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The Triangle and Its Properties Test - 26

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The Triangle and Its Properties Test - 26
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  • Question 1
    1 / -0
    In $$\Delta PQR$$, if $$\angle P=60^{o}$$, and $$\angle Q=40^{o}$$, then the exterior angle formed by producing $$QR$$ is equal to
    Solution
    Let $$QR$$ is extended to point $$S$$.
    (Refer image)
    In triangle $$PQR$$
    $$\angle PRS=\angle P+\angle Q$$
    $$\Rightarrow \angle PRS=60^{o}+40^{o}$$
    $$\Rightarrow \angle PRS=100^{o}$$

  • Question 2
    1 / -0
    In a right-angled triangle $$ABC$$, if angle $$B = 90^o$$, then which of the following is true?
    Solution
    Hypotenuse is the longest side of triangle which is opposite to right angle.
    By pythagoras theorm,
    $$\text{(hypotenuse)}^2=\text{(side 1)}^2+\text{(side 2)}^2$$
    $$\Longrightarrow AC^2 = AB^2 + BC^2$$
    So, option $$B$$ is correct.

  • Question 3
    1 / -0
    Write the correct answer from the given four options.
    The hypotenuse of a right triangle with its legs of lengths $$3x \times 4x$$ is
    Solution
    $$(Hypotenuse)^2 = (3x)^2 + (4x)^2 = 9x^2 + 16x^2  = 25x^2$$
    $$Hypotenuse  = \sqrt{25x^2} = 5x$$
  • Question 4
    1 / -0
    The measures of $$\angle x$$ and $$\angle y$$ in figure are respectively

    Solution
    $$120^0$$ is exterior of $$\angle R$$
    $$\therefore \angle P+\angle Q=120^0$$
    $$\Rightarrow 120^{o}=x+50^{o}$$
    $$\Rightarrow x=120^{o}-50^{o}$$
    $$\Rightarrow x=70^{o}$$
    Now in $$\Delta PQR$$
    $$x+y+50^{o}=180^{o}$$
    $$\Rightarrow 70^{o}+y+50^{o}=180^{o}$$
    $$\Rightarrow y=180^{o}-70^{o}-50^{o}$$
    $$\Rightarrow y=60^{o}$$
    Therefore, $$x=60^{o}$$ and $$y=70^{o}$$.
    Hence, option $$D$$ is correct.

  • Question 5
    1 / -0
    If we join a vertex to a point on opposite side, which divides that side in the ratio $$1:1$$, then what is the special name of that line segment?
    Solution
    Median from an vertex divides the opposite sides into ratio of $$1:1$$
    So, special name of that segment is $$\text{Median}$$
    Hence, option $$A$$ is correct.
  • Question 6
    1 / -0
    How many altitudes does a triangle have?
    Solution
    $$\textbf{Step-1: Represent the altitudes of a triangle using a diagram. }$$
                     $$\text{A triangle has three altitudes. From each vertex perpendicular to the opposite side can be drawn.}$$
    $$\textbf{Hence, option - B is the correct answer.}$$

  • Question 7
    1 / -0
    Which of the following can be the length of the third side of triangle whose two sides measure $$18 cm$$ and $$14 cm $$?
    Solution
    Let $$y \,cm$$ be the third side of the triangle.
    Hence,
    $$\Rightarrow 18+14>y$$
    $$\Rightarrow 32>y$$

    $$18-14 <y$$
    $$y>4  \ and\ 32>y$$
    $$4<y<32$$

    Therefore, the third side of a triangle can be $$5 cm$$.
  • Question 8
    1 / -0
    Which of the following figures will have its altitude outside the triangle?
    Solution
    In obtuse angled triangle, two of its altitudes lie outside the triangle.
    Also, from figure it is clear that $$D$$ has its altitude outside triangle, which is an obtuse angled triangle.

    Hence, option D is correct.

  • Question 9
    1 / -0
    If one angle of triangle is equal to the sum of the other two angles then the triangle is 
    Solution

  • Question 10
    1 / -0
    In given $$\triangle ABC$$, AE, BF and CD are

    Solution

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