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Atoms Test - 62

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Atoms Test - 62
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  • Question 1
    1 / -0
    The number of nodal sphere of $$3s-$$orbital are
    Solution

  • Question 2
    1 / -0
    The radius of hydrogen atom, when it is in its second excited state, becomes :
    Solution
    The relation between the radius and the orbit of the atom is:
    $$r\propto n^2$$

    For second excited state, $$n=3$$.
    $$r \propto (3)^2$$

    $$\Rightarrow r\propto 9$$
  • Question 3
    1 / -0
    The order of size of nucleus and Bohr radius of an atom respectively are :
    Solution

  • Question 4
    1 / -0
    A particle moving with a velocity $$\dfrac{1}{10}th$$ of light will cross a nucleus in about:
    Solution

  • Question 5
    1 / -0
    Stability of half filled sub-shell is caused by :
    Solution

  • Question 6
    1 / -0
    Number of lobes of $$2p-$$orbital as in $$yz-$$plane is :
    Solution

  • Question 7
    1 / -0
    The mass of an electron in motion depends upon :
    Solution

  • Question 8
    1 / -0
    In Bohr's radius is $$R_0$$ then radius of $$3^{rd}$$ orbit of hydrogen atom will be :
    Solution

  • Question 9
    1 / -0
    Mark out the incorrect statement:
    Solution
    When a free neutron decays to a proton along with an electron and an antineutrino, the $$Q$$ value of the reaction is positive which means the reaction is possible all by itself. Hence, statement A is correct.
    A free proton cannot convert itself into a neutron due to negative $$Q$$ value. Hence, statement B is incorrect.
    In beta minus decay, the electron originates from nucleus only, by the transformation of neutron into a proton, with simultaneous emission of an antineutrino, this reaction is same as the first one and so it is feasible. Hence, statement C is correct.
  • Question 10
    1 / -0
    Taking the Bohr radius as $$a_0 = 53 pm$$, the radius of $$Li^{++}$$ ion in its ground state, on the basis of Bohr's model, will be about
    Solution
    According to Bohr's model of atom, radius of an atom in its ground state is $$r = \dfrac{r_o}{z}$$ where $$r_o$$ is Bohr's radius, and Z is atomic number.
    As $$r_o = 53 pm$$ and atomic number of Lithium atom is $$3$$ so, $$r = \dfrac{53}{3} = 17.67 pm  = 18 pm$$ verifies option (c).
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