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Comparing Quantities Test - 11

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Comparing Quantities Test - 11
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  • Question 1
    1 / -0
    A, B and C enter into partnership A invests 3 times as much as B invests and B invests two-third of what C invests At the end of the year the profit earned is Rs 6600 What is the share of B?
    Solution
    Let C invest x Rs.
    Then according to the question B invest=$$\frac{2x}{3}   Rs.$$
    A invest=$$\frac{2x}{3}\times 3=2x    Rs.$$
    Then $$x+\frac{2x}{3}+2x=6600$$
    $$\Rightarrow 3x+2x+6x=19800$$
    $$\Rightarrow 11x=19800$$
    $$\Rightarrow x=1800$$
    Then B's share=$$\frac{2}{3}\times 1800=1200  Rs.$$
  • Question 2
    1 / -0
    If the selling price of 50 articles is equal to the cost price of 40 articles then the loss and gain percent is 
    Solution
    Let C.P of one article =1 Rs.
    Then C.P of 40 article=40 Rs.
    According to the question
    S.P of 50 article =C.P of 40 article=40 Rs.
    We assume that C.P of one article =1Rs.
    then C.P of 50 article=50 Rs.
    Loss=50-40=10 Rs.
    Loss %=$$\frac{10}{50}\times 100=20$$%
  • Question 3
    1 / -0
    Mechanic Raj purchased a motorcycle for Rs. 20,000 and sold it at 5% loss. Its selling price is 
    Solution
    $$Cost = Rs 20000$$
    $$Loss = 5$$%
    $$Loss = \frac{5 \times 20000}{100}$$
    $$SP = CP - Loss$$
    $$SP = 20000 -  \frac{5 \times 20000}{100}= Rs  \frac{95 \times 20000}{100}$$
  • Question 4
    1 / -0
    Equivalent of $$\displaystyle \frac { 6 }{ 20 } $$ is:
    Solution
    Given fraction is $$\dfrac{6}{20}$$
    Equivalent percentage is
    $$=\dfrac{6}{20} \times 100$$ $$=30\%$$
  • Question 5
    1 / -0
    Simple interest on Rs.2000 for 4 years is Rs.400. Percent rate of interest is
    Solution
    Principal = Rs 2000
    Time = 4 years
    Interest = Rs 400
    Let Rate of Interest= $$R$$
    Now, $$Interest = \frac{Principal \times Rate \times Time}{100}$$
    $$400 = \frac{2000\times R\times 4}{100}$$
    $$R = \frac{400 \times 100}{2000 \times 4}$$
  • Question 6
    1 / -0
    A bookseller sold a book for Rs.100 and thereby gains Rs.20. Find his gain percent.
    Solution
    Selling Price = Rs 100
    Profit = Rs 20
    Cost Price = SP - Profit = $$100 - 20= 80$$
    Thus, Profit % = $$\frac{Profit}{CP} \times 100 = \frac{20}{80} \times 100 = 25$$ %
  • Question 7
    1 / -0
    A and B invest Rs 200 and Rs 300 respectively in a business for a period for three years and two years respectively. Then the profit will be divided into the ratio of
    Solution
    $$Ratio\quad in\quad which\quad they\quad should\quad share\quad their\quad profits=Raio\quad of\quad investments\times \quad Time\quad period$$
    $$=\frac { 200\times 3 }{ 300\times 2 } =\frac { 600 }{ 600 } =1:1$$
  • Question 8
    1 / -0
    Jayant sold two books at Rs 14 each. On one he gains 20% and on the other loses 20%. Then he made
    Solution
    on the first article Jayant gains 20%
    so if CP is 100, selling price will be 120 and profit will be Rs20
    when selling price is 120 profit is 20
    when selling price is 14 profit is $$=\frac { 20 }{ 120 } \times 14=2.33$$
    cost price =selling price-profit
                      =14-2.33
                       =Rs11.67
    on second article he losses 20%
    so if CP is 100, selling price will be 80 and Loss will be Rs20
    when selling price is 80 loss is 20
    when selling price is 14 loss is $$=\frac { 20 }{ 80 } \times 14=3.5$$
    cost price is =selling price+loss
                          =14+3.5
                            =17.5
    total selling price=14+14=Rs28
    total cost price=17.5+11.67=Rs29.17
    net loss=29.17-28=Rs1.17
    loss percantage=$$=\frac { 1.17 }{ 29.17 } \times 100=4$$
    he makes a loss of 4%
  • Question 9
    1 / -0
    If a radio is sold at Rs 972, then profit is 8%. If it is sold at Rs 872, then there is a loss of
    Solution
    Given,
    Profit percent $$=8\%$$
    Therefore:
     If selling price is $$108$$ cost price will be  $$100$$.
     If selling price is $$1$$ cost price will be $$\dfrac { 100 }{ 108 } $$
     If selling price is $$972$$ cost price $$=\dfrac { 100 }{ 108 } \times 972=900$$

    If the radio is sold for $$872$$ there will be a loss of$$=\left( 872-900 \right) =Rs.28$$
  • Question 10
    1 / -0
    If the cost of a pen is $$Rs.\ 12.60$$ and the gain was $$10\%$$ of the marked price, then the marked price of the pen was
    Solution
    Let the marked price be $$Rs.\ 100.$$

    It is given that $$10\%$$ gain is made on the marked price.
    So,
    $$Gain=100\times \dfrac { 10 }{ 100 } $$
               $$=Rs.\ 10$$

    Cost price will be $$100-10=Rs.\ 90.$$

    When $$Rs.\ 90$$ is the cost price marked price is $$Rs.\ 100.$$
    So, when $$Rs.\ 12.60$$ is the cost price marked price will be $$\dfrac { 100 }{ 90 } \times 12.60=Rs.\ 14.$$

    Hence, option $$B$$ is correct.
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