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Lines and Angles Test - 18

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Lines and Angles Test - 18
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  • Question 1
    1 / -0
    $$p||q,r||s$$ then p is _____.
    Solution
    Given $$p||q$$  and   $$r||s$$.
    No relation is given between line $$p$$ with $$r$$ and $$s$$
    So $$p$$ is not parallel to $$s$$
    Option $$C$$ is correct.
  • Question 2
    1 / -0
    The measure of $$\displaystyle \angle POQ$$ in the following figure is:

    Solution
    If two straight lines intersect the measures of vertically opposite angles are equal.
    Given, $$\angle SOR=110^o$$
    Therefore, $$\angle SOR=\angle POQ$$
    $$\Rightarrow \displaystyle \angle POQ=110^{\circ}$$
  • Question 3
    1 / -0
    The complementary angle of $$\displaystyle 30^{\circ}$$ is:
    Solution

    We know, two angles are complementary when they add up to $$90^o.$$

    Given, measure of one complementary angle is $$30^o.$$

    $$\Rightarrow$$ Measure of other complementary angle $$=90^o-30^o$$ $$=60^o.$$

    $$\therefore$$ Measure of a complementary angle of $$ 30^{o}=60^o$$.

    Hence, option $$A$$ is correct.

  • Question 4
    1 / -0
    If sum of two angles is $$\displaystyle { 90 }^{ o }$$. They will be:
    Solution
    By definition we know that two angles, the sum of whose measure is $$ { 90^o } $$ are called complimentary angles.
    Then, such angles are called complement of each other.

    E.g.: Let the measure of one complementary angle is $$58^o.$$

    $$\Rightarrow$$ Measure of other complementary angle $$=90^o-58^o$$ $$=32^o.$$

    $$\therefore$$ Measure of the complementary angle of $$ 58^{o}=32^o$$.

    Hence, $$ 58^{o}$$ and $$32^o$$ are complements of each other.

    That is, if the sum of two angles is $$90^o$$

    Therefore, option $$C$$ is correct.

  • Question 5
    1 / -0
    If two angles are supplementary, then their sum is
    Solution
    If two angles are supplementary , then their sum is $${ 180 ^o } $$
  • Question 6
    1 / -0
    Two angles are supplementary, if one of them is $$\displaystyle { 49 }^{ o }$$. Find the other angle?
    Solution
    Since, two angles are supplementary their sum is $$\displaystyle { 180 }^{ o }$$
    $$\displaystyle \angle 1+\angle 2={ 180 }^{ o }$$
    $$\displaystyle { 49 }^{ o }+\angle 2={ 180 }^{ o }$$ (As one of the angle is $$\displaystyle { 49 }^{ o }$$
    $$\displaystyle \angle 2={ 180 }^{ o }-{ 49 }^{ o }$$
    $$\displaystyle ={ 131 }^{ o }$$
  • Question 7
    1 / -0
    The value of $$y$$ in the given figure is _____

    Solution
    Given, $$\angle ABC=115^{\circ}$$

    $$\angle ABC$$ and $$\angle CBD$$ form linear pair.

    So,
    $$\angle ABC+\angle CBD=180^{\circ}$$
    $$\Rightarrow 115^{\circ}+y^{\circ}=180^{\circ}$$
    $$\Rightarrow y^{\circ}=180^{\circ}-115^{\circ}$$
    $$\Rightarrow y^{\circ}=65^{\circ}$$

    Hence, the value of $$y$$ is $$65$$.
  • Question 8
    1 / -0
    A pair of angles with a common vertex and common arm are called
    Solution


    A pair of angles with a common vertex and common arm are called adjacent angles.

  • Question 9
    1 / -0
    Two angles the sum of whose measure is $$90^{\circ}$$ are called ______ angles.
    Solution
    By definition we know that two angles, the sum of whose measure is $$ { 90^o } $$ are called complementary angles.
    Then, such angles are called complement of each other.

    E.g.: Let the measure of one complementary angle is $$58^o.$$

    $$\Rightarrow$$ Measure of other complementary angle $$=90^o-58^o$$ $$=32^o.$$

    $$\therefore$$ Measure of the complementary angle of $$ 58^{o}=32^o$$.

    Hence, $$ 58^{o}$$ and $$32^o$$ are complements of each other.


    Therefore, option $$B$$ is correct.

  • Question 10
    1 / -0
    Find the supplement  of the  angle
    $$148^{\circ}$$
    Solution
    We know that the supplement angle
    $$=180^0-\theta$$

    So,
    The supplement angle of $$148^0$$ will be
    $$=180^0-148^0=32^0$$ 

    Hence, this is the answer.
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