Electrostatic P...

The capacitance of a parallel plate capacitor with air as medium is $$6 \mu F$$. With the introduction of a dielectric medium, the capacitance becomes $$30\mu F$$. The permittivity of the medium is :
$$(\in_0= 8.85 \times 10^{-12} C^2N^{-1} m^{-2})$$ 

Two parallel metal plates having charges +Q and -Q face each other at a certain distance between them. If the plates are now dipped in kerosene oil tank, the electric field between the plates will :

An electric charge $${10}^{-3}\mu C$$ is placed at the origin $$(0,0)$$ of $$(x,y)$$ co-ordinate system. Two points $$A$$ and $$B$$ are situated at $$(\sqrt {2}, \sqrt {2})$$ and $$(2,0)$$ respectively. The potential difference between the points $$A$$ and $$B$$ will be:

A parallel plate capacitor with air as a dielectric has capacitance $$C$$. A slab of dielectric constant $$K$$, having same thickness as the separation between the plates is introduced so as to fill one-fourth of the capacitor as shown in the figure. The new capacitance will be:

A parallel plate capacitor of area $$'A'$$ plate separation $$'d'$$ is filled with two dielectrics as shown. What is the capacitance of the arrangement?

Space between the plates of a parallel plate capacitor is filled with a dielectric slab. The capacitor is charged and then the supply is disconnected to it. If the slab is now taken out , then:

A parallel plate condenser is charged by connecting it to a battery. The battery is disconnected and a glass slab is introduced between the plates. Then, 

In order to increase the capacity of a parallel plate condenser,  one should introduce a sheet of  $$\underline{\hspace{0.5in}}$$ between the plates (assume that the space is completely filled).

The capacity of a parallel plate air condenser is $$2\ \mu F$$. If a dielectric of dielectric constant $$4$$ is introduced between the plates, its new capacity is:

In an electrical circuit, which of the following quantities is analogous to temperature?