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Fractions and Decimals Test - 28

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Fractions and Decimals Test - 28
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Solve : $$25 +\displaystyle{\frac{3}{100}}+\displaystyle{\frac{4}{1000}}=$$ ?
    Solution
    The value of $$25 $$ $$+$$ $$\displaystyle{\frac{3}{100}}$$ $$+$$ $$\displaystyle{\frac{4}{1000}}$$ is
    $$=25+0.03+0.004$$
    $$= 25.034$$
  • Question 2
    1 / -0
    Which of the following is a proper fraction ?
    Solution
    Fraction is proper if the denominator is greater than the numerator.
    Fraction is improper if the numerator is greater than or equal to the denominator.
    fig A = $$\cfrac{4}{8}$$ = proper fraction
    fig B = $$\cfrac{6}{9}$$ = proper fraction
    fig C = $$\cfrac{1}{4}$$ = proper fraction

  • Question 3
    1 / -0
    Example for a proper fraction is
    Solution
    Proper fraction is a fraction in which the numerator is less than the denominator, for example $$\dfrac {11}{23}$$.

    Hence, $$\dfrac {11}{23}$$ is a proper fraction.
  • Question 4
    1 / -0
    If $$\displaystyle \frac{547.527}{0.0082}=x $$, then the value of $$\displaystyle \frac{547527}{82}$$ is 
    Solution
    Given, $$\displaystyle \frac{547.527}{0.0082}=x $$

    $$\displaystyle \Rightarrow \frac{547527\times 10000}{82\times 1000}=x $$

    $$\displaystyle \Rightarrow \frac{5475270}{82}=x $$

    $$\displaystyle \Rightarrow \frac{5475270}{82\times10}=\frac{x}{10} $$

    $$\displaystyle \Rightarrow \frac{547527}{82}=\frac{x}{10} $$

    Hence, $$Op-A$$ is correct.
  • Question 5
    1 / -0
    Example for an improper fraction is
    Solution
    Improper fraction is a fraction in which the numerator is greater than the denominator.

    Hence, $$\dfrac {15}{14}$$ is an improper fraction.
  • Question 6
    1 / -0
    The result of $$(54.327\times 357.2\times 0.0057)$$ is the same as
    Solution
    $$54.327 \times 357.2 \times 0.0057 = \cfrac {54327}{1000} \times \cfrac {3572}{10} \times \cfrac {57}{10000}$$
                                                 $$= \cfrac {54327}{1000} \times \cfrac {10}{10} \times \cfrac {3572}{10} \times \cfrac {100}{100} \times \cfrac {57}{10000} \times \cfrac {1000}{1000}$$
                                                 $$= \cfrac {54327}{10000} \times 10 \times \cfrac {3572}{1000} \times 100 \times \cfrac {57}{10000} \times \cfrac {1000}{1000}$$

                                               $$= 5.4327 \times 3.572 \times 5.7 \times 10 \times 100 \times \cfrac {1}{1000}$$
                                               $$= 5.4327 \times 3.572 \times 5.7$$

    Hence, option A is correct.
  • Question 7
    1 / -0
    $$\displaystyle 4\frac{7}{11}$$ = $$\displaystyle \frac{?}{11}$$
    Solution
    $$\displaystyle 4 \frac{7}{11} =  \frac{4 \times 11 + 7}{11} =  \frac{51}{11}$$
  • Question 8
    1 / -0
    Expanded form of $$78.059$$ is
    Solution
    Expanded form of $$78.059$$ is $$70+ 8+\displaystyle \frac { 0 }{ 10 } +\frac { 5 }{ 100 } +\frac { 9 }{ 1000 } $$


  • Question 9
    1 / -0
    If $$\displaystyle\frac { 1 }{ 6.198 } = 0.16134$$, then the value of $$\displaystyle\frac { 1 }{ 0.0006198 } $$ is.
    Solution
    $$\displaystyle\frac { 1 }{ 0.0006198 } = \displaystyle\frac { 1 }{ \displaystyle\frac { 6.198 }{ 10000 }  } \\= \displaystyle\frac { 10000 }{ 6.198 } \\=10000\times\dfrac{1}{6.198}\\= 10000 \times 0.16134 \\= 1613.4$$
  • Question 10
    1 / -0
    $$\displaystyle  \frac { 2 }{ 4 }$$ of a rupee = .......paise 
    Solution
    1 rupee=100 paise
    so $$\dfrac{2}{4}$$ of a rupee=$$\dfrac{2}{4}\times100=50$$ paise
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