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Practical Geometry Test - 4

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Practical Geometry Test - 4
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  • Question 1
    1 / -0

    Directions For Questions

    The steps for construction of an $$\angle ABC$$ of measure $$60^\circ$$ is given below in jumbled order:
    1. Join $$B-E$$ and extend it as a ray $$BA$$.
    2. Draw a ray $$BC$$.
    3. With the same radius and the pointed end of the compass at $$D$$, mark a point $$E$$ on the same arc.
    4. With the pointed end of the compass at $$B$$ and any arbitrary radius, draw an arc and mark the intersection point with ray $$BC$$ as $$D$$.

    ...view full instructions

    The first step in the process is:
    Solution

    Correct sequence is :

    Step 1. Draw a ray $$BC$$.

    Step 2. With the pointed end of the compass at B and any arbitrary radius, draw an arc and mark the intersection point with ray $$BC$$ as $$D.$$

    Step 3. With the same radius and the pointed end of the compass at $$D$$, mark a point $$E$$ on the same arc.

    Step 4 Join $$B−E$$ and extend it as a ray $$BA.$$

    So the first step is $$2$$

    Option $$B$$ is correct.

  • Question 2
    1 / -0
    Which of the following lines from point $$P$$ is a perpendicular to line $$AB$$?

    Solution
    Line $$PR$$ makes a right angle with line $$AB$$
    $$\therefore PR$$ is perpendicular to $$AB$$
    Option $$B$$ is correct.
  • Question 3
    1 / -0
    Each angle of equilateral triangle is $$ 60^\circ$$. The angles are bisected then each angle will be of:
    Solution
    Angle bisector divide the angle in two equal parts.
    $$\therefore $$ bisected angle $$=\dfrac{60^{\circ}}{2}=30^{\circ}$$
    So option $$B$$ is correct.
  • Question 4
    1 / -0
    A square is given and an angle of $$30^{o}$$ is drawn from one of its vertex . The figure will look like what?

    Solution
    Place a protractor and draw an angle of $$30^{\circ}$$ on one of its vertex.
    If angle is drawn on the topmost right vertex then the figure looks like figure in option $$D$$
    So option $$D$$ is correct.
  • Question 5
    1 / -0

    Directions For Questions

    The steps for constructing an $$\angle ABC$$ of measure $$120^\circ$$ are given below in jumbled order:
    1. From the point $$E$$, mark a point $$F$$ on the same arc with the same radius.
    2. Place the pointed end of the compass on $$B$$ and draw a semi-circular arc with arbitrary radius and name its intersection with ray $$BC$$ as $$D$$.
    3. Draw a ray $$BC$$.
    4. From point $$D$$, mark a point $$E$$ on the arc with the same radius.
    5. Join $$B-F$$ and extend it to obtain ray $$BA$$

    ...view full instructions

    The fourth step in the process is:
    Solution
    Correct sequence is :
    Step 1. Draw a ray $$BC$$.
    Step 2.Place the pointed end of the compass on $$B$$ and draw a semi-circular arc with arbitrary radius and name its intersection with the ray $$BC$$ as $$D$$.
    Step 3. From $$D$$ mark a point $$E$$ on the arc with the same radius.
    Step 4. From point $$E$$, mark a point $$F$$ on the same arc with same radius.
    Step 5. Join $$B-F$$ and extend it to obtain ray $$BA$$
    So the fourth step is $$1$$
    Option $$A$$ is correct.
  • Question 6
    1 / -0
    The steps of construction of an $$\angle AOB=45^{o}$$ is given in jumbled order below:
    1. Place compass on intersection point.
    2. Place ruler on start point and where arc intersects perpendicular line.
    3. Adjust compass width to reach start point. 
    4. Construct a perpendicular line.
    5. Draw $$45$$ degree line.
    6. Draw an arc that intersects perpendicular line. 
    Which step comes first?
    Solution
    Correct sequence is :
    1. Construct a perpendicular line .
    2. Draw an arc that intersect the perpendicular line.
    3. Adjust the compass width to reach the start point .
    4.Place compass on intersection point.
    5. Place ruler on start point and where the arc intersects the perpendicular line.
    6. Draw $$45$$ degree line.
    So the first step is $$4$$
    Option $$C$$ is correct.
  • Question 7
    1 / -0
    An architect needs a staircase attached to a wall.The angle between stair and ground needs to be 30.
    His plan will look like:
    Solution
    Only option $$(B)$$ shape have an angle equivalent to $$30^o$$.
    So architect plan will look like shape $$(B)$$.

  • Question 8
    1 / -0
    The steps for constructing an $$\angle ABC$$ of measure $$120^\circ$$ are given below in jumbled order:
    1. From the point $$R$$, mark a point $$P$$ on the same arc with the same radius.
    2. Place the pointed end of the compass on $$B$$ and draw a semi-circular arc with arbitrary radius and name its intersection with ray $$BC$$ as $$Q$$.
    3. Draw a ray $$BC$$.
    4. From point $$Q$$, mark a point $$R$$ on the arc with the same radius.
    5. Join $$B-P$$ and extend it to obtain ray $$BA$$

    $$The \  fifth \  step \  in \  the \  process \  is:$$
    Solution
    Correct sequence is :
    Step 1. Draw a ray $$BC$$.
    Step 2.Place the pointed end of the compass on $$B$$ and draw a semi-circular arc with arbitrary radius and name its intersection with the ray $$BC$$ as $$Q$$.
    Step 3. From $$Q$$ mark a point $$R$$ on the arc with the same radius.
    Step 4. From point $$R$$, mark a point $$P$$ on the same arc with same radius.
    Step 5. Join $$B-P$$ and extend it to obtain ray $$BA$$

    So the fifth step is $$5$$
    Option $$D$$ is correct.

  • Question 9
    1 / -0

    Directions For Questions

    The steps for constructing an $$\angle ABC$$ of measure $$120^\circ$$ are given below in jumbled order:
    1. From the point $$E$$, mark a point $$F$$ on the same arc with the same radius.
    2. Place the pointed end of the compass on $$B$$ and draw a semi-circular arc with arbitrary radius and name its intersection with ray $$BC$$ as $$D$$.
    3. Draw a ray $$BC$$.
    4. From point $$D$$, mark a point $$E$$ on the arc with the same radius.
    5. Join $$B-F$$ and extend it to obtain ray $$BA$$

    ...view full instructions

    The second step in the process is:
    Solution
    Correct sequence is :
    Step 1. Draw a ray $$BC$$.
    Step 2.Place the pointed end of the compass on $$B$$ and draw a semi-circular arc with arbitrary radius and name its intersection with the ray $$BC$$ as $$D$$.
    Step 3. From $$D$$ mark a point $$E$$ on the arc with the same radius.
    Step 4. From point $$E$$, mark a point $$F$$ on the same arc with same radius.
    Step 5. Join $$B-F$$ and extend it to obtain ray $$BA$$
    So the second step is $$2$$
    Option $$B$$ is correct.
  • Question 10
    1 / -0
    Which of the following angles cannot be constructed using a protractor?
    Solution
    A protractor has integral marking of angles .

    So $$56^{\circ}$$ , $$75^{\circ}$$  , $$90^{\circ} $$ can be drawn easily by protractor as they are integers .

    $$94.3^{\circ}$$ can not be drawn , it has decimal part.
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