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Atoms Test - 7

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Atoms Test - 7
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Weekly Quiz Competition
  • Question 1
    1 / -0

    In accordance with the Bohr’s model, find the quantum number that characterises the earth’s revolution around the sun in an orbit of radius 1.5 × 1011 m with orbital speed 3 × 104 m/s. (Mass of earth= 6.0 × 1024 kg.)

    Solution

    Angular momentum mvr = nh/2π ,  n = 2.6 × 1074.

  • Question 2
    1 / -0

    Average angle of deflection of α -particles by a thin gold foil predicted by Thomson’s model is

    Solution

    The alpha particles which pass close to the nucleus (positively charged) suffer a strong electrostatic force and are scattered through large angles ( Rutheford's explanation). Thomson model was unable to explain large angle scattering of alpha particles. However, the average angle of deflection suggested by both is about the same size. 

  • Question 3
    1 / -0

    Probability of backward scattering (i.e., scattering of α -particles at angles greater than 90) predicted by Thomson’s model is

    Solution

    A few small number of particles (1 in 8000) experienced a strong electrostatic repulsive force and thus deflected by more than 90o.

  • Question 4
    1 / -0

    It is found experimentally that for small thickness t, the number of α-particles scattered at moderate angles is proportional to t. What clue does this linear dependence on t provide?

    Solution

    Scattering occurs due to collisions, mainly single collision. As number of target atoms increases, the chances of collision also increases linearly. Increase in the thickness (t) of the foil increases the number of the target atoms and thus increases the chances of single collisions.

  • Question 5
    1 / -0

    In which model is it completely wrong to ignore multiple scattering for the calculation of average angle of scattering of α -particles by a thin foil?

    Solution

    Thomson proposed the plum pudding model of the atom. Here the scattering angle, caused due to collision with the electrons spread in the atom, will be very less. It would require multiple scattering to get a large deflection. Hence, we cannot ignore multiple scattering when calculating average angle of scattering of alpha particles by a thin foil.

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