Alternating Cur...

An ac voltage source $$V = V_0\sin(\omega t)$$ is connected across resistance $$R$$ and capacitance $$C$$ as shown in figure. It is given that $$R = \dfrac{1}{\omega C}$$. The peak current is $$I_0$$ . If the angular frequency of the voltage source is changed to $$\dfrac{\omega}{\sqrt{3}}$$ then the new peak current in the circuit is:

A coil has resistance $$30\ \text{ohm}$$ and inductive reactance $$20\ \text{Ohm at}\ 50\ \text{Hz}$$ frequency. If an ac source, of  $$200\ \text{volt},\ 100\ \text{Hz},$$ is connected across the coil, the current in the coil will be :

When $$100$$ volt $$DC$$ source is applied across a coil, a current of $$1A$$ flows through it. When $$100V$$ $$AC$$ source of $$50Hz$$ is applied to the same coil, only $$0.5A$$ current flows. Calculate the inductance of the coil.

A coil, a capacitor and an $$AC$$ source of rms voltage $$24V$$ are connected in series. By varying the frequency of the source, a maximum rms current of $$6A$$ is observed. If coil is connected to a dc battery of emf $$12$$ volt and internal resistance $$4\Omega$$, then current through it in steady state is :

A $$50Hz$$ $$AC$$ source of $$20V$$ is connected across $$R$$ and $$C$$ as shown in figure. The voltage across $$R$$ is $$12V$$. The voltage across $$C$$ is

The value of resistance of the coil calculated by the student is :

Consider an $$L-C-R$$ circuit as shown in figure, with an $$AC$$ source of peak value $$V_0$$ and angular frequency $$\omega$$. Then the peak value of current through the $$AC$$ source is :

When an alternating voltage of $$220V$$ is applied across a device $$P$$, a current of $$0.25A$$ flows through the circuit and it leads the applied voltage by an angle $$\pi/2$$ radian. When the same voltage source is connected across another device $$Q$$, the same current is observed in the circuit but in phase with the applied voltage. What is the current when the same source is connected across a series combination of $$P$$ and $$Q$$?

An $$LCR$$ circuit contains resistance of $$100\Omega$$ and a supply of $$200\space V$$ at $$300\space rad/s$$ angular frequency. If only capacitance is taken out from the circuit and the rest of the circuit is joined, current lags behind the voltage by $$60^{\small\circ}$$. If on the other hand, only inductor is taken out, the current leads by $$60^{\small\circ{}}$$ with the applied voltage. The current flowing in the circuit is