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Comparing Quantities Test - 19

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Comparing Quantities Test - 19
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  • Question 1
    1 / -0
    Choose the correct answer from the alternatives given :
    If the cost price and selling price of an article are in the ratio 10: 11 then the percentage of profit is
  • Question 2
    1 / -0
    Mr. Z buys an article for Rs. 70/- and sells it at a loss of 20%. Then the selling price will be
    Solution
    Cost price of the article$$=Rs.\ 70 /-$$.
    Loss$$=20\%\ $$
    $$\therefore  Loss  =  70 \times \dfrac{20}{100}=Rs.\ 14$$
    $$ \therefore $$  Selling Price $$ =Rs.\ 70-14 $$
    $$=Rs.\ 56$$
  • Question 3
    1 / -0
    If selling price of $$10$$ articles is equal to cost price of $$11$$ articles, then gain is:
    Solution
    Let CP of $$1$$ article =Rs. $$1$$
    CP of $$11$$ article =Rs. $$11$$
    CP of $$10$$ article =Rs. $$10$$
    SP of $$10$$ article =Rs. $$11$$
    Profit % $$=\cfrac { 11-10 }{ 10 } \times 100$$
    $$=10$$%
  • Question 4
    1 / -0
    If $$P=5,000$$, $$T=1$$, $$S.I.=$$Rs. $$300$$, R will be.
    Solution
    Given
    $$I = Rs\ 300$$ 
    $$P= Rs\ 5000$$
    $$T= 1$$ 
    Apply the formula for simple interest
    $$ I = \cfrac{P\times R \times T }{100}$$
    $$ 300 = \cfrac{5000 \times 1 \times R }{100 }$$
    $$ R= \cfrac{300 }{50} = 6$$%
    Hence option (C) is correct option
  • Question 5
    1 / -0
    Jimmy's balance in a bank on 1st November was Rs.$$58709$$. He withdrew RS.$$13090$$ and Rs.$$16518$$ from his account and deposits Rs.$$1680$$ in his account in that month. What was the balance at the end of the month?
    Solution
    Amount of money in the account on 1st November$$=Rs.58709$$
    Total amount of money withdrawn
    $$=Rs.(13090+16518)=Rs.29608$$
    Amount of money deposited$$=Rs.1680$$
    Balance left at the end of the month
    $$=Rs.(58709-29608+1680)$$
    $$=Rs.(60389-29608)=Rs.30781$$
  • Question 6
    1 / -0
    A dealer marked his goods $$20$$% above the cost price and allows a discount of $$10$$%. Then, the gain percent is
    Solution
    Let CP be $$=100$$
    MP $$20$$% above CP$$=120$$
    After allowing Discount of $$10$$%
    $$SP=\cfrac { 90 }{ 100 } \times 120=108$$
    Gain $$=8$$%
  • Question 7
    1 / -0
    The ratio of boys to girls in Mona's class is 3 : 4 .Which of the following ratio is equivalent to 3 : 4 ?
    Solution
    (B) $$6 : 9 = 2\times3 : 3\times3$$ 
                   $$= 2:3$$
    (C) $$16:18 = 8\times2:9\times2$$ 
                   $$= 8:9$$
    (D) $$18:24 = 3\times6:4\times6$$
                   $$ = 3:4$$

    Hence, the answer is $${18}:{24}$$.
  • Question 8
    1 / -0
    How many of the following transactions are profitable?
    i) Two tables bought for Rs.30,500 and sold each at Rs.15,500.
    ii) Three fans bought for Rs.12,500 and sold each at Rs.4,300.
    iii) Three shirts bought for Rs.450 each and sold at Rs.1,430.
    iv) Two computers bought for Rs.15,200 each and sold at Rs.38,500.
    v) A pair of denims bought for Rs.1,000 and sold at Rs.850.
    vi) Two mobiles bought for Rs.49,000 and sold each at Rs.25,300.
    Solution
    Profit is there when selling price is greater then cost price.
    $$(1)$$  $$CP=Rs.30,500\\SP=15,500\times 2=31,500\\SP>CP$$
    $$\implies$$Profit

    $$(2)$$  $$CP=Rs.12,500\\SP=4,300\times 3=12,900\\SP>CP$$
    $$\implies$$Profit


    $$(3)$$  $$CP=450\times 3=Rs.1,350\\SP=1,430\\SP>CP$$
    $$\implies$$Profit


    $$(4)$$  $$CP=15,200\times 2=Rs.30,000\\SP=38,500\\SP>CP$$
    $$\implies$$Profit

    $$(5)$$  $$CP=Rs.1,000\\SP=850\\SP<CP$$
    $$\implies$$Loss

     Hence ,there are total $$5$$ profitable transactions.


  • Question 9
    1 / -0
    If cost price of an article is Rs. 10 and its selling price is Rs. 15, then profit % is:
    Solution
    Cost price $$= Rs. 10$$
    Selling price $$= Rs. 15$$

    Profit = Selling price - Cost price $$=  15-10= 5Rs.$$

    Hence, profit% $$ = \dfrac{profit}{CP}\times 100$$ 

                             $$\Rightarrow \dfrac{15-10}{10}\times100$$  $$=\dfrac{5}{10}\times100$$ $$=50\%$$

    Option D is correct.
  • Question 10
    1 / -0
    The period of time for which the interest is calculated is called the.
    Solution
    The period of time for which the interest is calculated is called conversion period.
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