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Electromagnetic Waves Test - 19

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Electromagnetic Waves Test - 19
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  • Question 1
    1 / -0
    In the propagation of electromagnetic waves the angle between the direction of propagation and the plane of vibration is ________
    Solution
    Axis of propagation always lie perpendicular to the plane of vibrations, therefor angle between them is $$\dfrac{\pi}{2}$$ . 
    Hence answer is B

  • Question 2
    1 / -0
    When light propagates in vaccum there is an electric field and a magnetic field. Which of the following is not true about these field?
    Solution
    $$Answer:-$$ A
    They vary with time following a wave function (sinuosoidal) and average value of these function is zero and also we can see in figure they are mutually perpendicular and also perpendicular to direction of propagation.

  • Question 3
    1 / -0
    The value of electric field in an electromagnetic wave originating from a point source of light at a distance of  10 meter is E= 500 volt/m. The electric field at a distance of 5 meter will be
    Solution
    As we know, $$ E \propto R^{-2} $$
    Therefore ,  $$ E( R= 5) = \dfrac{500}{10^{-2}} 5^{-2} = 2000 V/m $$
  • Question 4
    1 / -0
    Maxwell's modified form of Ampere's circuital law is
    Solution
    $$Answer:-$$ D
    Treating all charges on the same footing (disregarding whether they are bound or free charges), the generalized Ampère's equation, also called the Maxwell–Ampère equation, is in integral form.

  • Question 5
    1 / -0
    Assume you are sitting in sun for 2.5 hours. The area of your body exposed normally to sun rays $$ { 1.3m }^{ 2 }$$. The intensity of sun rays is 1.1 Kilowatt/$${ m }^{ 2 }$$. If your body completely absorbs the sun rays then the momentum transferred to your body will be (in Kg-m/s):
    Solution
    $$Power=intensity\times area$$
    Intensity and area are given ,
    $$Power=1.3\times 1.1KW$$
    $$Energy = power\times time$$
    Time is 2.5hr
    $$Energy= 1300\times 1.1\times 2.5\times 3600J$$
               $$=12870000J$$  
    $$Momentum=\dfrac{energy}{c}$$
                     $$=\dfrac{12870000}{3\times 10^{8}}$$
                     $$=0.043$$
  • Question 6
    1 / -0
    The displacement current is 
    Solution

  • Question 7
    1 / -0
    In the propagation of light waves, the angle between the plane of vibration &  plane of polarisation is:
    Solution
    The plane of polarisations is that plane in which there is no vibration. While a plane including the direction of light propagation and the direction of electric field is called the plane of vibration. The angle between them is $$ { 90 }^{ o }$$.
  • Question 8
    1 / -0
    In the propagation of electromagnetic waves,  the angle between the direction of propagation and plane of polarisation is
    Solution
    Plane of polarization is a confinement of the electric/magnetic field vector to a given plane along the direction of propagation. Therefore angle between them is $$ { 0 }^{ o }$$
  • Question 9
    1 / -0
    If $$\vec{E}$$ and $$\vec{B}$$ are the electric and magnetic field vectors of electromagnetic waves then the direction of propagation of electromagnetic wave is along the direction of:
    Solution
    The direction of propagation of electromagnetic wave is perpendicular to the variation of electric field $$\vec{E}$$ as well as to the magnetic field $$\vec{B}$$
  • Question 10
    1 / -0
    Which of the following has/have zero average value in a plane electromagnetic wave?
    Solution

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