Comparing Quantities Test

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Comparing Quantities Test - 10

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Question 1
1 / -0

1.8% $$=$$ .......

A
1.800

B
1.8

C
0.18

D
0.018

Solution

$$1.8% $$= $$\dfrac{1.8}{100} = 0.018$$
Question 2
1 / -0

A shopkeeper sold an article offering a discount of 5% and earned a profit of 23.5%. What would have been the percentage of profit earned if no discount was offered ?

A
$$24.5\%$$

B
$$25\%$$

C
$$28.5\%$$

D
$$30\%$$

Solution

Let the M.P. of the article $$= Rs.100$$

Discount $$= 5\%$$ $$\Rightarrow S.P. = Rs.95$$

Profit $$= 23.5\%$$ $$\Rightarrow$$ C.P. = Rs.$$\displaystyle \left ( \frac{95\times 100}{123.5} \right )=Rs.\frac{95000}{1235}$$

Had there been no discount, $$S.P. = Rs100 $$

Then Profit % $$ =\cfrac{100-\dfrac{95000}{1235}}{\cfrac{95000}{1235}}\times 100$$

$$ =\cfrac{\left ( \dfrac{123500-95000}{1235} \right )}{\cfrac{95000}{1235}}\times 100$$

$$ =\cfrac{28500}{95000}\times 100=30\%$$
Question 3
1 / -0

Find the principle if $$S.I$$ is $$Rs. 31.50$$, time period is 1$$\displaystyle \frac{1}{4}$$ years and rate percent per annum is 5 $$\displaystyle \frac{1}{4}$$%.

A
$$Rs. 460$$

B
$$Rs. 430$$

C
$$Rs. 480$$

D
$$Rs. 4800$$

Solution

$$P = \displaystyle \frac{100 \times S.I}{T \times R}$$

$$= \displaystyle \frac{100 \times 31.50}{\displaystyle \frac{5}{4} \times \frac{21}{4}} = Rs.\, 480$$
Question 4
1 / -0

If C.P is Rs. 1750, S.P is Rs. 1925 then the profit percent is

A
$$9\frac{1}{10}$$

B
10

C
25

D
110

Solution

$$C. P. = Rs 1750$$
$$S.P. = Rs 1925$$
$$Profit = 1925 - 1750 = 175$$
$$Profit$$ % = $$\frac{Profit}{C.P.} \times 100$$
$$Profit$$ % = $$\frac{175}{1750} \times 100 = 10$$ %
Question 5
1 / -0

$$\frac{1}{8}$$% means

A
$$\frac{1}{8}$$

B
$$\frac{100}{8}$$

C
$$\frac{8}{100}$$

D
$$\frac{1}{800}$$

Solution

$$\frac{1}{8}$$ % = $$\frac{\frac{1}{8}}{100} = \frac{1}{800}$$
Question 6
1 / -0

A person spends $$33\frac{1}{3}$$% of his total income on food.Amount spend on food will be what part of his income

A
$$33\frac{1}{3}$$

B
$$3\frac{1}{33}$$

C
$$\frac{1}{3}$$

D
$$\frac{1}{33}$$

Solution

Let the persons income = $$I$$
He spends, $$33 \frac{1}{3}$$ % of his income = $$\frac{100}{3}$$ %
Thus, Money spend on food = $$\frac{100}{3}$$ % of I = $$\frac{\frac{100}{3}}{100}$$ of I = $$\frac{I}{3}$$

Thus, the man spends $$\frac{1}{3}$$ of his income on food.
Question 7
1 / -0

80% of a non-leap year $$= ....... $$days

A
$$288$$

B
$$256$$

C
$$292$$

D
$$270$$

Solution

A non-leap year has $$= 365$$ days
$$80\%$$ of a non-leap year $$= \dfrac{80}{100}\times 365$$
$$= 292$$ days
Question 8
1 / -0

$$\dfrac{2}{5}$$ of total students in a class have opted Maths. Find the percentage of students opting Maths

A
$$\dfrac{2}{5}\times 100$$

B
$$\dfrac{5}{2}\times 100$$

C
$$\dfrac{2}{5}\times \dfrac{1}{100}$$

D
$$\dfrac{5}{2}\times \dfrac{1}{100}$$

Solution

Percentage of students opting for math's $$= \dfrac{2}{5} \times 100$$
$$ = 40\%$$ of the students
Question 9
1 / -0

Express:

35% as fraction

A
$$\displaystyle\frac{7}{20}$$

B
$$\displaystyle\frac{7}{30}$$

C
$$\displaystyle\frac{14}{30}$$

D
$$\displaystyle\frac{7}{10}$$

Solution

$$35$$ % = $$\frac{35}{100}$$ = $$\frac{7}{20}$$
Question 10
1 / -0

A man bought a number of clips at 3 for a rupee and an equal number at 2 for a rupee At what price per dozen should he sell them to make a profit of 20%?

A
Rs 4

B
Rs 5

C
Rs 6

D
Rs 7

Solution

Let he bought 1 dozen clips of each kind.
C.P of 2 dozen=$$\frac{1}{3}\times 12+\frac{1}{2}\times 12=10 Rs$$
S.P of 2 dozen=$$120\% of 10 = Rs\dfrac{120}{100}\times 10=12 Rs$$
Hence S.P per dozen=6 Rs.

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Re-Attempt Weekly Quiz Competition

Comparing Quantities Test - 10

Result

Comparing Quantities Test - 10

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SHARING IS CARING

Question 1

1.800

1.8

0.18

0.018

Solution

Question 2

$$24.5\%$$

$$25\%$$

$$28.5\%$$

$$30\%$$

Solution

Question 3

$$Rs. 460$$

$$Rs. 430$$

$$Rs. 480$$

$$Rs. 4800$$

Solution

Question 4

$$9\frac{1}{10}$$

10

25

110

Solution

Question 5

$$\frac{1}{8}$$

$$\frac{100}{8}$$

$$\frac{8}{100}$$

$$\frac{1}{800}$$

Solution

Question 6

$$33\frac{1}{3}$$

$$3\frac{1}{33}$$

$$\frac{1}{3}$$

$$\frac{1}{33}$$

Solution

Question 7

$$288$$

$$256$$

$$292$$

$$270$$

Solution

Question 8

$$\dfrac{2}{5}\times 100$$

$$\dfrac{5}{2}\times 100$$

$$\dfrac{2}{5}\times \dfrac{1}{100}$$

$$\dfrac{5}{2}\times \dfrac{1}{100}$$

Solution

Question 9

$$\displaystyle\frac{7}{20}$$

$$\displaystyle\frac{7}{30}$$

$$\displaystyle\frac{14}{30}$$

$$\displaystyle\frac{7}{10}$$

Solution

Question 10

Rs 4

Rs 5

Rs 6

Rs 7

Solution

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