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Comparing Quantities Test - 23

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Comparing Quantities Test - 23
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  • Question 1
    1 / -0
    Rajan borrowed Rs. 50,000 from Rakesh at simple interest. After 3 years,  Rakesh got Rs. 3000 more  than what he had given to   Rajan. What was the rate of  interest per annum?
    Solution
    $$\Rightarrow$$   Here, we have $$P=Rs.50,000,\, T=3\, years$$ and $$S.I.=Rs.3000$$
    $$\Rightarrow$$  $$Simple\, Interest=\dfrac{P\times R\times T}{100}$$

    $$\Rightarrow$$  $$3000=\dfrac{50000\times R\times 3}{100}$$

    $$\Rightarrow$$  $$R=\dfrac{3000\times 100}{50000\times 3}$$

    $$\therefore$$    $$R=2\%$$
  • Question 2
    1 / -0
    The manufacturer A of a  certain item sells it to a wholesaler at a profit of 20%  on his manufacturing cost. The wholesaler sells it to a retailer at a profit of 25% and the retailer sells it to a consumer at a profit of 20%. The price paid by the consumer over and above manufacturing cost will be
    Solution
    Let the manufacturing cost be Rs. $$x$$. 
    Then the wholesaler's cost price $$= x+\cfrac{20}{100}x = Rs. \cfrac{6x}{5}$$
    Retailer's cost price $$= \cfrac{6x}{5}+\cfrac{25}{100}.\cfrac{6x}{5} = Rs. \cfrac{3x}{2}$$
    Finally, consumer's purchasing price
    $$= \cfrac{3x}{2}+\cfrac{20}{100}\times \cfrac{3x}{2} = Rs. \cfrac{9x}{5}$$
    Thus, on the manufacturing cost of Rs. $$x$$, the consumer pays $$(\cfrac{9x}{5}-x) = Rs. \cfrac{4x}{5}$$ over and above.
    $$\therefore$$ % price paid by consumer over and above manufacturing cost $$= \cfrac{4x}{5}\times\cfrac{1}{x} \times 100 = 80$$.
  • Question 3
    1 / -0
    A and B invest Rs. 200 and Rs. 300, respectively, in a business for a period of three years and two years, respectively. Then the profit will be divided into the ratio of
    Solution
    Interest earned $$\propto$$ Amount invested $$\times$$ Time

    $$\therefore$$ Profit of A $$:$$ Profit of B $$= 200\times 3 : 300 \times 2$$
                                             $$= 1:1$$
  • Question 4
    1 / -0
    A shopkeeper purchases 11 pens for Rs. 10 and sells them at the rate of Rs. 11, then the profit is
  • Question 5
    1 / -0
    If a radio is sold at Rs. $$972$$, then profit is $$8\%$$. If it is sold at Rs. $$872$$, then there is a loss of
    Solution
    Let the cost price of the radio is $$Rs. x$$.
    Condition I:-
    Selling price of radio $$= Rs. 972$$
    Profit $$\% = 8 \%$$
    Therefore,
    $$972 - x = \cfrac{8}{100} x$$
    $$\Rightarrow \cfrac{2}{25}x + x = 972$$
    $$\Rightarrow \cfrac{2x + 25x}{25} = 972$$
    $$\Rightarrow x = \cfrac{972}{27} \times {25}$$
    $$\Rightarrow x = 900$$
    Hence the cost price of radio is $$Rs. 900$$
    Condition II:-
    Selling price of radio $$= Rs. 872$$
    Cost price of radio $$= Rs. 900 \quad \left( \text{Given} \right)$$
    Therefore,
    Loss $$=$$ Cost price $$-$$ Selling price
    $$\therefore$$ Loss $$= 900 - 872 = Rs. 28$$
    Hence when the radio is sold at $$Rs. 872$$, then there is a loss of $$Rs. 28$$.
  • Question 6
    1 / -0
    A shopkeeper mixes 80 kg sugar worth of Rs. 6.75 per kg with 120 kg of sugar worth of Rs. 8 per kg. He earns a profit of 20% by selling the mixture. He sells it at the rate.
    Solution
    Total cost $$=80\times 6.75+120\times 8=Rs. 1500$$
    Selling price $$=1500\times \dfrac {120}{100}=Rs. 1800$$
    S.P. per kg $$=\dfrac {1800}{200}=Rs.9$$
  • Question 7
    1 / -0
    If the selling price of $$16$$ items is the same as the cost price of $$20$$ items, then there is a
    Solution
    Let SP of $$1$$ item is equal to $$Rs.\;1.$$ Then, SP of $$16$$ items is equal to $$Rs.\;16.$$

    We are given  that cost price of $$20$$ items is equal to $$Rs.\;16.$$
    Then, C.P. of $$1$$ item will be,
    $$\dfrac{16}{20}=Rs.\;0.8$$

    So, profit on each item is,
    $$SP-CP=1-0.8$$
                       $$=Rs.\;0.2$$

    $$\begin{aligned}{}\text{Gain percentage} &= \frac{{Gain}}{{CP}} \times 100\\ &= \frac{{0.2}}{{0.8}} \times 100\\ &= 25\% \end{aligned}$$
  • Question 8
    1 / -0
    A started business with Rs. 4,500 and B joined afterward with Rs. 3,000. If the profits at the end of one year were divided in the ratio 2 : 1, respectively, then B would have joined A for business after
    Solution
    A's 1 month's investment $$= Rs. (4500\times 12)$$
    $$= Rs. 54,000$$
    Let B joins after $$x$$ months.
    $$\therefore$$ B's 1 month's investment $$= Rs.3,000 (12 -x)$$
    By hypothesis
    $$54,000 : 3,000 (12 -x) = 2 : 1$$
    or $$\cfrac{18}{12-x} = 2$$
    or $$18 = 24-2x$$
    or $$2x = 6$$
    $$\therefore x = 3$$ months
  • Question 9
    1 / -0
    A certain sum of money lent out at S.I. amounts to Rs. 6900 in 3 years and Rs. 7500 in 5 years. The sum lent is
    Solution
    S.I. for 2 years $$= (7500 - 6900) = Rs. 600$$
    S.I. for 3 years $$= Rs. (\cfrac{600}{2}\times 3)$$
    $$= Rs. 900$$
    $$\therefore$$ Principal $$= Rs. (6900 - 900)$$
    $$= Rs. 6000$$
  • Question 10
    1 / -0
    A shopkeeper buys $$x$$ kg sugar for Rs. $$y$$ and sells it at Rs. $$z$$ per kg. Then expression for his profit can be represented by:
    Solution
    Amount he sells $$x$$ kg of sugar = Rs. $$z$$ per kg.
    $$\therefore S.P = Rs. zx$$ and $$C.P = Rs. y$$
    $$\therefore Profit = zx - y $$
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