Motion and Time Test

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Motion and Time Test - 9

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Weekly Quiz Competition

Question 1
1 / -0

Unit of Time is:

A
Metre

B
Kilometre

C
Second

D
None of these

Solution

Unit of time is second.
While metre and kilometre are units of length.
Question 2
1 / -0

A dancer demonstrating dance steps along a straight line. The position-time graph is given below.
Find the average velocity of the dancer during the time interval between t $$=$$ 4.5 s to t $$=$$ 9 s

A
$$1 m s^{-1}$$

B
$$-1.33 m s^{-1}$$

C
$$2.75 m s^{-1}$$

D
$$-0.89 m s^{-1}$$

Solution

Displacement = final position - initial position
From graph final position is zero at $$9\ s$$.
From graph initial position is $$4\ m$$ at $$4.5\ s$$.
Here, displacement $$=-4\ m$$
Time taken,
$$t=9-4.5$$
$$\Rightarrow t = 4.5\ s$$
Average velocity$$(V_{avg})$$
$$V_{avg} \displaystyle = \dfrac{displacement}{time}$$
$$\Rightarrow V_{avg}= \displaystyle \dfrac{-4}{4.5} $$
$$ \Rightarrow V_{avg} = -0.89 m s^{-1}$$
Question 3
1 / -0

A dancer demonstrating dance steps along a straight line. The displacement time graph is given.
Find the average speed for the dance step depicted by CD.

A
$$1 \ m s^{-1}$$

B
$$2 \ m s^{-1}$$

C
$$2.75 \ m s^{-1}$$

D
$$0.89 \ m s^{-1}$$

Solution

Average speed is defined as the ratio of the distance covered to the total time taken .

Average speed $$s_{av} = \dfrac{ Distance \ covered}{ time \ taken}$$

For step CD
Initial position is $$4$$, final position is $$0$$, hence distance covered $$=4 \ m$$
Total time is $$6-4 = 2 \ sec$$
So average speed is $$s = \dfrac{4}{2}=2\ m/s$$
So option $$B$$ is correct.
Question 4
1 / -0

A dancer demonstrating dance steps along a straight line. The position time graph is given. Find the average velocity for the dance step depicted by AB.

A
$$1 m s^{-1}$$

B
$$1.33 m s^{-1}$$

C
$$2.75 m s^{-1}$$

D
$$0 m s^{-1}$$

Solution

For the dance step depicted by AB :
Path length $$=$$ 0;
Displacement $$=$$ 0
Time taken, t $$=$$ 1 s
Average velocity $$= \displaystyle \dfrac{displacement}{time \ taken}$$
$$ \displaystyle = \dfrac{0}{1} =0$$
Question 5
1 / -0

Which of the following is not in uniform motion?

A
A bullet travelling with a constant speed in a straight line.

B
A swinging pendulum

C
The earth rotating about its axis

D
Both B & C

Solution

$$A-$$As the bullet has a constant speed and is travelling in a straight line, so it will have a constant velocity and hence it is in uniform motion
$$B-$$A swinging pendulum is under the action of gravitational force and is also changing its direction, hence it is not in uniform motion.
$$C-$$The rotation of the earth in non accelerated motion and hence it is a uniform motion

Hence, correct answer is option $$B$$
Question 6
1 / -0

Which of the following relations is correct?

A
Speed = $$\frac { 1 }{ Distance\times Time } $$

B
Speed = $$\frac { Time }{ Distance } $$

C
Speed = $$\frac { Distance }{ Time } $$

D
Speed = Distance $$\times $$ Time

Solution

Speed is defined as the distance travelled by an object per unit time.
$$Speed = \dfrac{Distance}{time}$$
Question 7
1 / -0

Which of the following is NOT matched correctly?

A
Speedometer: Speed

B
Odometer : Odour

C
Anemometer : Wind speed

D
Stopwatch : Time

Solution

Odometer indicates the distance travelled by the vehicle.
Question 8
1 / -0

Fill in the blank:

$$1$$ mean solar day = _____ $$s$$.

A
$$43200$$

B
$$86636$$

C
$$21600$$

D
$$10800$$

Solution

A solar day is the time it takes for the Earth to rotate about its axis so that the Sun appears in the same position in the sky, which is equal to $$24\ hr\ 03\ min\ 55\ s$$, i.e. in total, $$86636\ seconds$$.
Question 9
1 / -0

What is the value of $$1$$ nano-second in second?

A
$$10^{-9}$$

B
$$10^{-6}$$

C
$$10^{-8}$$

D
$$10^{-10}$$

Solution

A nanosecond ($$ns$$) is an SI unit of time equal to one billionth of a second . One nanosecond is to one second as one second is to $$31.71\ years$$. The word nanosecond is formed by the prefix nano and the unit second. Its symbol is $$ns$$.
Question 10
1 / -0

With what speed should a car travel so that it can cover a distance of 5 km in 5 min?

A
1 km/h

B
5 km/h

C
12 km/h

D
60 km/h

Solution

Given,
Distance cover $$d=5\ km$$
Time $$t=5\ min$$ or $$t=5/60\ hr$$
Speed $$v=\dfrac{5}{5/60}=60\ km/hr$$
Option D

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Motion and Time Test - 9

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Motion and Time Test - 9

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Question 1

Metre

Kilometre

Second

None of these

Solution

Question 2

$$1 m s^{-1}$$

$$-1.33 m s^{-1}$$

$$2.75 m s^{-1}$$

$$-0.89 m s^{-1}$$

Solution

Question 3

$$1 \ m s^{-1}$$

$$2 \ m s^{-1}$$

$$2.75 \ m s^{-1}$$

$$0.89 \ m s^{-1}$$

Solution

Question 4

$$1 m s^{-1}$$

$$1.33 m s^{-1}$$

$$2.75 m s^{-1}$$

$$0 m s^{-1}$$

Solution

Question 5

A bullet travelling with a constant speed in a straight line.

A swinging pendulum

The earth rotating about its axis

Both B & C

Solution

Question 6

Speed = $$\frac { 1 }{ Distance\times Time } $$

Speed = $$\frac { Time }{ Distance } $$

Speed = $$\frac { Distance }{ Time } $$

Speed = Distance $$\times $$ Time

Solution

Question 7

Speedometer: Speed

Odometer : Odour

Anemometer : Wind speed

Stopwatch : Time

Solution

Question 8

$$43200$$

$$86636$$

$$21600$$

$$10800$$

Solution

Question 9

$$10^{-9}$$

$$10^{-6}$$

$$10^{-8}$$

$$10^{-10}$$

Solution

Question 10

1 km/h

5 km/h

12 km/h

60 km/h

Solution

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