Nuclei Test

Result

Nuclei Test - 70

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

$${{\text{Bi}}^{{\text{210}}}}$$ has half life of 5 days. The time taken for $$\dfrac{7}{8}$$th of a sample to decay is___ days

A
15

B
3.4

C
10

D
20

Solution
Question 2
1 / -0

The binding energy per nucleon for a deuterium is 1.115 MeV. Mass deflect for this nucleus is about -

A
2.23 u

B
0.0024

C
0.027 u

D
0.0012 u

Solution
Question 3
1 / -0

Atomic weight of boron is 10.81 and it has two isotopses $$ _5B^{10} and _5B^{11} $$ . then the ratio of $$ _5B^{10} : _5B^{11} $$ in nature would be

A
15 : 16

B
10: 11

C
19 : 81

D
81 ; 19

Solution
Question 4
1 / -0

Atomic weight of Boron is $$10.81$$ and it has two isotopes $$_{5}B_{10}$$ and $$_{5}B_{11}$$, then the ratio of $$_{5}B^{10} : _{5}B^{11}$$ in nature would be

A
$$15 : 16$$

B
$$10 : 11$$

C
$$19 : 81$$

D
$$81 : 19$$

Solution
Question 5
1 / -0

The binding energy per nucleon for a $$_6{C^{12}}$$ the nucleus is
( nuclear mass of $$_6{C^{12}}$$ =12.00000 a.m.u.
Mass of hydrogen nucleus = 1.007825 a.m.u.
Mass of neutron =1.00 8665 a.m.u)

A
2.675 MeV

B
7.675 MeV

C
0 MeV

D
3.675 MeV

Solution
Question 6
1 / -0

For $${\text{N = }}{{\text{N}}_0}{e^{ - kt}}and\,{t_2} > {t_1},$$ the number of nuclei disintegrating between $${t_1}\,and\,{t_2}$$ is..............

A
$${{\text{N}}_0}[{e^{ - \lambda t_1}} - {e^{ - \lambda t_2}}]$$

B
$${{\text{N}}_0}[{e^{ - \lambda t_2}} - {e^{ - \lambda t_1}}]$$

C
$${{\text{N}}_0}[{e^{\lambda t_2}} - {e^{\lambda t_1}}]$$

D
none of the above.

Solution
Question 7
1 / -0

How much energy is released when $$1$$ amu of mass is annihilated?

A
$$931.5\,MeV$$

B
$$1.49 \times {10^{ - 3}}J$$

C
$$4.138 \times {10^{ - 17}}\,kWh$$

D
All of these

Solution
Question 8
1 / -0

If $$M(A,Z)$$, $$ M_p$$ and $$M_n $$ denote the masses of the nucleus $$^A_ZX , $$ proton and neutron respectively in units of $$u$$ $$( 1u = 931.5 MeV /C^2 )$$ and BE represents its bonding energy in $$MeV$$, then

A
$$ M(A, Z) = ZM_p + (A-Z)M_n + BE/C^2 $$

B
$$ M(A, Z) = ZM_p + (A-Z)M_n - BE/C^2 $$

C
$$ M(A, Z) = ZM_p + (A-Z)M_n + BE $$

D
$$ M(A, Z) = ZM_p + (A-Z)M_n - BE $$

Solution
Question 9
1 / -0

The mass of proton is $$1.0073 u$$ and that of neutron is $$1.0087 u$$ ($${ u } =$$ atomic mass unit). The binding energy of $$_ { 2 } H e ^ { 4 }$$ is (Given, mass of helium nucleus $$= 4.0015{ u }$$ )

A
$$28.4{ MeV }$$

B
$$62.4{ MeV }$$

C
$$42.4{ MeV }$$

D
$$10.2{ MeV }$$

Solution
Question 10
1 / -0

Assuming that about $$20MeV$$ of energy is released per fusion reaction $${ _{ 1 }^{ }{ H } }^{ 2 }+{ _{ 1 }^{ }{ H } }^{ 3 }\longrightarrow { _{ 0 }^{ }{ n } }^{ 1 }+{ _{ 2 }^{ }{ He } }^{ 4 }$$, the mass of $${ _{ 1 }^{ }{ H } }^{ 2 }$$ consumed per day in a future fusion of power $$1MW$$ would be approximately

A
$$0.1gm$$

B
$$0.01gm$$

C
$$1gm$$

D
$$10gm$$

Solution