Self Studies

Comparing Quantities Test - 28

Result Self Studies

Comparing Quantities Test - 28
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0
    Satyanarayana buys a watch for Rs. 1125 and sells it for Rs. 1250. The profit percentage was
    Solution
    Given: Cost price of a watch $$=Rs.1125$$

    Selling price $$=Rs. 1250$$

    Since Selling price > Cost price

    $$\therefore$$ Profit = Selling price $$-$$ Cost price

    $$\Rightarrow$$ Profit $$= 1250 - 1125 = Rs.125$$

    Now, Profit percentage $$= \dfrac{\mathrm{profit}}{\mathrm{Cost\ Price}}\times 100 $$

                                            $$= \dfrac{125\times 100}{1125} $$

                                            $$= 11\dfrac{1}{9}\%$$
  • Question 2
    1 / -0
    If 3 articles are sold for the cost price of4, then what is the profit percentage?
    Solution
    Let the C.P. of 1 article $$= Rs. 1$$.
     Then, S.P. of 3 articles = C.P. of 4 articles $$=Rs. 4$$
    C.P. of 3 articles $$=Rs. 3$$
    Profit $$= Rs. 4 - Rs. 3 =Rs. 1$$
    Profit % $$=\frac {1}{3}\times 100=33\frac {1}{3}$$%
  • Question 3
    1 / -0
    The marked price of a pen is Rs. $$60$$.After allowing a discount of $$10 \%$$, the merchant makes a profit of $$20 \%$$. What is the cost price of the pen?
    Solution
    Let the cost price of a pen Rs. $$100$$
    The marchant make profit $$20\%$$, then selling price $$=$$ Rs. $$100+20=120$$
    Marked price Rs. $$60$$. Allowing discount $$10\%$$ then selling price $$=$$ $$\dfrac{60\times 90}{100}=54$$ Rs
    So, cost price $$=$$ $$\dfrac{54\times 100}{120}=$$ Rs. $$45$$
  • Question 4
    1 / -0
    A machine is sold at a profit of $$10\%$$. Had it been sold for Rs. $$40$$ less, there would have been a loss of $$10\%$$ . What was the cost price?
    Solution
    Let the cost price, C.P. be Rs. $$x$$
    Profit $$= 10\%$$
    Hence, S.P. $$= 1.1(x) =$$ Rs. $$ 1.1x$$
    If a loss has been incurred, then the selling price of the machine would be Rs. $$0.9x$$.
    Difference in selling prices $$= 40$$
    $$1.1x - 0.9x = 40$$
    $$0.2x = 40$$ or $$x = 200$$
    The cost price of the machine is Rs. $$ 200$$.
  • Question 5
    1 / -0
    A owned an, article worth Rs. $$10, 000$$. He sold it to $$B$$ at a profit of $$10\%$$ based on the worth of the article. $$B$$ sold the article back to $$A$$ at a loss of $$10\%$$. How much did $$A$$ make in these transactions?
    Solution
    C.P of the article for $$A$$ $$=$$ Rs. $$10,000$$
    Profit $$=10\%$$
    Selling price of the article by $$A$$ to $$B$$ $$=$$ Rs. $$\dfrac {110}{100}\times 10000=$$ Rs. $$11000$$
    C.P of the  article for $$B$$ $$=$$ Rs. $$11000$$
    Loss $$=10\%$$
    Selling price of the article by $$B$$ to $$A$$ $$=$$ Rs. $$\dfrac {90}{100}\times 11000=$$ Rs. $$ 9900$$
    $$\therefore$$ Profit earned by $$A$$ $$=$$ Rs. $$ (11000-9000)=$$ Rs. $$1100$$.
  • Question 6
    1 / -0
    If Ashok makes a profit  of $$25$$% on the selling price, what will be his profit on C.P.?
    Solution

