Semiconductor Electronics: Materials, Devices and Simple Circuits Test 60

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Semiconductor Electronics: Materials, Devices and Simple Circuits Test 60

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Weekly Quiz Competition

Question 1
1 / -0

Which gates is represented by this figure

A
$$NAND$$ gate

B
$$AND$$ gate

C
$$NOT$$ gate

D
$$OR$$ gate

Solution

The given symbol is of $$NAND$$ gate.
Question 2
1 / -0

For non conductor, the energy gap is

A
$$6\ eV$$

B
$$1.1\ eV$$

C
$$0.8\ eV$$

D
$$0.3\ eV$$

Solution

Since the non conductor do not conduct, so the gap energy must be high and $$6eV$$ is the highest value among all the options.
Question 3
1 / -0

At room temperature, a $$P-$$ type semiconductor has

A
Large number of holes and few electrons

B
Large number of free electrons and few holes

C
Equal number of free electrons and holes

D
No electrons or holes

Solution

In $$P-$$ type semi conductor, holes are majority charge carriers.
Question 4
1 / -0

The grid in a triode value is used

A
To increases the thermionic emission

B
To control the plate to cathode current

C
To reduce the inter-electrode capacity

D
To keep cathode at constant potential

Solution

The grid in a triode value is used to control the plate to cathode current.
Question 5
1 / -0

Doid is used as a/an

A
Oscillator

B
Amplifier

C
Rectifier

D
Modulator

Solution

A diode is used as a rectifier to convert $$ac$$ in to $$dc$$
Question 6
1 / -0

In a semiconductor

A
There are no free electrons at any temperature

B
The number of free electrons is more than that in a conductor

C
There are no free electrons at $$0\ K$$

D
None of these

Solution

At $$0\ K$$ semiconductor behaves as an insulator.
Question 7
1 / -0

The introduced of a grid in a triode value affects plate current by

A
Making the thermionic emission easier at law temperature

B
Releasing more electrons from the plate

C
By increasing plate voltage

D
By neutralising space charge

Solution

The introduced of a grid in a triode value affects plate current by neutralising space charge.
Question 8
1 / -0

The charge on a hole is equal to the charge of

A
Zero

B
Proton

C
Neutron

D
Electron

Solution

The charge on hole is positive. Hence, the charge on a hole is equal to the charge of proton.
Question 9
1 / -0

The logic gate obtained by two NAND gate is:

A
AND gate

B
OR gate

C
XOR gate

D
NOR gate

Solution

By De Morgan's theorem, a two-input NAND gate's logic may be expressed as AB=A+B, making a NAND gate equivalent to inverters followed by an OR gate. The NAND gate is significant because any boolean function can be implemented by using a combination of NAND gates.
Question 10
1 / -0

Series resistance is connected in the Zener diode circuit to

A
properly reverse bias the Zener

B
protect the Zener

C
properly forward bias the Zener

D
protect the load resistance

Solution

The series resistance protects the zener diode from damage due to high current flow.

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Semiconductor Electronics: Materials, Devices and Simple Circuits Test 60

Result

Semiconductor Electronics: Materials, Devices and Simple Circuits Test 60

Score

-

Rank

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SHARING IS CARING

Question 1

$$NAND$$ gate

$$AND$$ gate

$$NOT$$ gate

$$OR$$ gate

Solution

Question 2

$$6\ eV$$

$$1.1\ eV$$

$$0.8\ eV$$

$$0.3\ eV$$

Solution

Question 3

Large number of holes and few electrons

Large number of free electrons and few holes

Equal number of free electrons and holes

No electrons or holes

Solution

Question 4

To increases the thermionic emission

To control the plate to cathode current

To reduce the inter-electrode capacity

To keep cathode at constant potential

Solution

Question 5

Oscillator

Amplifier

Rectifier

Modulator

Solution

Question 6

There are no free electrons at any temperature

The number of free electrons is more than that in a conductor

There are no free electrons at $$0\ K$$

None of these

Solution

Question 7

Making the thermionic emission easier at law temperature

Releasing more electrons from the plate

By increasing plate voltage

By neutralising space charge

Solution

Question 8

Zero

Proton

Neutron

Electron

Solution

Question 9

AND gate

OR gate

XOR gate

NOR gate

Solution

Question 10

properly reverse bias the Zener

protect the Zener

properly forward bias the Zener

protect the load resistance

Solution

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