Be My Multiple, I'll be Your Factor Test 9

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Be My Multiple, I'll be Your Factor Test 9

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Weekly Quiz Competition

Question 1
1 / -0

Determine the number nearest to 100000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21?

A
100200

B
100800

C
240800

D
260040

Solution

Reminder= 40 84040=800 100000+800=100800
Question 2
1 / -0

182/195 when reduced to the lowest term is

A
13/15

B
14/15

C
13/14

D
12/13

Solution
Question 3
1 / -0

Which of the following pair is co-prime?

A
81, 135

B
87, 116

C
43, 73

D
26, 65

Solution

HCF of 81 and 135 = 27 HCF of 87 and 116 = 29 HCF of 43 and 73 = 1 HCF of 26 and 65 = 13 Hence, 43 and 73 are co-prime
Question 4
1 / -0

Find the number of factors of 1024

A
11

B
12

C
13

D
14

Solution

1024=2¹⁰=2ⁿ
⇒ (n+1) = (10+1) = 11.
Where (n+1) = no. of factors. Here factors will be 1, 2, 4, 8, 16?????.1024.
Question 5
1 / -0

If the 8-digit number 136y5785 is divisible by 15, then find the least possible value of

A
1

B
2

C
0

D
None of these

Solution

136Y5785

For 15, No. should be divisible by 5, 3
No. is already divisible by 5 1 + 3 + 6 + 5 + 7 + 8 + 5 + y = 35 + y

∴ y = 1
Question 6
1 / -0

Find the smallest number which when divided by 25, 40 and 60 leaves remainder 7 in each case?

A
607

B
608

C
609

D
610

Solution

5×4×5×2×3=600
Required numbers is 600+7=607
Question 7
1 / -0

Directions For Questions

x, y, z, w are four odd natural numbers. Let u=x²+y²+z²+w². Consider following statements

I. U is always divisible by 4
II. U is never divisible by 8

...view full instructions

Which of the above statements) is /are true?

A
Only I

B
Only II

C
Both I and II

D
Neither I nor II
Question 8
1 / -0

2211/5025 , which reduced to its simplest form. By dividing the numerator and denominator

A
11/25

B
23/27

C
47/49

D
37/43

Solution
Question 9
1 / -0

A boy saves Rs. 4.65 daily. Find the least number of days in which he will be to save an exact number (whole number) of rupees.

A
24

B
20

C
30

D
40

Solution

Rs. 4.65 = 465 paise
The exact number of rupees will be a multiple of 100
So, we have to fine the L.C.M. of 465 and 100
100 = 2*2*5*5
465 = 3*5*31
L.C.M. of 465 and 100 = 2*2*3*5*5*31
= 9300
So, the boy saves 9300 paise
Hence, least number of days required to save 9300 paise = 9300/465
= 20 days
Question 10
1 / -0

H.C.F of two numbers is 16, then their LCM is

A
162

B
167

C
192

D
197

Solution

H.C.F is always a factor of L.C.M. In this case 16 Divides 192 only.

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Re-Attempt Weekly Quiz Competition

Be My Multiple, I'll be Your Factor Test 9

Result

Be My Multiple, I'll be Your Factor Test 9

Score

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Rank

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SHARING IS CARING

Question 1

100200

100800

240800

260040

Solution

Question 2

13/15

14/15

13/14

12/13

Solution

Question 3

81, 135

87, 116

43, 73

26, 65

Solution

Question 4

11

12

13

14

Solution

Question 5

1

2

0

None of these

Solution

Question 6

607

608

609

610

Solution

Question 7

Only I

Only II

Both I and II

Neither I nor II

Question 8

11/25

23/27

47/49

37/43

Solution

Question 9

24

20

30

40

Solution

Question 10

162

167

192

197

Solution

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Question Analysis

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