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Electrostatic Potential and Capacitance Test - 81

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Electrostatic Potential and Capacitance Test - 81
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  • Question 1
    1 / -0
    The total capacitance between points A and B in the arranged shown below is

    Solution

  • Question 2
    1 / -0
    Four metallic plates each with surface area '$$A$$' and inter plate separation '$$d$$' are placed as shown. Alternative plates are connected to point $$A$$ and $$B$$. The equivalent capacitance of the system is

    Solution

  • Question 3
    1 / -0
    For section $$AB$$ of a circuit, $$C_1 = 1 \mu F,$$ $$C_2 = 2 \mu F,$$ $$E = 10 V,$$ and the potential difference $$V_A - V_B = -10 V$$. Charge on capacitor $$C_1$$ is

    Solution

  • Question 4
    1 / -0
    The equivalent capacitance between A and B is

    Solution

  • Question 5
    1 / -0

    Five plates (same plate area for each) are placed as shown
    in figure.Capacitance of each parallel plate capacitor is C. Then find $${C_{AB}}$$.

    Solution

  • Question 6
    1 / -0
    A combination arrangement of the capacitors is shown in the figure $$C_1 = 3\mu F, C_2 = 6\mu F$$ and $$C_3 = 2\mu F$$ then eqivalent capactance between 'a' and 'b' is:
     

    Solution

  • Question 7
    1 / -0
    In the circuit shown in figure, point C is connected to A to charge the capacitor $$4    \mu F$$ capacitor thereby changes by a factor:  

  • Question 8
    1 / -0
    The equivalent capacitance in the figure shown between indicated points is -

    Solution

  • Question 9
    1 / -0
    In a region of uniform field $$,$$ as an electron travels from $$A$$ to $$B,$$ it slows from $${u_A} = 6.1 \times {10^6}\,m/s$$ to $${u_B} = 4.5 \times {10^6}\,m/s.$$ What is its potential change $$\Delta V = {V_B} - {V_A}$$ in volts?
    Solution

  • Question 10
    1 / -0
    The charge on each capacitors shown in figure and the potential difference across them will be respectively.

    Solution

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