Atoms Test - 69...

In which transition is a Balmer series photon absorbed?

The ratio between Bohr radii is

If the atom $$_{100} Fm^{257}$$ follows the Bohr model and the radius of $$_{100} Fm^{257}$$ is n times the Bohr radius, then find $$n$$.

The radius of the first orbit of hydrogen is $$r_H$$, and the energy in the ground state is $$-13.6$$eV. Considering a $$\mu^-$$-particle with a mass $$207$$ $$m_e$$ revolving round a proton as in Hydrogen atom, the energy and radius of proton and $$\mu^-$$ combination respectively in the first orbit are: 

A donor atom in a semiconductor has a loosely bound electron. The orbit of this electron is considerably affected by the semiconductor material but behaves in many ways like an electron orbiting a hydrogen nucleus. Given that the electrons has an effective mass of $$0.07\ m_e$$ (where $$m_{e}$$ is mass of the free electron) and the space in which it moves has a permittivity $$13\epsilon_{0}$$, then the radius of the electron's lowermost energy orbit will be close to (The Bohr radius of the hydrogen atom is $$0.53\overset {\circ}{A})$$.

The number of revolutions per second made by an electron in the first Bohr's orbit of hydrogen atom is(Given, $$r=0.53\overset{o}{A}$$).

To calculate the size of a hydrogen anion using the Bohr model, we assume that its two electrons move in an orbit such that they are always on diametrically opposite sides of the nucleus. With each electron having the angular momentum $$\hbar = h/2\pi$$, and taking electron interaction into account the radius of the orbit in terms of the Bohr radius of hydrogen atom $$a_{B}= \dfrac {4\pi \epsilon_{0}\hbar^{2}}{me^{2}}$$ is

In the Bohr model of a hydrogen atom, the centripetal force is furnished by the coulomb attraction between the proton and the electron. If $$a_0$$ is the radius of the ground state orbit, m is the mass and e is the charge on the election and $$\varepsilon_0$$ is the vacuum permittivity, the speed of the electron is?

To calculate the size of a hydrogen anion using the Bohr model, we assume that its two electrons move in an orbit such that they are always on diametrically opposite sides of the nucleus. With each electron having the angular momentum equal to $$\dfrac{h}{ 2 \pi}$$, and taking electron interaction into account the radius of the orbit in terms of the Bohr radius of hydrogen atom $$a_B=\displaystyle\frac{4\pi \epsilon_0h^2}{me^2}$$ is?

Given mass number of glod=197, density of gold=19.7 g per $$cm^3$$, Avogadro's number = $$6\times 10^{23}$$.The radius of the gold atom is approximately: