Data Handling Test

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Data Handling Test - 23

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Weekly Quiz Competition

Question 1
1 / -0

Find the average of $80, 90, 100, 110, 120, 130$ .

A
$100$

B
$105$

C
$110$

D
$115$

Solution

Given numbers $=80,90,100,110,120,130$
Average $=\dfrac{\text{Sum of observations}}{\text{Number of observations}}$

Average $=\cfrac { 80+90+100+110+120+130 }{ 6 }$

$= \cfrac { 630 }{ 6 } =105$
Question 2
1 / -0

Consider the data: $2, x, 3, 4, 5, 2, 4, 6, 4$ where $x >2$
The mode of the data is _____

A
$2$

B
$3$

C
$4$

D
$5$

Solution

The value which occurs the maximum number of times in a given set of data is know as mode.
In the given data $4$ occurs 3 times and hence it is the mode. But $x$ is unknown.
We know that $x>2$
Hence even if we consider $x$ as $3,4,5\ or\ 6$ still $4$ will remain as the mode.
Hence $4$ is the ans.
Question 3
1 / -0

The arithmetic mean of $2+\sqrt {(2)}$ and $2-\sqrt {(2)}$ is

A
$2$

B
$\sqrt {(2)}$

C
$0$

D
$4$

Solution

The arithmetic mean of $2+\sqrt 2$ and $2-\sqrt 2$ $=\displaystyle \frac {2+\sqrt 2+2-\sqrt 2}{2}$
$=\dfrac {4}{2}$

$=2$
Option A is correct.
Question 4
1 / -0

The range of $8, 17, 28, 16, 30, 28, 15, 5, 19$ and $35$ is _____

A
$20$

B
$18$

C
$30$

D
$16$

Solution

The difference between the maximum and minimum data entries is called the range
So, Range = maximum number - minimum number
Range = $35 -5$
Range = $30$
Question 5
1 / -0

Find the average of $201, 204, 207, 210, 213$ .

A
$204$

B
$207$

C
$213$

D
$208$

Solution

Average of Number $=\cfrac { Sum\quad of\quad all\quad numbers }{ Total\quad number\quad of\quad number }$
$=\cfrac { 201+207+210+213+204 }{ 5 }$
$=>\cfrac { 1035 }{ 5 } =207$
Question 6
1 / -0

What is the average(arithmetic mean) of all the multiples of ten from $10$ to $190$ inclusive?

A
$90$

B
$95$

C
$100$

D
$105$

E
$110$

Solution
Question 7
1 / -0

Which year did the same number of boys and girls attend the conference?

A
1995

B
1996

C
1997

D
1998

E
None
Question 8
1 / -0

Find the arithmetic mean of the progression $2, 4, 6, 8, 10.$

A
$10$

B
$20$

C
$30$

D
$6$

Solution

Using the formula for Required arithmetic mean $=\dfrac{\text{sum of the terms}}{\text{number of terms}}$

After substituting the values we get $=\dfrac{2+4+6+8+10}{5}=\dfrac{30}{5}=6$
Question 9
1 / -0

Directions For Questions

Study the bar chart and answer the questions.

...view full instructions

The difference in the sales of cellular phones for the years $1997$ and $1999$ is?

A
$500$ units

B
$1,000$ units

C
$5,000$ units

D
$18,000$ units

Solution

The given graph shows the sale of cellular phones in the years $1997, 1998, 1999, 2000,2001$ and $2002$ .

In the year $1997$ , the sale of cellular phones is $48000$ .
In the year $1999$ , the sale of cellular phones is $30000$ .

Therefore, the difference in the sales of cellular phones for the year $1997$ and $1999$ is,
$48000-30000=18000$

Hence, the difference in the sales of cellular phones for the year $1997$ and $1999$ is $18,000$ units.
Thus, option $D$ is correct.
Question 10
1 / -0

If the average arithmetic mean of 8, 12, 15, 21, x and 11 is 17 then what is x?

A
3

B
15

C
17

D
35

E
42

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Re-Attempt Weekly Quiz Competition

Data Handling Test - 23

Result

Data Handling Test - 23

Score

-

Rank

-

SHARING IS CARING

Question 1

100100100

105105105

110110110

115115115

Solution

Question 2

222

333

444

555

Solution

Question 3

222

(2)\sqrt {(2)}(2)​

000

444

Solution

Question 4

202020

181818

303030

161616

Solution

Question 5

204204204

207207207

213213213

208208208

Solution

Question 6

909090

959595

100100100

105105105

110110110

Solution

Question 7

1995

1996

1997

1998

None

Question 8

101010

202020

303030

666

Solution

Question 9

500500500 units

1,0001,0001,000 units

5,0005,0005,000 units

18,00018,00018,000 units

Solution

Question 10

3

15

17

35

42

User

Question Analysis

My Perfomance

Score

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Rank

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$100$

$105$

$110$

$115$

$2$

$3$

$4$

$5$

$2$

$\sqrt {(2)}$

$0$

$4$

$20$

$18$

$30$

$16$

$204$

$207$

$213$

$208$

$90$

$95$

$100$

$105$

$110$

$10$

$20$

$30$

$6$

$500$ units

$1,000$ units

$5,000$ units

$18,000$ units