Separation of Substances Test

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Separation of Substances Test - 11

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following aqueous solution is more concentrated?

(Assume that the density of the solution is $$1g/ml$$)

A
$$1M$$ Glucose

B
$$1m$$ Glucose

C
$$0.5m$$ Glucose

D
$$0.5M$$ Glucose

Solution

1 M glucose is more concentrated than 1m aqueous solution because 1M solution contains 1 mole of solute in 1 litre of solution [ where both solute and solvent are present]. This the mass of solvent [water]is less than 1000g/1litre. Whereas in 1m solution, 1 mole of solute is present in 1000g of solvent.
Question 2
1 / -0

Salt is separated from seawater by

A
evaporation

B
sublimation

C
filtration

D
All of these

Solution

Salt is separated from seawater by evaporation. In evaporation, water gets evaporated leaving behind salt.
Question 3
1 / -0

What happens when a saturated solution is cooled?

A
It becomes unsaturated

B
It remains unaffected

C
It becomes supersaturated

D
It becomes transparent

Solution

A solution in which no more solute can be dissolved at a given temperature is called a saturated solution, and the amount of solute present in a saturated solution at a given temperature is called solubility.
Solubility is directly proportional to temperature.

So, when temperature decreases (i.e., when the saturated solution is cooled), solubility also decreases.

Therefore, the solution becomes supersaturated.
Question 4
1 / -0

A mixture of water and NaCl can be separated by:

A
sublimation

B
evaporation

C
decantation

D
filtration

Solution

There is a difference in the boiling point of water and $$NaCl$$(salt). The boiling point of water is less than salt. On heating the mixture of water and $$NaCl$$, water evaporates leaving behind salt$$(NaCl)$$, so evaporation can be used to remove the water to obtain salt.
Question 5
1 / -0

The methods of separating components of a given mixture are based on the:

A
physical properties.

B
colour of the components only.

C
state of the components.

D
none of these.

Solution

Mixtures can be physically separated by using methods that use differences in physical properties to separate the components of the mixture, such as evaporation, distillation, filtration, and chromatography.
Hence, option A is correct.
Question 6
1 / -0

Winnowing is the method used to separate

A
chaff from grain.

B
stones from rice.

C
oil from water.

D
salt from sand.

Solution

Winnowing is the method used to separate $$\textbf{chaff from grain}$$.
Question 7
1 / -0

Winnowing is the method used to separate

A
Chaff from grain

B
Stones from rice

C
Oil from water

D
Salt from sand

Solution

Separating chaff from the grain is called winnowing.
Question 8
1 / -0

The methods of separating components of a given mixture are based on the.

A
physical properties and state of the components.

B
colour of the components only.

C
state of the components.

D
none of these.

Solution

Components of a given mixture can be separated on the basis of physical properties and the state of components (like solid, liquid, and gas).
Option $$A$$ is correct.
Question 9
1 / -0

A farmer drops the mixture of wheat and husk from a height. The separation is done by which of the following method?

A
filtration

B
threshing

C
sublimation

D
winnowing
Solution
- Filtration is a method for separating an insoluble solid from a liquid.
- The process that is used to separate the grain from stalks etc. is threshing. In this process, the stalks are beaten to free the grain seeds.
- Sublimation is a technique used to separate the components of a mixture containing a sublimable volatile solid and a non-sublimable impurity.
- The winnowing method is a process of throwing the grains from a certain height. The light-weighted chaffs are blown apart from the grains by the action of wind.
Therefore, the correct option is $$D$$.
Question 10
1 / -0

Stones are separated from pulses by

A
hand picking

B
winnowing

C
vaporization

D
none of the above

Solution

The hand-picking method is used to separate slightly larger size impurities or particles like stones, pieces of dirt, husk from the rice, wheat, etc. This method can be used in all those cases where the shape, size, and color of the substances are different.
Option $$A$$ is correct.

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Re-Attempt Weekly Quiz Competition

Separation of Substances Test - 11

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Separation of Substances Test - 11

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Question 1

$$1M$$ Glucose

$$1m$$ Glucose

$$0.5m$$ Glucose

$$0.5M$$ Glucose

Solution

Question 2

evaporation

sublimation

filtration

All of these

Solution

Question 3

It becomes unsaturated

It remains unaffected

It becomes supersaturated

It becomes transparent

Solution

Question 4

sublimation

evaporation

decantation

filtration

Solution

Question 5

physical properties.

colour of the components only.

state of the components.

none of these.

Solution

Question 6

chaff from grain.

stones from rice.

oil from water.

salt from sand.

Solution

Question 7

Chaff from grain

Stones from rice

Oil from water

Salt from sand

Solution

Question 8

physical properties and state of the components.

colour of the components only.

state of the components.

none of these.

Solution

Question 9

filtration

threshing

sublimation

winnowing

Solution

Question 10

hand picking

winnowing

vaporization

none of the above

Solution

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