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Atoms Test - 42

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Atoms Test - 42
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  • Question 1
    1 / -0
    The nuclear radius of $$_{ 4 }^{  }{ { Be }^{ 8 } }$$ nucleus is :
    Solution
    Mass number of $$_4Be^8$$  $$A = 8$$
    Nuclear radius, $$R = R_o A^{1/3}$$            where $$R_o  = 1.3 \times 10^{-15} m$$
    $$\therefore$$  $$R = 1.3\times 10^{-15} \times 8^{1/3}$$ $$m$$
    $$\implies$$   $$R = 1.3\times 10^{-15} \times 2 = 2.6\times 10^{-15} m$$
  • Question 2
    1 / -0
    The characteristic spectrum of an atom is observed as
    Solution
    When atoms are excited they emit light of certain wavelengths which correspond to different colors and the emitted light is observed as a series of colored lines with dark spaces in between.  The series of colored lines are called a line or atomic spectra. Each element produces a unique set of spectral lines and since no two elements emit the same spectral lines, elements can be identified by their line spectrum.
  • Question 3
    1 / -0
    The cathode rays are
    Solution
    A cathode ray is a beam of electrons in a vacuum tube traveling from the negatively charged electrode (cathode) at one end to the positively charged electrode (anode) at the other, across a voltage difference between the electrodes. They are also called electron beams.
  • Question 4
    1 / -0
    Atomic spectrum should be :
    Solution
    When atoms are excited they emit light of certain wavelengths which correspond to different colors and the emitted light is observed as a series of colored lines with dark spaces in between. The series of colored lines are called a line or atomic spectra. Each element produces a unique set of spectral lines and since no two elements emit the same spectral lines, elements can be identified by their line spectrum. It can have either absorption or emission line spectrum depending whether the atom is light or another colliding electron.
  • Question 5
    1 / -0
    According to Rutherford atom model, the spectrum emitted by an atom is :
    Solution
    One of the defects of Ruherford atom model was if the electrons emit energy continuously, continuous spectrum should be formed. But in practical line spectrum is observed.
  • Question 6
    1 / -0
    The ratio of the radii of the first three Bohr Orbits is
    Solution
    Radius of $$n^{th}$$ Bohr orbit, $$r_n  = 0.529 \dfrac{n^2}{Z}$$ $$A^o$$
    $$\implies$$  $$r_n \propto n^2$$
    Thus ratio of first three Bohr orbit is $$r_1 : r_2 : r_ 3 = 1^2 : 2^2 : 3^ 2$$
    $$\implies$$  $$r_1 : r_2 : r_ 3 = 1 : 4 : 9$$
  • Question 7
    1 / -0
    In Hydrogen atom, which of the following transitions produces a spectral line of maximum frequency.
    Solution
    The Rydberg formula for Hydrogen atom, $$\dfrac{1}{\lambda}=R[1/n_1^2-1/n_2^2]$$ where $$R=$$ Rydberg constant and $$n_1<n_2$$
    For $$2\rightarrow 1$$, $$\dfrac{1}{\lambda_{21}}=R[1/1^2-1/2^2]=(3/4)R=0.75 R$$;
    For $$6\rightarrow 2$$, $$\dfrac{1}{\lambda_{62}}=R[1/2^2-1/6^2]=(2/9)R=0.22 R$$;
    For $$4\rightarrow 3$$, $$\dfrac{1}{\lambda_{43}}=R[1/3^2-1/4^2]=0.05R$$ and 
    For $$5\rightarrow 2$$, $$\dfrac{1}{\lambda_{52}}=R[1/2^2-1/5^2]=0.21R$$
    Since frequency is inversely proportional to wavelength so  $$2\rightarrow 1$$ transition will give the maximum frequency. 
  • Question 8
    1 / -0
    The number of de Broglie waves of an electron in the $${ n }^{ th }$$ orbit of an atom is :
    Solution
    The only places an electron can take in an atom are those where it can complete a multiple of a full wavelength. So when an electron (in wave form) starts from a certain point it must come back to the same point and be at the exact same position as when it started from that point. Otherwise, the wave wouldn't coincide with itself, and it would consequently interfere with itself and possibly destroy itself. This can't happen according to the laws of the conservation of matter and energy, so the electron only takes the orbits in which it can complete a number of full wavelengths. The number of waves is thus $$n$$.
  • Question 9
    1 / -0
    In a photon-electron collision ___________.
    Solution
    In a photon-electron collision both total energy and total momentum are conserved. As in the case of compton effect,  when a photon with some energy collides with a stationary electron, some of the energy and momentum is transferred to the electron  but both energy and momentum are conserved in this elastic collision.
    Option C
  • Question 10
    1 / -0
    As the electron in Bohr's orbit of hydrogen atom passes from state $$n=2$$ to, $$n=1$$, the kinetic energy$$(K)$$ and the potential energy $$(U)$$ changes as
    Solution
    Given,
    Electron in Bohr's orbit of hydrogen atom passes from state $$n=2$$ to $$n=1$$,
    KE of an electron in nth orbit : $$K_n \propto \dfrac{1}{n^2}$$ and PE of an electron in nth orbit : $$U_n\propto \dfrac{1}{n^2}$$
    $$\therefore$$ When an electron passes from state n = 2 to n = 1
    $$\dfrac{K_2}{K_1}=\dfrac{1^2}{2^2}=\dfrac{1}{4}$$
    or $$K_1=4K_2$$
    $$\dfrac{U_2}{U_1}=\dfrac{1^2}{2^2}=\dfrac{1}{4}$$
    or $$U_1=4U_2$$
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