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Practical Geome...

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  • Question 1
    1 / -0

    While constructing a parallel line to a given line, we______.

  • Question 2
    1 / -0

    Identify the given lines $$l,\ m$$ are ________.

  • Question 3
    1 / -0

    Length of  sides of a $$\triangle ABC$$ is $$AB=5\ cm$$, $$AC = 3\ cm$$ and $$BC=4\ cm$$. If the construction of the triangle formed by these three sides include following steps, then answer the following question: 

    Which of the following is the last step of construction?
    Steps of construction: 
    Step 1. Now join $$A$$ to $$C$$ and $$B$$ to $$C$$.
    Step 2. Assuming $$A$$ a centre draw an arc of radius $$3 \ \ cm$$
    Step 3. Now assuming $$B$$ as centre draw an arc of $$4 \ \ cm$$ intersecting the previous arc at $$C$$.
    Step 4. Draw a line segment $$AB= 5 \ cm$$

  • Question 4
    1 / -0

    The steps for construction of $$\triangle DEF$$ with $$DE = 4\ cm, EF=6.5\ cm$$ and $$DF = 8.6\ cm$$ are given below in jumbled order:
    1. Draw arcs of length $$4\ cm$$ from $$D$$ and $$6.5\ cm$$ from $$F$$ and mark the intersection point as $$E$$.
    2. Join $$D-E$$ and $$F-E$$.
    3. Draw a line segment of length $$DF = 8.6\ cm$$.

    The correct order of the steps is:

  • Question 5
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    Construct a triangle $$ABC$$, in which $$AB = 5.5 cm, AC = 6.5 cm$$ and $$\angle BAC = 70^{\circ}$$.
    If the stpes of construction are given as below the answer the following question:

    Which is the 2nd step of construction?
    1) At $$A$$, construct a line segment $$AE$$, sufficiently large, such that $$\angle BAC$$ at $$70^\circ$$, use protractor to measure $$70^\circ$$
    2) Draw a line segment which is sufficiently long using ruler.
    3) With $$A$$ as centre and radius $$6.5cm$$, draw the line cutting $$AE$$ at C, join $$BC$$, then $$ABC$$ is the required triangle.
    4) Locate points $$A$$ and $$B$$ on it such that $$AB = 5.5cm$$.

  • Question 6
    1 / -0

    Given a, b and c are sides of a triangle,identify the correctly constructed triangle.














  • Question 7
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    Construct a $$\triangle PQR$$ such that $$\angle P = 30^\circ, \angle Q = 60^\circ$$ and $$PQ = 10\ cm$$.
    If following are the steps of construction, then answer the following question:
    Which of the following is the first step of construction?
    Steps of Construction:
    Step 1. At $$P$$, draw a ray making an angle of $$30^{\circ}$$.
    Step 2. At $$Q$$, draw another ray making an angle of $$60^{\circ}$$ which intersects the first ray at $$R$$. Thus, $$\triangle PQR$$ is the required triangle.
    Step 3. Draw a line segment $$PQ = 10\space\mathrm{cm}$$.

  • Question 8
    1 / -0

    Length of  sides of a $$\triangle ABC$$ is $$AB=5\ cm$$, $$AC = 3\ cm$$ and $$BC=4\ cm$$. Then, construct the triangle formed by these three sides by following these steps. Put them in proper order.
    Step 1. Draw a line segment $$AB=5\ \ cm$$
    Step 2. Now assuming $$B$$ as centre draw an arc of $$4 \ \ cm$$ intersecting the previous arc at $$C$$.
    Step 3. Assuming $$A$$ a centre draw an arc of radius $$3 \ \ cm$$
    Step 4. Now join $$A$$ to $$C$$ and $$B$$ to $$C$$.

  • Question 9
    1 / -0

    Construct a $$\triangle PQR$$ such that $$\angle P = 30^\circ, \angle Q = 60^\circ$$ and $$PQ = 10\ cm$$.
    If following are the steps of construction, then which of the following is not a part of construction?
    Steps of Construction:
    (i) Draw a line segment $$PQ = 10\space\mathrm{cm}$$.
    (ii) At $$P$$, draw a ray making an angle of $$30^{\circ}$$.
    (iii) At $$Q$$, draw another ray making an angle of $$60^{\circ}$$ which intersects the first ray at $$R$$.
    $$\triangle PQR$$ is the required triangle.

  • Question 10
    1 / -0

    Construct a $$\triangle PQR$$ such that $$\angle P = 30^\circ, \angle Q = 60^\circ$$ and $$PQ = 10\ cm$$.

    If the following are the steps of construction, then answer the following question:

    Which of the following is the last step of construction?

    Steps of Construction:

    Step 1. At $$P$$, draw a ray making an angle of $$30^{\circ}$$.

    Step 2. At $$Q$$, draw another ray making an angle of $$60^{\circ}$$       
                 which intersects the first ray at $$R$$. 
                 Thus, $$\triangle PQR$$ is the required triangle.

    Step 3. Draw a line segment $$PQ = 10\space\mathrm{cm}$$.

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