Alternating Current Test

Directions For Questions

It is known to all of you that the impedance of a circuit is dependent on the frequency of source. In order to study the effect of frequency on the impedance, a student in a lab took

2

impedance boxes

P

and

Q

and connected them in series with an

AC

source of variable frequency. The emf of the source is constant at

10V

. Box

P

contains a capacitance of

1\mu F

in series with a resistance of

32\Omega

. And the box

Q

has a coil of self inductance

4.9 mH

and a resistance of

68\Omega

in series. He adjusted the frequency so that the maximum current flows in

P

and

Q

. Based on his experimental set up and the reading by him at various moment answer the following questions.

...view full instructions

Directions For Questions

It is known to all of you that the impedance of a circuit is dependent on the frequency of source. In order to study the effect of frequency on the impedance, a student in a lab took

2

impedance boxes

P

and

Q

and connected them in series with an

AC

source of variable frequency. The emf of the source is constant at

10V

. Box

P

contains a capacitance of

1\mu F

in series with a resistance of

32\Omega

. And the box

Q

has a coil of self inductance

4.9 mH

and a resistance of

68\Omega

in series. He adjusted the frequency so that the maximum current flows in

P

and

Q

. Based on his experimental set up and the reading by him at various moment answer the following questions.

...view full instructions

Directions For Questions

A box

P

and a coil

Q

are connected in series with an ac source of variable frequency. The emf of the source is constant at

10\space V

. Box

P

contains a capacitance of

1\space \mu F

in series with a resistance of

32\space \Omega

. Coil

Q

has a self inductance of

4.9\space mH

and a resistance of

68\space \Omega

in series. The frequency is adjusted so that maximum current flows in

P

and

Q

...view full instructions

Directions For Questions

A current of

4\space A

flows in a coil when connected to a

12\space V

dc source. If the same coil is connected to a

12\space V

50\space rad\space s^{-1}

ac source, a current of

2.4\space A

flows in the circuit.

...view full instructions

Directions For Questions

A box

P

and a coil

Q

are connected in series with an ac source of variable frequency. The emf of the source is constant at

10\space V

. Box

P

contains a capacitance of

1\space \mu F

in series with a resistance of

32\space \Omega

. Coil

Q

has a self inductance of

4.9\space mH

and a resistance of

68\space \Omega

in series. The frequency is adjusted so that maximum current flows in

P

and

Q

...view full instructions

User

Question Analysis

Answered - 0
Unanswered - 10

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Alternating Cur...

Question 1

5(π2−5)π Ω\displaystyle\frac{5(\pi^2 - 5)}{\pi}\space \Omegaπ5(π2−5)​ Ω

10(10−π2)π Ω\displaystyle\frac{10(10 - \pi^2)}{\pi}\space \Omegaπ10(10−π2)​ Ω

10(π2−5)π Ω\displaystyle\frac{10(\pi^2 - 5)}{\pi}\space \Omegaπ10(π2−5)​ Ω

5(10−π2)π Ω\displaystyle\frac{5(10 - \pi^2)}{\pi}\space \Omegaπ5(10−π2)​ Ω

Question 2

10−4 H10^{-4}\space H10−4 H

10−6 H10^{-6}\space H10−6 H

10−8 H10^{-8}\space H10−8 H

10−10 H10^{-10}\space H10−10 H

Question 3

70Ω70\Omega70Ω

77Ω77\Omega77Ω

90Ω90\Omega90Ω

100Ω100\Omega100Ω

Question 4

105/7rad/s10^5/7 rad/s105/7rad/s

104rad/s10^4 rad/s104rad/s

105rad/s10^5 rad/s105rad/s

104/7rad/s10^4/7 rad/s104/7rad/s

Question 5

100 Ω100\space \Omega100 Ω

25 Ω25\space \Omega25 Ω

125×75 Ω\sqrt{125\times75}\space \Omega125×75​ Ω

400 Ω400\space \Omega400 Ω

Question 6

8 V8\ V8 V

16 V16\ V16 V

10 V10\ V10 V

not possible to determine unless values of R and C are given

Question 7

0.1 mH0.1\space mH0.1 mH

0.2 mH0.2\space mH0.2 mH

0.35 mH0.35\space mH0.35 mH

0.4 mH0.4\space mH0.4 mH

Question 8

77 Ω77\space \Omega77 Ω

36 Ω36\space \Omega36 Ω

40 Ω40\space \Omega40 Ω

125 Ω125\space \Omega125 Ω

Question 9

0.02 H0.02\space H0.02 H

0.04 H0.04\space H0.04 H

0.08 H0.08\space H0.08 H

1.0 H1.0\space H1.0 H

Question 10

200 Ω200\space \Omega200 Ω

1350 Ω\sqrt{1350}\space \Omega1350​ Ω

55 Ω55\space \Omega55 Ω

9524 Ω\sqrt{9524}\space \Omega9524​ Ω

User

Question Analysis

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$\displaystyle\frac{5(\pi^2 - 5)}{\pi}\space \Omega$

$\displaystyle\frac{10(10 - \pi^2)}{\pi}\space \Omega$

$\displaystyle\frac{10(\pi^2 - 5)}{\pi}\space \Omega$

$\displaystyle\frac{5(10 - \pi^2)}{\pi}\space \Omega$

$10^{-4}\space H$

$10^{-6}\space H$

$10^{-8}\space H$

$10^{-10}\space H$

$70\Omega$

$77\Omega$

$90\Omega$

$100\Omega$

$10^5/7 rad/s$

$10^4 rad/s$

$10^5 rad/s$

$10^4/7 rad/s$

$100\space \Omega$

$25\space \Omega$

$\sqrt{125\times75}\space \Omega$

$400\space \Omega$

$8\ V$

$16\ V$

$10\ V$

$0.1\space mH$

$0.2\space mH$

$0.35\space mH$

$0.4\space mH$

$77\space \Omega$

$36\space \Omega$

$40\space \Omega$

$125\space \Omega$

$0.02\space H$

$0.04\space H$

$0.08\space H$

$1.0\space H$

$200\space \Omega$

$\sqrt{1350}\space \Omega$

$55\space \Omega$

$\sqrt{9524}\space \Omega$