Rational Numbers Test

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Rational Numbers Test - 19

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Weekly Quiz Competition

Question 1
1 / -0

Rational numbers are commutative under .........

A
subtraction

B
multiplication

C
division

D
none of these

Solution

For any two rational numbers $$a$$ and $$b, a\times b = b\times a$$. Thus, multiplication is commutative for rational numbers.
Question 2
1 / -0

The missing value in $$\dfrac {2}{3} \times \dfrac {5}{6} =..... \times \dfrac {2}{3}$$ is

A
$$\dfrac {2}{3}$$

B
$$\dfrac {3}{2}$$

C
$$\dfrac {5}{6}$$

D
$$\dfrac {6}{5}$$

Solution

Multiplication is commutative for rational numbers. i.e. $$a\times b = b\times a.$$
$$\therefore \dfrac {2}{3} \times \dfrac {5}{6} = \dfrac {5}{6} \times \dfrac {2}{3}$$
Question 3
1 / -0

If .............. is excluded from the collection of rational numbers, then they are closed under division.

A
$$2$$

B
$$1$$

C
$$0$$

D
$$-1$$

Solution

For any rational number $$"a", a\div 0$$ is not a rational number. So, if $$0$$ is excluded from the set of rational numbers, then they are closed under division operation.
Question 4
1 / -0

.............. are not commutative for rational numbers.

A
Subtraction and division

B
Multiplication and division

C
Multiplication and addition

D
Addition and subtraction

Solution

Subtraction and division are not commutative for rational numbers because while performing these operations, if the order of numbers is changed, then the result also changes.
Question 5
1 / -0

Operation of ....... is not commutative for rational numbers.

A
addition

B
multiplication

C
division

D
none of these

Solution

For any two rational numbers $$a$$ and $$b, a\div b$$ is not necessarily equal to $$b\div a$$. Thus, division is not commutative for rational numbers.
Question 6
1 / -0

Operation of ........... are commutative for rational numbers.

A
subtraction and division

B
multiplication and division

C
addition and subtraction

D
addition and multiplication

Solution

Two rational numbers can be added/ multiplied in any order and the result remains same.
For any two rational numbers $$a$$ and $$b$$,
$$a + b = b + a$$
$$a\times b = b\times a$$
$$\therefore$$ Addition and multiplication are commutative for rational numbers.
Question 7
1 / -0

Find the missing value: $$\dfrac {-5}{6} + \dfrac {19}{11} = ..... + \dfrac {-5}{6}$$

A
$$\dfrac {19}{11}$$

B
$$-\dfrac {19}{11}$$

C
$$\dfrac {5}{6}$$

D
$$\dfrac {-5}{6}$$

Solution

Addition is commutative for rational numbers.
i.e. $$a + b = b + a$$
$$\therefore \dfrac {-5}{6} + \dfrac {19}{11} = \dfrac {19}{11} + \dfrac {-5}{6}$$
Question 8
1 / -0

Fill the blank spaces: $$\dfrac {2}{8} + ......= \dfrac {-1}{6} + .......$$

A
$$\dfrac {-1}{6}, \dfrac {2}{8}$$

B
$$\dfrac {1}{6}, \dfrac {-2}{8}$$

C
$$\dfrac {2}{8}, \dfrac {-1}{6}$$

D
$$\dfrac {1}{6}, \dfrac {2}{8}$$

Solution

Addition is commutative for rational numbers i.e. $$a + b = b + a$$
$$\therefore \dfrac {2}{8} + \dfrac {-1}{6} = \dfrac {-1}{6} + \dfrac {2}{8}$$
$$\therefore$$ The missing numbers are $$\dfrac {-1}{6}, \dfrac {2}{8}$$
Question 9
1 / -0

Find the missing value: $$\dfrac {-4}{7} + \dfrac {-7}{11} = \dfrac {-7}{11} + .....$$

A
$$\dfrac {-4}{7}$$

B
$$\dfrac {-7}{4}$$

C
$$\dfrac {-7}{11}$$

D
$$\dfrac {7}{11}$$

Solution

Addition is commutative for rational numbers. i.e. $$a + b = b + a.$$
$$\therefore \dfrac {-4}{7} + \dfrac {-7}{11} = \dfrac {-7}{11} + \dfrac {-4}{7}$$
Question 10
1 / -0

Fill the blank spaces: $$\dfrac {4}{-9} \times ..... = \dfrac {7}{6} \times ....$$

A
$$\dfrac {-4}{9}, \dfrac {7}{6}$$

B
$$\dfrac {4}{-9}, \dfrac {7}{6}$$

C
$$\dfrac {7}{6}, \dfrac {4}{-9}$$

D
$$\dfrac {7}{6}, \dfrac {7}{6}$$

Solution

Multiplication is commutative for rational numbers. i.e. $$a\times b = b\times a.$$
$$\therefore \dfrac {4}{-9} \times \dfrac {7}{6} = \dfrac {7}{6} \times \dfrac {4}{-9}$$
$$\therefore$$ The missing terms are $$\dfrac {7}{6}, \dfrac {4}{-9}.$$

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Rational Numbers Test - 19

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Rational Numbers Test - 19

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SHARING IS CARING

Question 1

subtraction

multiplication

division

none of these

Solution

Question 2

$$\dfrac {2}{3}$$

$$\dfrac {3}{2}$$

$$\dfrac {5}{6}$$

$$\dfrac {6}{5}$$

Solution

Question 3

$$2$$

$$1$$

$$0$$

$$-1$$

Solution

Question 4

Subtraction and division

Multiplication and division

Multiplication and addition

Addition and subtraction

Solution

Question 5

addition

multiplication

division

none of these

Solution

Question 6

subtraction and division

multiplication and division

addition and subtraction

addition and multiplication

Solution

Question 7

$$\dfrac {19}{11}$$

$$-\dfrac {19}{11}$$

$$\dfrac {5}{6}$$

$$\dfrac {-5}{6}$$

Solution

Question 8

$$\dfrac {-1}{6}, \dfrac {2}{8}$$

$$\dfrac {1}{6}, \dfrac {-2}{8}$$

$$\dfrac {2}{8}, \dfrac {-1}{6}$$

$$\dfrac {1}{6}, \dfrac {2}{8}$$

Solution

Question 9

$$\dfrac {-4}{7}$$

$$\dfrac {-7}{4}$$

$$\dfrac {-7}{11}$$

$$\dfrac {7}{11}$$

Solution

Question 10

$$\dfrac {-4}{9}, \dfrac {7}{6}$$

$$\dfrac {4}{-9}, \dfrac {7}{6}$$

$$\dfrac {7}{6}, \dfrac {4}{-9}$$

$$\dfrac {7}{6}, \dfrac {7}{6}$$

Solution

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