Atoms Test

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Atoms Test - 6

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Weekly Quiz Competition

Question 1
1 / -0

Suppose you are given a chance to repeat the alpha-particle scattering experiment using a thin sheet of solid hydrogen in place of the gold foil. (Hydrogen is a solid at temperatures below 14 K.) What results do you expect?

A
there would be scattering at all angles

B
there would be no large-angle scattering

C
there would be scattering at 90^∘

D
there would be no scattering

Solution

Hydrogen atom is lighter than alpha particle so there will be no bouncing back of the alpha particle.
Question 2
1 / -0

In Rutherford’s model, the size of the nucleus of the atom is

A
10^-5 to 10^-6 m

B
10^-15 to 10^-14 m

C
10^-10 to 10^-12 m

D
10^-16 to 10^-17 m

Solution

Rutherford's experiments suggested the size of the nucleus to be about 10^-15 to 10^-14 m. From kinetic theory, the size of an atom was know to be 10^-10m.
Question 3
1 / -0

In the ground state of which model electrons are in stable equilibrium with zero net force?

A
Rutherford’s model

B
Bohr model

C
Thomson’s model

D
No model

Solution

In the atomic model proposed by J J Thomson, there are positive charges inside an atom and they neutralise the negative charge of the electron. Thus the electrons in this model are in stable equilibrium in the ground state.
Question 4
1 / -0

According to which model a classical atom is doomed to collapse?

A
Rutherford’s model

B
Bohr model

C
Thomson’s model

D
No model

Solution

The revolving electrons are constantly accelerated towards the nucleus. These accelerated electrons continuously radiate energy in the form of e.m.waves. Hence they move in circular path of continuously decreasing radii and eventually fall into the nucleus and doom to collapse.
Question 5
1 / -0

In which of the models an atom has a nearly continuous mass distribution?

A
Thomson’s model

B
Rutherford’s model

C
Bohr model

D
No model

Solution

In the atom, the electrons are embedded in the sphere of positive charge which is distributed uniformly throughout the volume of the atom.
Question 6
1 / -0

In which of the models an atom has a highly non-uniform mass distribution?

A
Rutherford’s model

B
Thomson’s model

C
Bohr model

D
No model

Solution

Rutherford concluded that while most of alpha particles experienced a little force, a few of them experienced a strong repulsive force. This may be possible only if there is extreme dense concentration of positive charge and most of the mass of the atom in the nucleus of the atom. Hence +ve charge of the atom is not be distributed uniformly through out the sphere.
Question 7
1 / -0

In which of the models, the positively charged part of the atom possesses most of the mass?

A
Rutherford’s model only

B
Thomson’s model and Rutherford’s model

C
Thomson’s model only

D
Bohr model only

Solution

According to Thomson model, an atom consists of a positively charged sphere with electrons filled in it. The positively charged part of the atom in this model is the atom itself and so it has the most mass.
According to Rutherford model, the positive charge and most of the mass of the atom is concentrated in the nucleus of the atom. The nucleus is thus the positively charged part of the atom and it has the most mass.
So both the models say that the positively charged part of the atom possesses most of the mass.
Question 8
1 / -0

A difference of 2.3 eV separates two energy levels in an atom. The frequency of radiation emitted when the atom make a transition from the upper level to the lower level is _____

A
5.1 ×10¹⁴ Hz

B
6.6 ×10¹⁴ Hz

C
6.1 ×10¹⁴ Hz

D
5.6 ×10¹⁴ Hz

Solution

If electron jumps from n₂orbit to n₁ orbit, then E₂ - E₁ = hv,
E₂ - E₁ = 2.3 eV = 2.3 x 1.6 x 10^-19 J
h plank's constant = 6.63 x 10^-34 Js
v is frequency = E₂ − E₁ / h
Question 9
1 / -0

The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?

A
13.6 eV, –27.2 eV

B
14.6 eV, –29.2 eV

C
14.6 eV, –27.2 eV

D
13.1 eV, –29.2 eV

Solution

Total energy, E = -13.6 eV
Since sum of energies is constant so
K.E = 13.6 eV (-E)
and P.E = -27.2 eV (2 K.E)

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Atoms Test - 6

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Atoms Test - 6

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Question 1

there would be scattering at all angles

there would be no large-angle scattering

there would be scattering at 90∘

there would be no scattering

Solution

Question 2

10-5 to 10-6 m

10-15 to 10-14 m

10-10 to 10-12 m

10-16 to 10-17 m

Solution

Question 3

Rutherford’s model

Bohr model

Thomson’s model

No model

Solution

Question 4

Rutherford’s model

Bohr model

Thomson’s model

No model

Solution

Question 5

Thomson’s model

Rutherford’s model

Bohr model

No model

Solution

Question 6

Rutherford’s model

Thomson’s model

Bohr model

No model

Solution

Question 7

Rutherford’s model only

Thomson’s model and Rutherford’s model

Thomson’s model only

Bohr model only

Solution

Question 8

5.1 ×1014 Hz

6.6 ×1014 Hz

6.1 ×1014 Hz

5.6 ×1014 Hz

Solution

Question 9

13.6 eV, –27.2 eV

14.6 eV, –29.2 eV

14.6 eV, –27.2 eV

13.1 eV, –29.2 eV

Solution

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there would be scattering at 90^∘

10^-5 to 10^-6 m

10^-15 to 10^-14 m

10^-10 to 10^-12 m

10^-16 to 10^-17 m

5.1 ×10¹⁴ Hz

6.6 ×10¹⁴ Hz

6.1 ×10¹⁴ Hz

5.6 ×10¹⁴ Hz