Mensuration Test

Result

Mensuration Test - 9

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

If the length and breadth of a rectangle are doubled then its perimeter is

A
tripled

B
doubled

C
made half

D
none

Solution

We know.
Perimter of a rectangle =$$ 2(l+b) $$
Since, length and breadth are doubled.
Perimeter = $$ 2( 2l+2b) = 4(l+b) $$
Hence, Perimeter is doubled.
Question 2
1 / -0

The length of the wooden strip required to frame a photograph of length and breadth 39.5 cm and 31 cm respectively, is

A
$$79\ cm$$

B
$$1224.5\ cm$$

C
$$141\ cm$$

D
$$70.5\ cm$$

Solution

Length of photograph = 39.5 cm
Breadth of photograph = 31 cm
$$\therefore$$ Required length of the wooden strip
= Perimeter of photograph
= 2(39.5 + 31) = 2(70.5) = 141 cm
Question 3
1 / -0

If length of a rectangle is 5 less than 3 times it's breath and perimeter of the rectangle is 22m, then area of the rectangle is:

A
28$$m^{2}$$

B
14$$m^{2}$$

C
11$$m^{2}$$

D
21$$m^{2}$$

Solution

Let $$l$$ and $$b$$ be the length and breadth of rectangle.
According to the question-
$$l = 3b - 5 ..... \left( 1 \right)$$
Perimeter of rectangle $$= 22 \; m \; \left( \text{Given} \right)$$
As we know that the perimeter of rectangle is given as-
$$P = 2 \left( l + b \right)$$
Therefore,
$$2 \left( l + b \right) = 22$$
$$l + b = 11$$
$$\left( 3b - 5 \right) + b = 11 \; \left( \text{from } \left( 1 \right) \right)$$
$$4b = 11 + 5$$
$$\Rightarrow b = \cfrac{16}{4} = 4 \; m$$
Substituting the value of $$b$$ in $${eq}^{n} \left( 1 \right)$$, we have
$$l = 3 \times 4 - 5 = 7 \; m$$
Therefore,
Area of rectangle $$= l \times b = 7 \times 4 = 28 \; {m}^{2}$$
Hence the area of rectangle is $$28 \; {m}^{2}$$.
Question 4
1 / -0

What is the perimeter of a square with side $$6 cm$$?

A
$$36\ cm^{2}$$

B
$$216\ cm^{3}$$

C
$$24\ cm$$

D
$$12\ cm$$

Solution

Perimeter of a square is $$4*side$$
Given $$side=6cm$$
Perimeter of given square $$=4\times 6=24cm$$
Question 5
1 / -0

A tabletop measures 315 cm by 90 cm. The perimeter of the top of the table is:

A
4 m 5 cm

B
8 m 10 cm

C
24 m 30 cm

D
None of these

Solution

Length of top of the table = 315 cm
Breadth of top of the table = 90 cm
Perimeter = 2(315 + 90) = 2(405) = 810 cm
= 8 m 10 cm
Question 6
1 / -0

The area of a square field is $$\displaystyle 80\frac{244}{729}$$sq. m. The length of each side of the filed, is ___________.

A
$$8.96$$m

B
$$10.26$$m

C
$$13.54$$m

D
$$12.26$$m

Solution

area of any square with side $$a$$ m is $$=a^2$$ sq.m.

let the length of the side of the square field is $$x$$m

$$x^2=\dfrac{729*80+244}{729}$$

$$x^2=\dfrac{58564}{729}$$

$$x=\dfrac{242}{27}$$

$$x=8.96$$
length of the side is $$8.96$$ m
Question 7
1 / -0

The cost of enclosing a rectangular garden with a fence all around, at the rate of $$75$$ paise per metre, is $$Rs. 300$$. If the length of the garden is $$120$$ metres, find the area of the field in square metres.

A
$$9600sq.m$$

B
$$8400sq.m$$

C
$$7500sq.m$$

D
None of these

Solution

The cost of enclosing a rectangular garden with a fence all around, at the rate of $$75$$ paise (= $$0.75$$ rupee) per meter, is Rs.$$ 300$$.

