Comparing Quantities Test

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Comparing Quantities Test - 20

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Weekly Quiz Competition

Question 1
1 / -0

$$\dfrac{3}{5}$$ as a percent is

A
$$30\%$$

B
$$40\%$$

C
$$45\%$$

D
$$60\%$$

Solution

$$\cfrac{3}{5}$$ as a percent is$$=\cfrac{3}{5}\times 100=60\%$$
Question 2
1 / -0

Rahul purchased a scooter at $$\left(\dfrac{13}{15}\right)^{th}$$ of its selling price and sold it at $$12%$$ more than its selling price. His gain is _____.

A
$$20%$$

B
$$29\dfrac{3}{13}%$$

C
$$30%$$

D
$$38\dfrac{1}{13}%$$

Solution

Let selling price be x rs

Then cost price =$$\dfrac{13}{15}$$$$\times x$$

Receipt $$=\left( 100+12 \right)%$$ of $$x$$

$$=112%$$,of$$,x$$

$$ =\dfrac{112\times x}{25} $$

$$ =\dfrac{28}{25}$$ $$\times x$$

Hence ,Rahul gain

=$$\dfrac{28x}{25}$$-$$\dfrac{13x}{15} $$

$$ =\dfrac{84x-65x}{75} $$

$$ =\dfrac{19x}{75} $$

Gain in percent =$$\dfrac{19x}{75}\times \dfrac{15}{13x}\times 100$$
=$$\dfrac{380}{13}%=29\dfrac{3}{13}%$$
=29$$\dfrac{3}{13}%$$
Question 3
1 / -0

If the cost of a dozen soaps is $$Rs\ 285.60$$, what will be the cost of $$15$$ such soaps?

A
Rs. $$827$$

B
Rs. $$772$$

C
Rs. $$676$$

D
Rs. $$357$$

Solution

Cost of $$12$$ soaps $$=285.60$$

Cost of one soap $$=\dfrac{285.60}{12}$$

Cost of $$15$$ soaps $$=\dfrac{285.60}{12}\times{15}=Rs.357$$
Question 4
1 / -0

A housewife saved Rs. $$250$$ in buying a dress on sale, If she spent Rs. $$25$$ for the dress, she saved about:

A
$$80\%$$

B
$$90.90\%$$

C
$$89\%$$

D
$$11\%$$

E
$$12\%$$

Solution

The housewife saved $$250$$ Rs and she spent $$25$$ Rs on the dress.

$$\Rightarrow $$Actual cost $$=275$$

Saved percentage =$$\dfrac {250}{275}×100$$

$$\therefore $$saved percentage $$=90\%$$
Question 5
1 / -0

A dishonest dealer uses a scale of $$'90$$ cm instead of a metre scale and claims to sell at cost price. His profit is :

A
$$11.11 \%$$

B
$$10 \%$$

C
$$12 \%$$

D
None of these

Solution

Dealer uses a scale $$=90\ cm$$
Original scale $$=100\ cm$$

Profit in % $$=\dfrac{100}{90}\times 100$$

$$=11.11$$%
Question 6
1 / -0

A shopkeeper earns $$15$$% profit on a shirt even after allowing $$31$$% discount on the marked price.If the market price $$1250$$, then the cost price of the shirt is

A
$$870$$

B
$$ 800$$

C
$$750$$

D
$$690$$

Solution

According to the problem the S.P and C.P is
$$\begin{array}{l} Discount=\dfrac { { 31 } }{ { 100 } } \times 1250 \\ =387.5 \\ S.P=1250-387.5 \\ S.P=862.5 \\ C.P=\dfrac { { 100 } }{ { 100+15 } } \times 862.5 \\ =\dfrac { { 100 } }{ { 115 } } \times 862.5 \\ =\dfrac { { 17250 } }{ { 23 } } \\ =750 \end{array}$$
Therefore, the cost price is Rs $$750$$.
Question 7
1 / -0

A shopkeeper sells a sweater at a loss of $$5\%$$. If he had sold it for Rs. $$260$$ more, he would have made a profit of $$15\%$$. Calculate the purchase price of the sweater.

