Data Handling Test

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Data Handling Test - 23

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Weekly Quiz Competition

Question 1
1 / -0

Find the average of $$80, 90, 100, 110, 120, 130$$.

A
$$100$$

B
$$105$$

C
$$110$$

D
$$115$$

Solution

Given numbers$$=80,90,100,110,120,130$$
Average $$=\dfrac{\text{Sum of observations}}{\text{Number of observations}}$$

Average $$=\cfrac { 80+90+100+110+120+130 }{ 6 } $$

$$= \cfrac { 630 }{ 6 } =105$$
Question 2
1 / -0

Consider the data: $$2, x, 3, 4, 5, 2, 4, 6, 4$$ where $$x >2$$
The mode of the data is _____

A
$$2$$

B
$$3$$

C
$$4$$

D
$$5$$

Solution

The value which occurs the maximum number of times in a given set of data is know as mode.
In the given data $$4$$ occurs 3 times and hence it is the mode. But $$x$$ is unknown.
We know that $$x>2$$
Hence even if we consider $$x$$ as $$3,4,5\ or\ 6$$ still $$4$$ will remain as the mode.
Hence $$4$$ is the ans.
Question 3
1 / -0

The arithmetic mean of $$2+\sqrt {(2)}$$ and $$2-\sqrt {(2)}$$ is

A
$$2$$

B
$$\sqrt {(2)}$$

C
$$0$$

D
$$4$$

Solution

The arithmetic mean of $$2+\sqrt 2$$ and $$2-\sqrt 2$$ $$=\displaystyle \frac {2+\sqrt 2+2-\sqrt 2}{2}$$
$$=\dfrac {4}{2}$$

$$=2$$
Option A is correct.
Question 4
1 / -0

The range of $$8, 17, 28, 16, 30, 28, 15, 5, 19$$ and $$35$$ is _____

A
$$20$$

B
$$18$$

C
$$30$$

D
$$16$$

Solution

The difference between the maximum and minimum data entries is called the range
So, Range = maximum number - minimum number
Range = $$35 -5$$
Range =$$30$$
Question 5
1 / -0

Find the average of $$201, 204, 207, 210, 213$$.

A
$$204$$

B
$$207$$

C
$$213$$

D
$$208$$

Solution

Average of Number $$=\cfrac { Sum\quad of\quad all\quad numbers }{ Total\quad number\quad of\quad number } $$
$$=\cfrac { 201+207+210+213+204 }{ 5 } $$
$$=>\cfrac { 1035 }{ 5 } =207$$
Question 6
1 / -0

What is the average(arithmetic mean) of all the multiples of ten from $$10$$ to $$190$$ inclusive?

A
$$90$$

B
$$95$$

C
$$100$$

D
$$105$$

E
$$110$$

Solution
Question 7
1 / -0

Which year did the same number of boys and girls attend the conference?

A
1995

B
1996

C
1997

D
1998

E
None
Question 8
1 / -0

Find the arithmetic mean of the progression $$2, 4, 6, 8, 10.$$

A
$$10$$

B
$$20$$

C
$$30$$

D
$$6$$

Solution

Using the formula for Required arithmetic mean $$=\dfrac{\text{sum of the terms}}{\text{number of terms}}$$

After substituting the values we get$$=\dfrac{2+4+6+8+10}{5}=\dfrac{30}{5}=6$$
Question 9
1 / -0

Directions For Questions

Study the bar chart and answer the questions.

...view full instructions

The difference in the sales of cellular phones for the years $$1997$$ and $$1999$$ is?

A
$$500$$ units

B
$$1,000$$ units

C
$$5,000$$ units

D
$$18,000$$ units

Solution

The given graph shows the sale of cellular phones in the years $$1997, 1998, 1999, 2000,2001$$ and $$2002$$.

In the year $$1997$$, the sale of cellular phones is $$48000$$.
In the year $$1999$$, the sale of cellular phones is $$30000$$.

Therefore, the difference in the sales of cellular phones for the year $$1997$$ and $$1999$$ is,
$$48000-30000=18000$$

Hence, the difference in the sales of cellular phones for the year $$1997$$ and $$1999$$ is $$18,000$$ units.
Thus, option $$D$$ is correct.
Question 10
1 / -0

If the average arithmetic mean of 8, 12, 15, 21, x and 11 is 17 then what is x?

A
3

B
15

C
17

D
35

E
42

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Re-Attempt Weekly Quiz Competition

Data Handling Test - 23

Result

Data Handling Test - 23

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SHARING IS CARING

Question 1

$$100$$

$$105$$

$$110$$

$$115$$

Solution

Question 2

$$2$$

$$3$$

$$4$$

$$5$$

Solution

Question 3

$$2$$

$$\sqrt {(2)}$$

$$0$$

$$4$$

Solution

Question 4

$$20$$

$$18$$

$$30$$

$$16$$

Solution

Question 5

$$204$$

$$207$$

$$213$$

$$208$$

Solution

Question 6

$$90$$

$$95$$

$$100$$

$$105$$

$$110$$

Solution

Question 7

1995

1996

1997

1998

None

Question 8

$$10$$

$$20$$

$$30$$

$$6$$

Solution

Question 9

$$500$$ units

$$1,000$$ units

$$5,000$$ units

$$18,000$$ units

Solution

Question 10

3

15

17

35

42

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