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Current Electricity Test - 67

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Current Electricity Test - 67
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Weekly Quiz Competition
  • Question 1
    1 / -0
    For comparing the electromotive force of two cells with a potentiometer, a standard cell is used to develop a potential gradient along the wire. Which of the following possibilities would make the experiment unsuccessful?
    Solution
    The emf of the cell standard cell must be greater than that of experiment cells, otherwise balance point is not obtained.
  • Question 2
    1 / -0

    A circular coil of area $$8{m^2}$$  and number of turns 20 is placed in a magnetic field of 2T with its plane perpendicular to it. It is rotated with an angular velocity of 20rev/s about its natural axis. The emf induced is

    Solution

  • Question 3
    1 / -0
    Three resistances $$R_1,R_2$$ & $$R_3$$ $$(R_1> R_2> R_3)$$ are connected in series. If current $$I_1,I_2$$ & $$I_3$$ respectively is flowing through them, the correct relation will be
    Solution
    In series, same amount of current will flow through all the resistances.
    Current $$I_1=I_2=I_3=I=\dfrac{V}{R_{eq}}=\dfrac{V}{R_1+R_2+R_3}$$

    Option A is correct.

  • Question 4
    1 / -0
    Eight resistances each of resistance $$5\Omega $$ are connected in the circuit as shown in figure. The equivalent resistance between $$A$$ and $$B$$ is

    Solution

  • Question 5
    1 / -0
    Two resistances of $$400\Omega$$ and $$800\Omega$$ are connected in series with a $$6$$ volt battery of negligible internal resistance. A voltmeter of resistance $$10,000\Omega$$ is used to measure the potential difference across $$400\Omega$$. The error in the measurement of the potential difference in volts approximately is :
    Solution

  • Question 6
    1 / -0
    If $${i_1} = 3\sin \omega t\,and\,{i_2} = 4\cos \omega t$$, then $$i_3$$ is

    Solution

  • Question 7
    1 / -0
    Two resistors $$R_1 \, (24 \pm 0.5) \Omega$$  and $$R_2 \, (8 \pm 0.3) \Omega$$ are joined in series. The equivalent resistance is 
    Solution

    R1  = 24 ± 0.5

    R2 = 8 ± 0.3

    In series R1 + R2  = 32 ± 0.8

  • Question 8
    1 / -0
    The post office box works on the principle of :
    Solution

  • Question 9
    1 / -0
    Equivalence Resistance?

    Solution

  • Question 10
    1 / -0
    The inductance of a coil is $$L = 10 H$$ and resistance $$R = 5 \Omega$$. If applied voltage of battery is $$10 V$$ and it switches off in $$1$$ millisecond, find induced electromotive force of inductor.
    Solution
    According to question.....................
    $$\begin{array}{l} \varphi =Li \\ or,\, \, \, e-\frac { { d\varphi  } }{ { dt } } =-\frac { d }{ { dt } } (Li) \\ or,\, \, \, e=-L\frac { { di } }{ { dt } }  \\ Induced\, current\, =\frac { V }{ R } =\frac { { 10 } }{ 5 } =2A \\ Circuit\, \, switches\, \, off\, in\, \, 1\, milli{ { second } } \\ or,\, \, \, dt=1\times { 10^{ -3 } }s \\ and,\, \, \, L=10H \\ \therefore \, \, \, \, Induced\, emp\, in\, \, inductor\, is\, \left| e \right| =10\times \frac { 2 }{ { 1\times { { 10 }^{ -3 } } } } =2\times { 10^{ 4 } }V \\ so\, the\, \, option\, \, is\, \, A.\,  \end{array}$$
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