Electrostatic Potential and Capacitance Test

Result

Electrostatic Potential and Capacitance Test - 4

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Negative mutual potential energy corresponds to attraction between two charges

A
False

B
True

C
Can’t predict

D
None of the above

Solution

Yes, Negative mutual potential energy corresponds to attraction between two charges.
Question 2
1 / -0

Electric potential at a point located far away from the charge is taken to be

A
Infinite

B
Zero

C
Unity

D
May be zero or infinite

Solution

Electric potential at a point located far away from the charge is taken to be zero.
Question 3
1 / -0

Choose the non-polar molecule

A
CO₂

B
HCN

C
HCl

D
H₂O

Solution

O = C = O is a non polar molecule these bonds are arranged symmetrically so that the two dipoles cancel out resulting in no net dipole for the molecule.
Question 4
1 / -0

Let Q denote the charge, V denote potential difference and U denote stored energy. Of these quantities, capacitors in parallel must have the same:

A
Q only

B
V only

C
U only

D
Q and V only

Solution

Because capacitors in parallel have the same potential difference across them.
Question 5
1 / -0

Direction of electric field just outside the surface of a charged conductor is

A
Parallel to the surface

B
Normal to the surface

C
Tangential to the surface

D
At an angle of 45º to the surface.

Solution

If the electric field is not normal to the surface, then it will have a component along the surface which will immediately cause the flow of charges and produce surface current. But no current can exist under static conditions. Hence electric field is normal to the surface of the conductor at every point.
Question 6
1 / -0

A hollow metal sphere of radius 10 cm is charged such that the potential on its surface is 80 volt. The potential at the centre of the sphere is

A
zero

B
80 volt

C
800 volt

D
8 volt

Solution

Potential inside the charged sphere is constant and equal to potential on the surface of the conductor.
Question 7
1 / -0

A parallel plate capacitor is charged from a battery and then isolated from it. What will happen if the separation between the plates of a capacitor is increased?

A
The potential difference between the plates will not change

B
The potential difference between the plates will decrease

C
The field in the region in between the plates will not change

D
The capacitance of the plates will increase.

Solution

As separation between the plates d is increased, capacitance will decrease

That is C= e_oA/d.

Since charge Q=CV, is kept fixed, a decrease in C will imply increase in V.

The electric field between the two plates of the capacitor is s/e_o, since the charge is not changing, s will not change. Hence field remains constant between the plates.
Question 8
1 / -0

Coulomb’s law is given by F = kq₁q₂rⁿ, where n is

A
-1 / 2

B
1 / 2

C
2

D
- 2

Solution

Coulomb’s law is an inverse square law.

hence, n = -2

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Electrostatic Potential and Capacitance Test - 4

Result

Electrostatic Potential and Capacitance Test - 4

Score

-

Rank

-

SHARING IS CARING

Question 1

False

True

Can’t predict

None of the above

Solution

Question 2

Infinite

Zero

Unity

May be zero or infinite

Solution

Question 3

CO2

HCN

HCl

H2O

Solution

Question 4

Q only

V only

U only

Q and V only

Solution

Question 5

Parallel to the surface

Normal to the surface

Tangential to the surface

At an angle of 45º to the surface.

Solution

Question 6

zero

80 volt

800 volt

8 volt

Solution

Question 7

The potential difference between the plates will not change

The potential difference between the plates will decrease

The field in the region in between the plates will not change

The capacitance of the plates will increase.

Solution

Question 8

-1 / 2

1 / 2

2

- 2

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.

CO₂

H₂O