Electrostatic Potential and Capacitance Test

Result

Electrostatic Potential and Capacitance Test - 87

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Weekly Quiz Competition

Question 1
1 / -0

Charges $$ q_1, q_2\ and\ q_3 $$ are placed on capacitor of capacitance $$ C_1, C_2\ and\ C_3 $$ respectively arranged in series as shown, switch S is then closed.
$$ Given\ q_1 = 30 C, q_2 = 20 C, q_3 = 10 C; C_1 = 10 F; C_2 = 20F; C_1 = 30 F\ and\ 12 volts $$
The final chage on capacitor $$ C_1 is- $$

A
$$ q_1 = \frac {690}{11} \mu C $$

B
$$ q_1 = \frac {790}{11} \mu C $$

C
$$ q_1 = \frac {5000}{11} \mu C $$

D
$$ q_1 = \frac {550}{11} \mu C $$

Solution
Question 2
1 / -0

Six identical capacitors are connected as shown in figure. Capacitance of each capacitors is 5$$\mu$$F. The effective capacitance between point A and b is

A
7.5 $$\mu$$F

B
10 $$\mu$$F

C
5 $$\mu$$F

D
1.5 $$\mu$$F

Solution
Question 3
1 / -0

The effective resistance between the points $$A$$ and $$B$$ in figure is

A
$$2$$

B
$$3$$

C
$$6$$

D
$$9$$

Solution
Question 4
1 / -0

If a thin metal foil of same area is placed between the two plates of a parallel plates capacitors of capacitance C then new capacitance will be

A
C

B
2C

C
3C

D
4C

Solution
Question 5
1 / -0

Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be

A
$$\dfrac{C}{3}, \dfrac{V}{3}$$

B
$$3C, \dfrac{V}{3}$$

C
$$\dfrac{C}{3}, 3V$$

D
$$3C, 3V$$

Solution

Here C_eq=\dfrac{C}{3}$$
Question 6
1 / -0

The capacitance of parallel plate capacitor is 12$$\mu F$$ If the distance between the plates is double and are is halved, the new capacitance will be

A
$$8\mu F$$

B
$$6\mu F$$

C
$$4\mu F$$

D
$$3\mu F$$

Solution
Question 7
1 / -0

Find equivalent capacitance between A and B

A
$$3 C$$

B
$$5 C$$

C
$$4 C$$

D
$$2 C$$

Solution
Question 8
1 / -0

The equivalent capacitor between $$ A $$ and $$ B $$ in the given figure is

A
6$$ \mu \mathrm { F } $$

B
18$$ \mu \mathrm { F } $$

C
9$$ \mu \mathrm { F } $$

D
$$ \frac { 1 } { 9 } \mu \mathrm { F } $$

Solution
Question 9
1 / -0

In the given network of capacitors, the equivalent capacitance between pints A and B is

A
$$\frac{11}{5}C$$

B
2 C

C
$$\frac{9}{7}C$$

D
4 C
Question 10
1 / -0

Minimum number of capacitors of 2$$ \mu \mathrm{F} $$ each required to obtain a capacitance of 5$$ \mu F $$ will be

A
$$4$$

B
$$3$$

C
$$5$$

D
$$6$$

Solution