    Let Selling price be Rs. $$x$$
    $$\therefore$$ Profit $$=25$$ $$\%$$ of $$x=\dfrac {x}{4}$$
    $$\Rightarrow$$ C.P. $$=x-\dfrac {x}{4}=\dfrac {3x}{4}$$
    Profit per cent on C.P. $$=\left (\dfrac {x}{4}\div \dfrac {3x}{4}\right )\times 100$$
    $$=\dfrac {x}{4}\times \dfrac {4}{3x}\times 100$$

    $$=33\dfrac {1}{3}$$ $$\%$$

  • Question 7
    1 / -0
    A merchant has $$1000$$ kg of sugar, part of which he sells at $$8\%$$ profit and the rest at $$18\%$$ profit. He gains $$14\%$$ on the whole. The quantity of sugar sold at $$18\%$$ profit is
    Solution
    Let the C.P. of sugar be Rs. $$x$$ per kg.
    Then, C.P. $$=$$ Rs. 1$$000 x$$
    Let the sugar sold at $$8\%$$ gain by $$y$$ kg.
    Then, sugar sold at $$18\%$$ gain $$= (1000 - y)$$ kg
    $$\therefore \left (\dfrac {108}{100}\times xy\right )+\left [\dfrac {118}{100}\times x(1000-y)\right ]=\dfrac {114}{100}\times 1000x$$
    $$\Rightarrow \dfrac {108y}{100}+1180-\dfrac {118y}{100}=1140$$
    $$\Rightarrow \dfrac {10y}{100}=40$$
    $$\Rightarrow y=400$$
    $$\therefore$$ Quantity sold at 18% gain $$=(1000-400)$$ kg
    $$=600$$ kg.
  • Question 8
    1 / -0
    Ram mixes $$15$$ kg of sugar purchased with the rate, off Rs. $$8.00$$ per kg with $$25$$ kg of sugar purchased at the rate of Rs. $$10.00$$ per kg. At what rate per kg should Ram sell the mixture to get a profit of $$3$$ per kg?
    Solution
    C.P. of $$40$$ kg of sugar $$=$$ Rs. $$ (15 \times 8 + 25\times 10) =$$ Rs. $$ 120 + $$ Rs. $$ 250 =$$ Rs. $$ 370$$
    $$\therefore$$ C.P. of $$1$$ kg of sugar $$=$$ Rs. $$ \dfrac {370}{40}=$$ Rs. $$ 9.25$$
    $$\therefore$$ S.P. of $$1$$ kg of sugar $$=$$ Rs. $$ 9.25+$$ Rs. $$ 3=$$ Rs. $$ 12.25$$
  • Question 9
    1 / -0
    A shopkeeper sells an article at a loss of $$12\dfrac {1}{2}\%$$, Had he sold it for Rs. $$51.80$$ more than he would have earned a profit of $$6\%$$. The cost price of the article is
    Solution
    Let the C.P. of the article be Rs. $$x$$
    According to the question, we have
    S.P. at $$6\%$$ profit $$-$$ S.P. at $$12\dfrac {1}{2}\%$$ loss $$=$$ Rs. $$51.80$$
    $$\Rightarrow \dfrac {x\times (100+6)}{100}-\dfrac {x\times (100-12.5)}{100}=51.80$$
    $$\Rightarrow \dfrac {106x}{100}-\dfrac {87.5x}{100}=51.80$$
    $$\Rightarrow \dfrac {18.5x}{100}=51.80 \Rightarrow x=\dfrac {51.80\times 100}{18.5}=280$$
  • Question 10
    1 / -0
    Mohan lent some amount of money at $$9\%$$ simple interest and an equal amount of money at $$10\%$$ simple interest each for $$2$$ years. If his total interest was Rs. $$760$$, what amount was lent in each case?
    Solution
    Let the amount lent in each case be Rs. $$x$$ 
    $$\Rightarrow \dfrac{x\times9\times2}{100}+\dfrac{x\times10\times2}{100}=760$$
    $$\Rightarrow \dfrac{18x}{100}+\dfrac{20x}{100}=760$$
    $$\Rightarrow\;38x=76000$$
    $$\Rightarrow\;x=2000$$
Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now