Mensuration Test

Result

Mensuration Test - 12

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Weekly Quiz Competition

Question 1
1 / -0

Find the perimeter of a square.

A
13.2 in

B
23.2 in

C
33.2 in

D
43.2 in

Solution

The perimeter of a square $$= 4a$$

Where, $$a = side$$

Perimeter $$= 4 \times 5.8$$

$$= 23.2$$ in
Question 2
1 / -0

Jen wants to tile the floor of her kitchen. The floor is rectangular and measures $$12$$ feet by $$8$$ feet. If it costs $$\text{Rs. }2.50$$ per square foot for the materials, what is the total cost of the materials for tiling the kitchen floor?

A
$$\text{Rs. }160$$

B
$$\text{Rs. }200$$

C
$$\text{Rs. }220$$

D
$$\text{Rs. }240$$

Solution

The given floor is rectangular with length$$(l)=12$$ feet and breadth $$(b)=8$$ feet

Area of the rectangular floor$$=l\times b$$

$$=12\times 8$$

$$=96$$ sq. feet

Given $$\text{Rs. } 2.50$$ is the cost of the materials per square foot.

$$\therefore$$ Cost of materials for $$96$$ sq. feet

$$=96\times 2.50$$

$$=\text{Rs. }240.0$$
Question 3
1 / -0

An athlete takes 15 rounds & a rectangular park, 30 m long and 20 m wide. The total distance covered by him is ________.

A
$$1500$$ m

B
$$1300$$ m

C
$$1200$$ m

D
$$1550$$ m

Solution

Length of rectangular park = 30 m
Breadth of rectangular park = 20 m
$$\therefore$$ Perimeter of park = 2(30 20) = 100 m
So, distance covered by the athlete in 15 rounds = $$15 \times 100 = 1500 m$$
Question 4
1 / -0

Calculate area of the figure made by joining $$25$$ unit squares.

A
$$22$$ sq. unit

B
$$23$$ sq. unit

C
$$24$$ sq. unit

D
$$25$$ sq. unit

Solution

Area of figure$$=25\times 1=25$$ sq. unit
Question 5
1 / -0

Parul walks twice around a square field of side $$25$$ m. Nitish walks thrice around a rectangular field with length $$20$$ m and breadth $$14$$ m. Who covers more distance and by how much?

A
Nitish, $$4$$ m

B
Parul, $$6$$ m

C
Nitish, $$204$$ m

D
Parul, $$8$$ m

Solution

We know that, distance covered by Parul is twice the perimeter of Square
and Distance covered by Nitish is thrice the perimeter of rectangle.
Perimeter of Square $$=4\times \text{Side}$$
$$= 4\times 25 =100 \text{ m}$$
Perimeter of Rectangle $$=2(\text{Length}+ \text{Breadth}) $$
$$= 2(20+14)= 68 \text{ m}$$
Therefore, distance covered by Parul $$=2\times 100= 200 \text{ m}$$
And Distance covered by Nitish $$=3\times 68 = 204 \text{ m}$$
Hence, Nitish Travels more distance by $$4 \text{ m}$$
Question 6
1 / -0

Each square in the figure covers an area of $$2$$ in$$^{2}$$. What is the area of the region enclosed in the figure shown?

A
$$42\ in^{2}$$

B
$$48\ in^{2}$$

C
$$56\ in^{2}$$

D
$$64\ in^{2}$$

Solution

Number of squares enclosed$$=21$$
Area of figure $$21\times 2=42$$ square units.
Question 7
1 / -0

Calculate the perimeter of the following figures:

A
(1) $$18a$$
(2) $$11b$$

B
(1) $$10a$$
(2) $$44b$$

C
(1) $$20a$$
(2) $$22b$$

D
none

Solution
Question 8
1 / -0

Latika wants to put a border around her bedsheet of length 10 m and breadth 5 m 60 cm. Find the total cost of the border required at the rate of Rs 90 per metre.

A
$$Rs\ 2808$$

B
$$Rs\ 2505$$

C
$$Rs\ 2408$$

D
$$Rs\ 2605$$

Solution

Length of bedsheet $$= 10 m$$
Breadth of bedsheet $$= 5 m\ 60 cm = 5.6 m$$ (as $$1m=100cm$$)
Perimeter of bedsheet $$= 2(10 + 5.6)$$
$$=2 \times (15.6) = 31.2 m$$
Cost of $$1 m$$ border $$= Rs 90$$
$$\therefore$$Total cost $$=$$ Rs $$(90 \times 31.2) = Rs\ 2808$$
Question 9
1 / -0

Calculate the approximate area enclosed in the figure if the area of each square is $$6\text{ sq. units}.$$

A
$$180\text{ sq. units}$$

B
$$252\text{ sq. units}$$

C
$$270\text{ sq. units}$$

D
$$288\text{ sq. units}$$

Solution

The number of squares enclosed in the given figure is equal to $$45.$$ It is given that area of each square is equal to $$6\text{ sq. units}.$$

Area of figure,
$$A=45\times 6$$
$$=270\text{ sq. units}$$
Question 10
1 / -0

Estimate the area of the shaded region. Each unit is $$1$$ square inch.

A
$$14$$ sq. in

B
$$22$$ sq. in

C
$$30$$ sq. in

D
$$38$$ sq. in

Solution

Number of full squares $$=18$$
Number of half squares $$=8$$
Area of figure $$=18\times 1+8\times \cfrac { 1 }{ 2 } =22 \text{ sq. in}$$