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Electromagnetic Induction Test - 12

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Electromagnetic Induction Test - 12
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  • Question 1
    1 / -0

    In electromagnetic induction, the induced e.m.f. in a coil is independent of

    Solution

    Because induced e.m.f. is given by E = −Ndφ/dt

     

  • Question 2
    1 / -0

    Lenz's law is consequence of the law of conservation of

    Solution

    The energy of the field increases with the magnitude of the field. Lenz’s law infers that there is an opposite field created due to increase or decrease of magnetic flux around a conductor so as to hold the law of conservation of energy.

     

  • Question 3
    1 / -0

    A magnet is brought towards a coil (i) speedily (ii) slowly then the induced e.m.f./induced charge will be respectively

    Solution

    The magnitude of induced e.m.f. is directly proportional to the rate of change of magnetic flux. Induced charge doesn’t depend upon time.

     

  • Question 4
    1 / -0

    A magnet is dropped down an infinitely long vertical copper tube

    Solution

    If bar magnet is falling vertically through the hollow region of long vertical copper tube then the magnetic flux linked with the copper tube (due to 'non-uniform' magnetic field of magnet) changes and eddy currents are generated in the body of the tube by Lenz's law the eddy currents opposes the falling of the magnet which therefore experience a retarding force.

    The retarding force increases with increasing velocity of the magnet and finally equals the weight of the magnet. The magnet then attains a constant final terminal velocity i.e. magnet ultimately falls with zero acceleration in the tube.

     

  • Question 5
    1 / -0

    If a copper ring is moved quickly towards south pole of a powerful stationary bar magnet, then

    Solution

    Magnetic flux linked with the ring changes so current flows through it.

     

  • Question 6
    1 / -0

    A 10-metre wire kept in east-west falling with velocity 5 m/sec perpendicular to the field 0.3 x 10−4 Wb/m2. The induced e.m.f. across the terminal will be

    Solution

    Induced e.m.f. = Blv = 0.3 x 10−4 x 10 x 5

    = 1.5 x 10−3 V

    = 1.5 mV

     

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