Exponents and Powers Test

Result

Exponents and Powers Test - 12

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Weekly Quiz Competition

Question 1
1 / -0

The expression $$[(-1^{10})^{10}]^{11}$$ is equal to

A
$$-1$$

B
$$1$$

C
$$0$$

D
$$(-1)^{31}$$

Solution

$$[(-1^{10})^{10}]^{11} = [(-1^{100})]^{11}$$

$$= (-1)^{1100}$$ $$=1$$

So, option $$B$$ is correct.
Question 2
1 / -0

Evaluate: $$(-5)^{8} \div (-5)^{5}$$

A
$$125$$

B
$$\dfrac {1}{125}$$

C
$$-\dfrac {1}{125}$$

D
$$-125$$

Solution

$$(-5)^{8} \div (-5)^{5} = \dfrac {(-5)^{8}}{(-5)^{5}}$$

$$=(-5)^{8-5} = (-5)^{3} $$

$$= -125$$

So, option $$D$$ is correct.
Question 3
1 / -0

Find the value of $$m$$, if $$(16^{8})^{m} = (16)^0$$.

A
$$0$$

B
$$1$$

C
$$16$$

D
$$8$$

Solution

$$(16^{8})^{m} = (16)^{0}$$

$$\therefore 16^{8m} = 16^{0}$$

$$\therefore 8m = 0$$
$$\therefore m = 0$$

So, option $$A$$ is correct.
Question 4
1 / -0

Which one of the following is the value of $$(101)^{0}$$?

A
$$0$$

B
$$101$$

C
$$1010$$

D
$$1$$

Solution

$$101^{0} = 1$$

So, option $$D$$ is correct.
Question 5
1 / -0

The value of $$(10)^{0} \times (20)^{0}\times (30)^{0}$$ is:

A
$$1$$

B
$$3$$

C
$$60$$

D
$$0$$

Solution

$$(10)^{0} \times (20)^{0} \times (30)^{0} = 1\times 1\times 1 = 1$$

So, option $$A$$ is correct.
Question 6
1 / -0

Find the value of $$(6)^{0} - (10)^{0}$$

A
$$-4$$

B
$$2$$

C
$$1$$

D
$$0$$

Solution

$$(6)^0 - (10)^0 = 1-1 = 0$$
So, option $$D$$ is correct.
Question 7
1 / -0

The expression $$((2)^{0} + (3)^{0} + (5)^{0})^{0}$$ is equal to _____

A
$$3$$

B
$$1$$

C
$$10$$

D
$$0$$

Solution

$$((2)^{0} + (3)^{0} + (5)^{0})^{0} = (1 + 1 + 1)^{0}$$
$$= 3^{0}$$
$$= 1$$

So, option $$B$$ is the correct answer.
Question 8
1 / -0

Which of the following is equal to $$1$$?

A
$$(3)^{0} + (3)^{0}$$

B
$$(3)^{0} - (3)^{0}$$

C
$$(3)^{0}$$

D
$$(3^{3})^{0} + (3^{0})^{3}$$

Solution

$$\textbf{Step 1: Simplify the following expressions.}$$

$$(a)\ 3^0+3^0=1+1=2\neq 1$$

$$(b)\ 3^0-3^0=1-1=0\neq 1$$

$$(c)\ 3^0=1$$

$$(d)\ (3^3)^0+(3^0)^3=9^0+1^3=1+1=2\neq 1$$

$$\textbf{Hence, Option C is correct.}$$
Question 9
1 / -0

Simplify: $$\left((9)^{0} + (11)^{0} + (13)^{0}\right) \div (23)^{0}$$

A
$$1$$

B
$$3$$

C
$$0$$

D
$$2$$

Solution

$$\left((9)^{0} + (11)^{0} + (13)^{0}\right) \div (23)^{0}$$
$$= (1 + 1 + 1) \div 1$$
$$= 3\div 1$$
$$= 3$$
So, option $$B$$ is correct.
Question 10
1 / -0

The value of $$((6)^{0} + (16)^{0}) \div ((7)^{0} + (17)^{0})$$ is _____

A
$$2$$

B
$$4$$

C
$$1$$

D
$$0$$

Solution

$$((6)^{0} + (16)^{0}) \div ((7)^{0} + (17)^{0})$$
$$ = (1 + 1)\div (1 + 1)$$
$$= 2\div 2$$
$$= 1$$
So, option $$C$$ is correct.

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Re-Attempt Weekly Quiz Competition

Exponents and Powers Test - 12

Result

Exponents and Powers Test - 12

Score

-

Rank

-

SHARING IS CARING

Question 1

$$-1$$

$$1$$

$$0$$

$$(-1)^{31}$$

Solution

Question 2

$$125$$

$$\dfrac {1}{125}$$

$$-\dfrac {1}{125}$$

$$-125$$

Solution

Question 3

$$0$$

$$1$$

$$16$$

$$8$$

Solution

Question 4

$$0$$

$$101$$

$$1010$$

$$1$$

Solution

Question 5

$$1$$

$$3$$

$$60$$

$$0$$

Solution

Question 6

$$-4$$

$$2$$

$$1$$

$$0$$

Solution

Question 7

$$3$$

$$1$$

$$10$$

$$0$$

Solution

Question 8

$$(3)^{0} + (3)^{0}$$

$$(3)^{0} - (3)^{0}$$

$$(3)^{0}$$

$$(3^{3})^{0} + (3^{0})^{3}$$

Solution

Question 9

$$1$$

$$3$$

$$0$$

$$2$$

Solution

Question 10

$$2$$

$$4$$

$$1$$

$$0$$

Solution

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