of neutral helium at $$5876 \mathring{A}$$ wavelength (almost yellow colour).
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