Thus, the perimeter of the rectangular garden $$=\cfrac{300}{0.75}$$$$=400$$ m

Perimeter of a rectangle $$=2(length + breadth)$$

$$\therefore 2(length + breadth)=400$$

$$\Rightarrow 2(120+breadth)=400$$

$$\Rightarrow 120 + breadth = 200$$

$$\Rightarrow breadth = 80 $$ m

Thus, the area of the rectangle $$=\ell \times b =80 \times 120$$

$$=9600$$ sq. m
Question 8
1 / -0

The rate for a $$1.2$$ m wide carpet is Rs. $$40$$ per metre; find the cost of covering a hall $$45$$ m long and $$32$$ m wide with this carpet. Also, find the cost of carpeting the same hall if the carpet, $$80$$ cm wide, is at Rs. $$25$$ per metre.

A
Rs. $$48,000$$; Rs. $$45,000$$

B
Rs. $$52,000$$; Rs. $$75,000$$

C
Rs. $$66,000$$; Rs. $$35,000$$

D
Rs. $$17,000$$; Rs. $$85,000$$

Solution

Given, length of hall is $$45$$ m and width is $$32$$ m
Then area of hall $$=$$ $$45\times 32=1440 m^{2}$$
Length of carpet $$=$$ $$\dfrac{1440}{1.2}$$ .....(given width of carpet is $$1.2$$ m)
Then cost of carpet $$=$$ $$\dfrac{1440}{1.2}\times40=$$ Rs. $$48000$$
When cost of $$80$$ cm width at rate Rs. $$25$$ per meter
Then cost carpet $$=$$ $$\dfrac{1440}{0.80}\times 25=$$ Rs. $$45000$$
Question 9
1 / -0

The length and breadth of a rectangular plot are $$900 m$$ and $$700 m$$ respectively. If three rounds of fence is fixed around the field at the cost of $$Rs$$. $$8$$ per meter, the total amount spent is ?

A
$$Rs. 768$$

B
$$Rs. 7680$$

C
$$Rs. 76800$$

D
$$Rs. 768000$$

Solution

$$l = 900, b = 700$$
Perimeter = $$2 (900 + 700)$$
$$=(1600)$$
$$=3200$$
$$3$$ rounds of fence :
$$=3 (3200)$$
$$=9600 m%$$
$$9600 \times 8$$
$$=Rs. 76800$$
Question 10
1 / -0

A rectangular field is to be fenced on three sides leaving a side of $$20\ m$$ uncovered. If the area of the field is $$680\ m^2$$, how many metres of fencing will be required.

A
$$34$$

B
$$40$$

C
$$68$$

D
$$88$$

Solution

If length of one side is $$ 20\ m $$ and area is $$680\ m^2$$
$$\Rightarrow$$ Length of other side $$ = \dfrac {680}{20} = 34\ m $$
Now, length of fencing required for the three sides $$ = 34 + 34 + 20 = 88\ m $$

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Mensuration Test - 9

Result

Mensuration Test - 9

Score

-

Rank

-

SHARING IS CARING

Question 1

tripled

doubled

made half

none

Solution

Question 2

$$79\ cm$$

$$1224.5\ cm$$

$$141\ cm$$

$$70.5\ cm$$

Solution

Question 3

28$$m^{2}$$

14$$m^{2}$$

11$$m^{2}$$

21$$m^{2}$$

Solution

Question 4

$$36\ cm^{2}$$

$$216\ cm^{3}$$

$$24\ cm$$

$$12\ cm$$

Solution

Question 5

4 m 5 cm

8 m 10 cm

24 m 30 cm

None of these

Solution

Question 6

$$8.96$$m

$$10.26$$m

$$13.54$$m

$$12.26$$m

Solution

Question 7

$$9600sq.m$$

$$8400sq.m$$

$$7500sq.m$$

None of these

Solution

Question 8

Rs. $$48,000$$; Rs. $$45,000$$

Rs. $$52,000$$; Rs. $$75,000$$

Rs. $$66,000$$; Rs. $$35,000$$

Rs. $$17,000$$; Rs. $$85,000$$

Solution

Question 9

$$Rs. 768$$

$$Rs. 7680$$

$$Rs. 76800$$

$$Rs. 768000$$

Solution

Question 10

$$34$$

$$40$$

$$68$$

$$88$$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.