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Atoms Test - 65

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Atoms Test - 65
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Weekly Quiz Competition
  • Question 1
    1 / -0
    In Bohr's model of hydrogen atom, which of the following pairs of quantities are quantized
    Solution

  • Question 2
    1 / -0
    The boher model of atoms
    Solution

    Bohr defined stable orbits of electron revolution in his second postulate. According to this postulate:

    ·        An electron revolves around the nucleus in orbits.

    ·        The angular momentum of revolution is an integral multiple of h/2π where h is Planck’s constant.

    Hence, the angular momentum (L) of the orbiting electron is: L = nh/2π, which is quantized.  (Option A is correct)
  • Question 3
    1 / -0
    The possible quantum number for $$3d$$ electron are 
    Solution

  • Question 4
    1 / -0
    The radius of the first ( lowest ) orbit of the hydrogen atom is $$a_0$$. The radius of the second ( next higher ) orbit will be 
    Solution
    $$r_n=\dfrac{n^2}{z}a_b$$
    $$r_1=\dfrac{1}{L}a_0$$
    $$r_1=a_0$$
    $$r_2=\dfrac{(2)^2}{1}a_0$$
    $$r_2=4a_0$$
  • Question 5
    1 / -0
    Radius of first Bohr orbit is $$r$$. What is the radius of $$2-$$Bohr orbit?
    Solution

  • Question 6
    1 / -0
    Which of the following is quantised according to Bohr's theory of hydrogen atom 
    Solution

  • Question 7
    1 / -0
    The spectrum obtained from a sodium vapour lamp is an example of
    Solution
    Sodium light gives emission spectrum having two yellow lines.
  • Question 8
    1 / -0
    The colour of the second line of Balmer series is
    Solution

  • Question 9
    1 / -0
    When light emitted by a white hot solid is passed through a sodium flame, the spectrum of the emergent light will show
    Solution
    When light emitted by a white hot solid passes through sodium vapour then cooler sodium vapour absorb energy from white light spectrum producing spectrum of bright yellow light with two dark lines in the yellow region.
  • Question 10
    1 / -0
    When a hydrogen atom is raised from ground to excited state.
    Solution
    Potential energy of hydrogen atom is given by
    $$P.E=\dfrac{-kZe}{r}$$
    As atom is excited,it's radius increases. But due to negative sign or reverse sign. Its actual potential energy increases.
    And kinetic energy is given by
    $$K.E=\dfrac{kZe}{2r}$$
    As Tom is excited, it's radius increases this resulting in decrease of kinetic energy.
    The PE increases and KE decreases.
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