Perimeter and Area Test

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Perimeter and Area Test - 16

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Weekly Quiz Competition

Question 1
1 / -0

If the circumference of a circle is $352$ metres, then its area (approx)in $\text{ m }^{ 2 }$ is

A
$9859$

B
$8956$

C
$6589$

D
$5986$

Solution
Question 2
1 / -0

Find the circumference of the circle with the following radius : 10 cm

A
$20 \pi \ cm$

B
$10 \pi \ cm$

C
$30 \pi \ cm$

D
None of these

Solution

Radius, r = 10 cm
We know, Circumference = $2\pi r = 2 \times \pi \times 10 =20 \pi \ cm$
Question 3
1 / -0

The area of circle with radius $24\ cm$ is

A
$576\pi$

B
$24\pi$

C
$12\pi$

D
$48\pi$

Solution

The radius of circle = $24\ cm$
The area of circle of radius $r = \pi r^2$
$\therefore$ Required area = $π \times {24}^2\ cm^2 = 576 \pi\ cm^2$
Question 4
1 / -0

Circumference of a circle is always

A
more than three times of its diameter

B
three times of its diameter

C
less than three times of its diameter

D
three times of its radius.

Solution

Option (a) is correct.
As we know [bat Circumference of a circle $2 \times 3.14 \times r$
$\Rightarrow circumference = 3.14 \times d$
Therefore, Circumference of a circle is more than three of its diameter.
Question 5
1 / -0

If the radius of a circle is tripled, The area becomes

A
$9\ times$

B
$3\ times$

C
$remains\ the\ same$

D
$\sqrt{3}\ times$

Solution

Let the radius of the circle be $r$ .
So Area $=A=\pi r^2$
If radius is tripled, then radius becomes $3r$ .

Now, area of circle $A'=\pi(3r)^2 =9\pi r^2=9A$
Therefore. if the radius of a circle is tripled, the area becomes $9\ times$ .
Question 6
1 / -0

Circumference of a circle disc is $88\, cm$ . Its radius is.

A
$8\, cm$

B
$11\, cm$

C
$14\, cm$

D
$44\, cm$

Solution

Option (c) is correct.
We know that.
Circumference $= 2\pi r =88$
$\Rightarrow 88=2\times \dfrac {22}{7} \times r$

$\Rightarrow r=\dfrac {88\times 7}{2\times 22}$

$\Rightarrow r= 14\, cm$
Therefore, $14\,cm$ is the radius.
Question 7
1 / -0

If $1m^2 = x\, mm^2$ , then the value of x is.

A
$1000$

B
$10000$

C
$100000$

D
$1000000$

Solution

We know that $1m = 1000mm$ , then $1m^2 = (1000)^2 mm$
Option (d) is correct.
Given, $1\,m^2= x\, mm^2$
$\Rightarrow (1000\,mm)^2 = x\,mm ^2$
$\Rightarrow x =1000000$
Question 8
1 / -0

Area of a circle with diameter $m$ , radius $n$ and circumference $p$ is

A
$2 \pi \, n$

B
$\pi \, m^2$

C
$\pi \, p^2$

D
$\pi \, n^2$

Solution

Option (d) is correct.
Given,
Diameter $= m$
Radius $= n$ ,
Circumference $= p$ .
Therefore, area of circle $= \pi r^2=\pi n^2$
Question 9
1 / -0

Circumference of a circle of diameter $5 \, cm$ is

A
$5 \, cm$

B
$31.4 \, cm$

C
$15.7 \, cm$

D
$1.57 \, cm$

Solution

Option (c) is correct. Given,
Diameter $= 5 \,cm$
Hence. Radius $=\dfrac {5}{2}\, cm$

Now. circumference $= 2\pi r = 2\times \dfrac {22}{7}\times \dfrac {5}{2}$
$=\dfrac {110}{7}= 15.7\, cm$
Question 10
1 / -0

If the sum of the areas of two circles with radii $R_1$ and $R_2$ is equal to the area of a circle of radius R, then

