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Nuclei Test - 37

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Nuclei Test - 37
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  • Question 1
    1 / -0
    The difference between the sum of the masses of the constituent particles and the mass of an atom is called ___________.
    Solution
    The difference between the sum of the masses of the constituent particles and the mass of an atom is called mass defect.
    The energy released due to mass defect was given by Einstein
    $$E=\triangle mc^2$$
  • Question 2
    1 / -0
    The radiant energy of the sun results from
    Solution
    $$ \begin{array}{l} \text { The radient energgy of is result of } \\ \text { nuclear fusion. The energy from both }\\ \text{heat and light originates from a nuclear fusion}\\ \therefore \text { (A) option is correct. } \end{array} $$
  • Question 3
    1 / -0
    $${ _{ 7 }{ { N }^{ 14 } }_{  } }$$ is bombarded with an $$\left(\alpha\right)$$ alfa particle to produce a proto and an unknown nucleus $$'X', $$ 
    $${ _{ 7 }{ { N }^{ 14 } }_{  } } + \alpha$$ (particle)  $$\longrightarrow X + p$$
    Then $$'X'$$ stands for
    Solution
    The required reaction is
    $${ _{ 7 }{ { N }^{ 14 } }_{  } }+{ _{ 2 }{ { He }^{ 4 } }_{  } }\longrightarrow { _{ 8 }{ { O }^{ 17 } }_{  } }+{ _{ 1 }{ { H }^{ 1 } }_{  } }$$
  • Question 4
    1 / -0
    What are the different isotopes formed when protons combine to form a $$_{2}{He}^{4}$$ nucleus ?
    Solution
    $$_1^1H$$ and $$_2^3He$$ combine to form $$_2He^4$$ nucleus.
    $$_{ 2 }^{ 3 }{ He }+_{ 1 }^{ 1 }{ H }\rightarrow  _{ 2 }{ He }^{ 4 }+E$$
  • Question 5
    1 / -0
    What is the mass defect and the binding energy of $$_{27}{Co}^{59}$$ which has a nucleus of mass of $$58.933  u$$ ? $$\left({m}_{p} = 1.0078  u,   {m}_{n} = 1.0087  u \right)$$
    Solution
    In $$_{27}{Co}^{59}$$ number of protons $$= 27$$.
    Number of neutrons $$= 59 - 27 = 32$$.
    $$\therefore$$  The total mass of the nucleus $$= 27 \times 1.0078  u + 32 \times 1.0087  u = 27.2106  u + 32.2784  u = 59.489  u$$.
    Given, the actual mass of the nucleus $$= 58.933  u$$.
    $$\therefore$$ The mass defect $$= 59.489  u - 58.933  u = 0.556  u$$.
    $$\therefore$$  The binding energy $$= \Delta m \times 931.5  MeV = 0.556  u \times 931.5  MeV = 517.914  MeV$$.
  • Question 6
    1 / -0
    Complete the following reaction.
    $$_{13}{Al}^{27} + $$ __________   $$\rightarrow  _{15}{P}^{30} + _{0}{n}^{1}$$
    Solution
    $${ _{ 13 }{ Al }^{ 27 } }+{ _{ 2 }{ \alpha  }^{ 4 } }\rightarrow { _{ 15 }{ P }^{ 30 } }+{ _{ 0 }{ n }^{ 1 } }$$
    Atomic No.  : 13+2=15+0  
    Mass No. :    27+4=30+1
    So, $$\alpha$$ particle will be emitted.
  • Question 7
    1 / -0
    Which scientist proposed the concept of atomic mass?
    Solution
    The concept of atomic mass was proposed by William Prout. Early atomic mass theory was proposed by the English chemist William Prout in a series of published papers in 1815 and 1816. Known as Prout's Law, Prout suggested that the known elements had atomic weights that were whole number multiples of the atomic mass of hydrogen.

    Option C is correct.
  • Question 8
    1 / -0
    Chlorine has ______isotopes.
    Solution
    Chlorine has two isotopes $$_{17}^{35} Cl$$ and $$_{17}^{37} Cl$$ each isotope in its Nucleus has 17 protons.
  • Question 9
    1 / -0
    What is the atomic mass (u) of chlorine?
    Solution
    Chlorine is a chemical element with the symbol Cl and atomic number 17. The second-lightest of the halogens, it appears between fluorine and bromine in the periodic table and its properties are mostly intermediate between them.

    The atomic mass (u) of Chlorine is 35.5u.
  • Question 10
    1 / -0
    Carbon has __________ isotopes. 
    Solution
    Carbon has three isotopes $$_6^{12} C, \ \  _6^{13} C \ \ and \ \  _6^{14} C$$ 
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