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Fractions and Decimals Test - 33

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Fractions and Decimals Test - 33
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  • Question 1
    1 / -0
    If the numerator and denominator of a proper fraction are increased by the same quantity, then the resulting fraction is?
    Solution
    If the numerator and denominator of a proper fraction are increased by the same quantity, then the resulting fraction is always greater than the original fraction.

    Let us understand and verify it with the help of couple of examples:

    $$(i)$$ Let $$\dfrac{1}{2}$$ be an original fraction.
    $$\dfrac{1}{2}=0.5$$
    If the numerator and denominator are increased by $$5$$, the fraction becomes:
    $$\dfrac{1+5}{2+5}=\dfrac{5}{7}=0.71$$

    $$\therefore$$   $$\dfrac{1}{2}<\dfrac{5}{7}$$

    $$(ii)$$ Let $$\dfrac{7}{9}$$ be an original fraction.
    $$\dfrac{7}{9}\approx 0.78$$
    If the numerator and denominator are increased by $$1$$, the fraction becomes:
    $$\dfrac{7+1}{9+1}=\dfrac{8}{10}=0.8$$

    $$\therefore$$   $$\dfrac{7}{9}<\dfrac{8}{10}$$

    Hence, if the numerator and denominator of a proper fraction are increased by the same quantity, then the resulting fraction is always greater than the original fraction.

    Therefore, option A is correct.
  • Question 2
    1 / -0
    The simplification of $$33.6 - 2 { .05 } + 0.133$$ is equal to
    Solution

  • Question 3
    1 / -0
    Evaluate: $$3.7-1.9$$
    Solution
    $$3.7-1.9$$
    $$=1.8$$
  • Question 4
    1 / -0
    A  proper fraction with denominator $$3$$ , which is less than 1 is 
    Solution
    Clearly from question denominator$$=3$$
                                         numerator $$=2$$
                    Fraction $$=\dfrac{2}{3}$$
  • Question 5
    1 / -0
    A fraction whose numerator is greater than its denominator is           fraction.
    Solution
    That will be an improper fraction
    Ex $$\dfrac{6}{5}$$
  • Question 6
    1 / -0
    Multiply $$\dfrac{6}{13}$$ by the reciprocal of $$\dfrac{-7}{16}$$
    Solution
    Reciprocal of $$\dfrac{-7}{16}$$ is $$\dfrac{-16}{7}$$

    Now $$\dfrac{6}{13}\times$$ Reciprocal of $$\dfrac{-7}{16}$$

    $$=\dfrac{6}{13}\times\dfrac{-16}{7}$$

    $$=\dfrac{6\times -16}{13\times 7}=\dfrac{-96}{91}$$
  • Question 7
    1 / -0
    Which of the following is a proper fraction?
    Solution
    We know that, if the numerator is less than the denominator then the fraction is called as proper fraction.
    Amongst the given fractions only $$\dfrac78$$ has a numerator that is less than the denominator.

    Hence, $$\dfrac78$$ is a proper fraction.
  • Question 8
    1 / -0
    Mark against the correct answer in each of the following:
    $$ ( 1.007 - 0.7) = ? $$

    Solution
    $$ 3.07 $$
    First convert the given decimals into like decimals

    $$ = (1.007 – 0.700)$$

    $$ = 0.307 $$
  • Question 9
    1 / -0
    Which of the following is an improper fraction?
    Solution
    Improper fraction is a fraction in which numerator is greater than denominator.
    $$\cfrac{9}{7}$$ follows this condition.
    Hence, option $$(C)$$ is correct.
  • Question 10
    1 / -0
    $$5.2 - 3.6$$ is equal to
    Solution
    $$5.2 - 3.6 = \dfrac{52}{10} - \dfrac{36}{10} $$

                     $$= \dfrac{16}{10}$$

                     $$=1.6$$
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