A
$R_{1}+R_{2}=R$

B
$R_{1}^{2}+R_{2}^{2}=R^{2}$

C
$R_{1}+R_{2} < R$

D
$R_{1}^{2}+R_{2}^{2} < R^{2}$

Solution

$ar.circle\quad with\quad radius\quad { R }_{ 1 }=\pi { { R }_{ 1 } }^{ 2 }\quad and\\ ar.circle\quad with\quad radius\quad { R }_{ 2 }=\pi { { R }_{ 2 } }^{ 2 }.\\ \therefore \quad sum\quad of\quad the\quad areas=\pi \left( { { R }_{ 1 } }^{ 2 }+{ { R }_{ 2 } }^{ 2 } \right) .\\ \quad Again\quad ar.circle\quad with\quad radius\quad R=\pi { { R } }^{ 2 }.\\ \therefore \quad By\quad the\quad given\quad condition\quad \pi \left( { { R }_{ 1 } }^{ 2 }+{ { R }_{ 2 } }^{ 2 } \right) =\pi { { R } }^{ 2 }\\ \Longrightarrow \left( { { R }_{ 1 } }^{ 2 }+{ { R }_{ 2 } }^{ 2 } \right) ={ { R } }^{ 2 }.\\ Ans-\quad Option\quad B.\\$

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Re-Attempt Weekly Quiz Competition

Perimeter and Area Test - 16

Result

Perimeter and Area Test - 16

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Rank

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SHARING IS CARING

Question 1

985998599859

895689568956

658965896589

598659865986

Solution

Question 2

20π cm20 \pi \ cm20π cm

10π cm10 \pi \ cm10π cm

30π cm30 \pi \ cm30π cm

None of these

Solution

Question 3

576π576\pi 576π

24π24\pi24π

12π12\pi12π

48π48\pi48π

Solution

Question 4

more than three times of its diameter

three times of its diameter

less than three times of its diameter

three times of its radius.

Solution

Question 5

9 times9\ times9 times

3 times3\ times3 times

remains the sameremains\ the\ sameremains the same

3 times\sqrt{3}\ times3​ times

Solution

Question 6

8 cm8\, cm8cm

11 cm11\, cm11cm

14 cm14\, cm14cm

44 cm44\, cm44cm

Solution

Question 7

10001000 1000

100001000010000

100000100000 100000

10000001000000 1000000

Solution

Question 8

2π n2 \pi \, n2πn

π m2\pi \, m^2πm2

π p2\pi \, p^2πp2

π n2\pi \, n^2πn2

Solution

Question 9

5 cm5 \, cm5cm

31.4 cm 31.4 \, cm31.4cm

15.7 cm15.7 \, cm15.7cm

1.57 cm1.57 \, cm1.57cm

Solution

Question 10

R1+R2=RR_{1}+R_{2}=RR1​+R2​=R

R12+R22=R2R_{1}^{2}+R_{2}^{2}=R^{2}R12​+R22​=R2

R1+R2<RR_{1}+R_{2} < RR1​+R2​<R

R12+R22<R2R_{1}^{2}+R_{2}^{2} < R^{2}R12​+R22​<R2

Solution

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$9859$

$8956$

$6589$

$5986$

$20 \pi \ cm$

$10 \pi \ cm$

$30 \pi \ cm$

$576\pi$

$24\pi$

$12\pi$

$48\pi$

$9\ times$

$3\ times$

$remains\ the\ same$

$\sqrt{3}\ times$

$8\, cm$

$11\, cm$

$14\, cm$

$44\, cm$

$1000$

$10000$

$100000$

$1000000$

$2 \pi \, n$

$\pi \, m^2$

$\pi \, p^2$

$\pi \, n^2$

$5 \, cm$

$31.4 \, cm$

$15.7 \, cm$

$1.57 \, cm$

$R_{1}+R_{2}=R$

$R_{1}^{2}+R_{2}^{2}=R^{2}$

$R_{1}+R_{2} < R$

$R_{1}^{2}+R_{2}^{2} < R^{2}$