Playing with Numbers Test

Result

Playing with Numbers Test - 25

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Weekly Quiz Competition

Question 1
1 / -0

What is the $$H.C.F.$$ of $$1134,\;1344$$ and $$1512$$?

A
$$42$$

B
$$64$$

C
$$1344$$

D
$$1512$$

Solution

$$1134 = 2\times3\times3\times3\times3\times7$$
$$=2^1\times3^4\times7^1$$

$$1344 = 2\times2\times2\times2\times2\times2\times3\times7$$
$$=2^6\times3^1\times7^1$$

$$1512 = 2\times2\times2\times3\times3\times3\times7$$
$$=2^3\times3^3\times7^1$$

$$\therefore \;\;H.C.F = 2\times 3\times 7 $$
$$= 42$$
Question 2
1 / -0

Some factor is missing in the factor tree. Fill it up.

A
$$4$$

B
$$6$$

C
$$3$$

D
$$2$$

Solution

$$56 = 7\times \underline {8}$$
$$= 7\times \underline {2\times 4}$$
$$= 7\times 2\times \underline {2\times 2}$$
The missing factor is $$4.$$
Therefore$$,$$ $$A$$ is the correct answer.
Question 3
1 / -0

Which of the following numbers are divisible by $$5$$ ?

A
$$125$$

B
$$625$$

C
$$1000$$

D
All of the above

Solution

A number is divisible by $$5$$, if it contains $$0$$ or $$5$$ in the units place.
Since all the numbers have $$0$$ or $$5$$ in the units place,
therefore all are divisible by $$5$$.

So, option D is correct.
Question 4
1 / -0

$$286$$ can be expressed as

A
$$2\times 11\times 13$$

B
$$3\times 11\times 13$$

C
$$3\times 5\times 11$$

D
$$11\times 2\times 5$$

Solution

$$2\times 11\times 13 = 286$$
Therefore, $$A$$ is the correct answer.
Question 5
1 / -0

The HCF of $$75$$ and $$15$$ is equal to

A
$$12$$

B
$$13$$

C
$$14$$

D
$$15$$

Solution

$$75=5\times5\times 3$$
$$15=5\times3$$
HCF$$=15$$
Question 6
1 / -0

The factor(s) of $$42$$ is/are

A
$$1$$

B
$$6$$

C
$$7$$

D
All of the above

Solution

$$42 = 1\times 2\times 3 \times 7$$.
The factors are $$1, 2, 3, 6, 7, 14, 21, 42$$.
So, option D is correct.
Question 7
1 / -0

Which of the following is divisible by $$3$$ ?

A
$$18$$

B
$$60$$

C
$$24$$

D
All of the above

Solution

A number is divisible by $$3$$ if the sum of its digits is divisible by $$3$$.
$$18 = 1 + 8 = 9$$
$$60 = 6 + 0 = 6$$
$$24 = 4 + 2 = 6$$
Therefore, all are divisible by $$3$$.
So, option D is correct.
Question 8
1 / -0

Which of the following numbers are divisible by $$3$$ ?

A
$$21$$`

B
$$24$$

C
$$27$$

D
All of the above

Solution

A number is divisible by $$3$$ only when sum of the digits of the number is divisible by $$3$$
Sum of digits of given numbers :
$$ 21 = 2+1=3$$
$$24 = 2+4=6$$
$$27 = 2+7=9$$
$$3,6,9$$ are divisible by $$3$$.
$$\therefore $$ All are divisible by $$3$$.
So, option D is correct.
Question 9
1 / -0

The the H.C.F of $$420$$ and $$396$$ is equal to

A
$$12$$

B
$$13$$

C
$$14$$

D
$$15$$

Solution

$$420 =7 \times 5\times 3\times 2\times2$$
$$396=2\times2 \times 3\times3\times 11$$
So, $$H.C.F=2\times2 \times 3=12$$
Ans- Option $$A$$
Question 10
1 / -0

The factor(s) of $$16$$ is/are

A
$$2$$

B
$$4$$

C
$$16$$

D
all of the above

Solution

$$16 = 2\times 2\times 2\times 2$$
The factors are $$1, 2, 4, 8, 16$$.
So, option D is correct.

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Re-Attempt Weekly Quiz Competition

Playing with Numbers Test - 25

Result

Playing with Numbers Test - 25

Score

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Rank

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SHARING IS CARING

Question 1

$$42$$

$$64$$

$$1344$$

$$1512$$

Solution

Question 2

$$4$$

$$6$$

$$3$$

$$2$$

Solution

Question 3

$$125$$

$$625$$

$$1000$$

All of the above

Solution

Question 4

$$2\times 11\times 13$$

$$3\times 11\times 13$$

$$3\times 5\times 11$$

$$11\times 2\times 5$$

Solution

Question 5

$$12$$

$$13$$

$$14$$

$$15$$

Solution

Question 6

$$1$$

$$6$$

$$7$$

All of the above

Solution

Question 7

$$18$$

$$60$$

$$24$$

All of the above

Solution

Question 8

$$21$$`

$$24$$

$$27$$

All of the above

Solution

Question 9

$$12$$

$$13$$

$$14$$

$$15$$

Solution

Question 10

$$2$$

$$4$$

$$16$$

all of the above

Solution

User

Question Analysis

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