Data Handling Test

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Data Handling Test - 15

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Weekly Quiz Competition

Question 1
1 / -0

The mean of the factors of 24 is;

A
$$\displaystyle \frac{12}{5}$$

B
$$\displaystyle \frac{9}{5}$$

C
$$\displaystyle \frac{15}{2}$$

D
$$\displaystyle \frac{17}{5}$$

Solution

The factor of 24 are 1,2,3,4,6,8,12,24
$$\therefore A.M=\dfrac{\sum x}{n}$$
$$\Rightarrow \dfrac{1+2+3+4+6+8+12+24}{8}$$
$$\Rightarrow \dfrac{60}{8}=\dfrac{15}{2}$$
Question 2
1 / -0

The arithmetic mean of 5, 6, 8, 9, 12, 13, 17 is

A
$$20$$

B
$$15$$

C
$$10$$

D
$$25$$

Solution

Arithmetic mean $$=\dfrac {\text{Sum of Terms}}{\text{No. of Terms}}=\dfrac {5+6+8+9+12+13+17}{7}$$

Arithmetic mean $$=\dfrac {70}{7} = 10$$
Question 3
1 / -0

The mean of first 8 natural numbers is

A
$$4.5$$

B
$$5$$

C
$$4$$

D
$$5.5$$

Solution

$$\textbf{Step 1: Finding the sum of observations and number of observations}$$

$$\text{The first 8 natural numbers are }1,\;2,\;3,\;4,\;5,\;6,\;7,\;8$$

$$\text{Sum of observations}=1+2+3+4+5+6+7+8=36$$

$$\text{Number of observations}=8$$

$$\textbf{Step 2: Finding the mean}$$

$$\text{Mean}=\dfrac{\text{Sum of observations}}{\text{Number of observations}}$$

$$\text{Mean}=\dfrac{36}{8}=4.5$$

$$\textbf{Thus, the mean of the first 8 natural numbers is 4.5}$$
Question 4
1 / -0

Find the AM of $$20$$ and $$26$$.

A
$$23$$

B
$$22$$

C
$$21$$

D
$$24$$

Solution

$$\displaystyle AM=\frac { 20+26 }{ 2 } =\frac { 46 }{ 2 } =23$$
Question 5
1 / -0

Mean of $$14, 17, 11, 13, 26, 21, 31$$, and $$19 $$

A
18

B
19

C
17

D
None of these

Solution

Sum of number $$\displaystyle =152$$
Required mean $$\displaystyle =152/8=19$$
Question 6
1 / -0

Consider the data: $$2, 3, 2, 4, 5, 6, 4, 2, 3, 3, 7, 8, 2, 2$$. The frequency of $$2$$ is _____

A
$$4$$

B
$$5$$

C
$$6$$

D
$$3$$

Solution

Number of times $$ 2 $$ occurs in the given data is $$ 5 $$

So, frequency of $$ 2 $$ in given data is $$ 5 $$.
Question 7
1 / -0

Mode of the distribution is that value of the variate for which the_____is_____

A
frequency, maximum

B
Frequency, minimum

C
frequency, arithmetic mean

D
median, mode

Solution

Mode of the distribution is that value of the variate for which the frequency is maximum.
Question 8
1 / -0

In a bar chart:

A
rectangles are of equal lengths

B
width of rectangles is fixed

C
rectangles are drawn with unequal shapes between them

D
width of rectangles carry important meaning

Solution

In a bat chart, width of rectangle is fixed
Question 9
1 / -0

The mean of the following natural numbers $$1, 2,3 ...... 10$$ is

A
$$6.5$$

B
$$4.5$$

C
$$5.5$$

D
$$5.4$$

Solution

Mean $$ = \dfrac {1 + 2 + 3 + 4 + 5 +6 + 7 + 8 + 9 + 10}{10} = 5.5 $$
Question 10
1 / -0

Find the median number of newspaper purchased in a story by $$9$$ customers.
$$2, 4, 5, 1, 6, 8, 9, 4, 7$$

A
$$2$$

B
$$4$$

C
$$5$$

D
$$7$$

Solution

The median of a set of data is the middlemost number in the set.
So, first arrange the data in order.
$$1, 2, 4, 4, 5, 6, 7, 8, 9$$
The median is $$5$$.

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Re-Attempt Weekly Quiz Competition

Data Handling Test - 15

Result

Data Handling Test - 15

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Rank

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SHARING IS CARING

Question 1

$$\displaystyle \frac{12}{5}$$

$$\displaystyle \frac{9}{5}$$

$$\displaystyle \frac{15}{2}$$

$$\displaystyle \frac{17}{5}$$

Solution

Question 2

$$20$$

$$15$$

$$10$$

$$25$$

Solution

Question 3

$$4.5$$

$$5$$

$$4$$

$$5.5$$

Solution

Question 4

$$23$$

$$22$$

$$21$$

$$24$$

Solution

Question 5

18

19

17

None of these

Solution

Question 6

$$4$$

$$5$$

$$6$$

$$3$$

Solution

Question 7

frequency, maximum

Frequency, minimum

frequency, arithmetic mean

median, mode

Solution

Question 8

rectangles are of equal lengths

width of rectangles is fixed

rectangles are drawn with unequal shapes between them

width of rectangles carry important meaning

Solution

Question 9

$$6.5$$

$$4.5$$

$$5.5$$

$$5.4$$

Solution

Question 10

$$2$$

$$4$$

$$5$$

$$7$$

Solution

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