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Current Electricity Test - 76

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Current Electricity Test - 76
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  • Question 1
    1 / -0
    The amperage of the fuse wire used in a circuit that works on $$230 \ V$$ is $$2.2 \ A$$. If so. the power of the device is
    Solution
    The amperage of the fuse wire used in a circuit that works on $$V = 230 \ V$$ is $$i = 2.2 \ A$$.
     
    Power, $$P = Vi = 230 \times 2.2 = 506 \ W$$

    Hence, the power of the device is between $$500 \ W$$ and $$510 \ W$$.

    The correct option is C.
  • Question 2
    1 / -0
    Answer the question:
    Two $$5.0\Omega$$ resistors are connected as shown in the diagram.
    What is the total resistance of the combination ?

    Solution
    As we can see that both resistance are connected in parallel.
    For parallel combination:
    $$R_{eq}=\dfrac{R_1R_2}{R_1+R_2}$$

    $$R_{eq}=\dfrac{5\times 5}{5+5}=2.5\Omega$$

    Hence option A is correct, equivalent resistance is less than 5 ohm
  • Question 3
    1 / -0
    If $$500\Omega$$ of resistance is made by adding five $$100\Omega$$ resistance of tolerance $$4\%$$, then the tolerance of the combination is .
    Solution
    Individual resisistors are having resistance:
    $$R=100\pm 4$$
    On combining 5 similar resistors we get:
    $$5R=500\pm 20$$
    So, tolerance of the combination is also $$4\%$$
  • Question 4
    1 / -0
    In the arrangement shown in figure when the switch $${S}_{2}$$is open, the galvanometer shows no deflection for  $${l}= {L/2}$$. When the switch $${S}_{2}$$ is closed, the galvanometer shows no deflection for $${l}={5L/12}$$ . The internal resistance $$(r)$$ of $$6V$$ cell, and the emf $${E}$$ of the other battery are respectively:

    Solution

  • Question 5
    1 / -0
    If the temperature is increase, what will be the effect on the resistance of a conductor?
    Solution

  • Question 6
    1 / -0
    Two non ideal batteries are connected in parallel. Consider the following statements:
    1. The equivalent emf is smaller than either of the two emfs.
    2. The equivalent internal resistance is smaller than either of the two internal resistances.
    Solution

  • Question 7
    1 / -0
    The potentiometer wire AB is 100 cm long. The value of R for which the galvanometer shown no deflection, when AC = 40cm shown in figure is

    Solution
    The condition of no deflection of galvanometer : $$\dfrac{10}{R}=\dfrac{AC}{BC}=\dfrac{40}{100-40}=\dfrac{2}{3} \Rightarrow R=15 \Omega$$
  • Question 8
    1 / -0
    The current in a metallic conductor is plotted against voltage at two
    different temperatures $$T_{1}$$ and $$T_{2}$$. Which is correct

    Solution

  • Question 9
    1 / -0
    The figure shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm. When a resistor of 9.5$$\Omega$$ is used in the external circuit of the cell, the balance point shifts to 64.8 cm length of the potentiometer. The internal resistance of the cell is

    Solution
    The expression of internal resistance of  a cell in potentiometer is given by
    $$r=R\left[\dfrac{l_1}{l_2}-1\right]$$

    or $$r=9.5\left[\dfrac{76.3}{64.8}-1\right]=1.69   \Omega$$
  • Question 10
    1 / -0
    In the network shown, each resistance is equal to R. The equivalent
    resistance between diagonally opposite corners is:

    Solution

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