A
Rs $$1900$$

B
Rs $$1400$$

C
Rs $$1000$$

D
Rs $$1300$$

Solution

case1:Let CP be $$x$$
Loss=5%
$$S{P_1} = x - 5\% of\,x$$
$$S{P_1} = 95\% \,of\,x = \dfrac{{95}}{{100}}x$$

Case2: CP$$=x$$,
$${P_2} = 15\% $$
$$S{P_2} = x + 15\% of\,x = \dfrac{{115}}{{100}}x$$

Difference in SP is given $$260$$
Thus,
\begin{array}{l} S{ P_{ 2 } }-S{ P_{ 1 } }=260 \\ \dfrac { { 115x-95x } }{ { 100 } } =260 \\ \Rightarrow 20x=260\times 100 \\ \Rightarrow x=\dfrac { { 26000 } }{ { 20 } } \\ \Rightarrow x=1300 \end{array}
Thus purchase price is $$1300$$ Rs.
Question 8
1 / -0

What percent is $$150\ \text{ml}$$ of $$3.5\ \text{litres}$$?

A
$$3\cfrac{2}{7}$$%

B
$$4\cfrac{2}{7}$$%

C
$$5\cfrac{2}{7}$$%

D
$$6\cfrac{2}{7}$$%

Solution

Convert both the figures into same units:
$$3.5\ \text{L} =3.5\times 1000\ \text{mL}= 3500\ \text{mL}$$
Required percentage $$=\dfrac{150}{3500}\times 100\ \%=\dfrac{30}{7}\ \% = 4\dfrac{2}{7}\ \%$$
Question 9
1 / -0

Write as percentage $$4\dfrac {4}{20}$$

A
$$84\%$$

B
$$420\%$$

C
$$8.4\%$$

D
$$42\%$$

Solution

$$4\dfrac{4}{20}$$
$$\Rightarrow \dfrac{84}{20}\times 100\Rightarrow 420\%$$
Question 10
1 / -0

$$16\frac{2}{3}\% $$ of $$600$$gm $$ - 33\frac{1}{3}\% $$ of $$180$$gm

A
$$20$$ gm

B
$$30$$ gm

C
$$40$$ gm

D
$$60$$ gm

Solution

$$16 \dfrac{2}{3}\%$$ of $$600\ gm-33 \dfrac{1}{3} \%$$ of $$180\ gm$$
$$\Rightarrow \left[ \dfrac{50}{3} \times \dfrac{1}{100} (600)- \left( \dfrac{100}{3} \times \dfrac{1}{100} \right) (180) \right] gm$$
$$\Rightarrow \left[ \dfrac{600}{6}- \dfrac{180}{3} \right]\ gm$$
$$\Rightarrow (100-60)\ gm$$
$$\Rightarrow 40\ gm$$
$$\therefore [16 2/3 \% \ of\ 600\ gm-33 1/3 \% \ of\ 180\ gm]=40\ gm$$

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Re-Attempt Weekly Quiz Competition

Comparing Quantities Test - 20

Result

Comparing Quantities Test - 20

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SHARING IS CARING

Question 1

$$30\%$$

$$40\%$$

$$45\%$$

$$60\%$$

Solution

Question 2

$$20%$$

$$29\dfrac{3}{13}%$$

$$30%$$

$$38\dfrac{1}{13}%$$

Solution

Question 3

Rs. $$827$$

Rs. $$772$$

Rs. $$676$$

Rs. $$357$$

Solution

Question 4

$$80\%$$

$$90.90\%$$

$$89\%$$

$$11\%$$

$$12\%$$

Solution

Question 5

$$11.11 \%$$

$$10 \%$$

$$12 \%$$

None of these

Solution

Question 6

$$870$$

$$ 800$$

$$750$$

$$690$$

Solution

Question 7

Rs $$1900$$

Rs $$1400$$

Rs $$1000$$

Rs $$1300$$

Solution

Question 8

$$3\cfrac{2}{7}$$%

$$4\cfrac{2}{7}$$%

$$5\cfrac{2}{7}$$%

$$6\cfrac{2}{7}$$%

Solution

Question 9

$$84\%$$

$$420\%$$

$$8.4\%$$

$$42\%$$

Solution

Question 10

$$20$$ gm

$$30$$ gm

$$40$$ gm

$$60$$ gm

Solution

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