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Rational Numbers Test - 20

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Rational Numbers Test - 20
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  • Question 1
    1 / -0
    Fill the blank spaces: $$....... + \dfrac {3}{7} = ...... + \dfrac {3}{8}$$
    Solution
    Addition is commutative for rational numbers. i.e. $$a + b = b + a$$
    $$\therefore \dfrac {3}{8} + \dfrac {3}{7} = \dfrac {3}{7} + \dfrac {3}{8}$$
    $$\therefore$$ The missing terms are $$\dfrac {3}{8}, \dfrac {3}{7}$$
  • Question 2
    1 / -0
    The missing value in $$........ + \dfrac {2}{7} = \dfrac {2}{7} + \dfrac {-11}{13}$$ is
    Solution
    Addition is commutative for rational numbers. i.e. $$a + b = b + a$$
    $$\therefore \dfrac {-11}{13} + \dfrac {2}{7} = \dfrac {2}{7} + \dfrac {-11}{13}$$
  • Question 3
    1 / -0
    Fill in the blank: $$\left (-\dfrac {1}{3}\right ) + \left [\left (\dfrac {-4}{3}\right ) + \dfrac {3}{7}\right ] = \left [\left (\dfrac {-1}{3}\right ) + ..... \right ] + \dfrac {3}{7}$$
    Solution
    Addition is associative for rational numbers
    i.e. $$a + (b + c) = (a + b) + c$$
    $$\therefore \left (-\dfrac {1}{3}\right ) + \left [\left (\dfrac {-4}{3}\right ) + \dfrac {3}{7}\right ] = \left [\left (\dfrac {-1}{3}\right ) + \left (\dfrac {-4}{3}\right ) \right ] + \dfrac {3}{7}$$
  • Question 4
    1 / -0
    ......... are associative for rational numbers.
    Solution
    Multiplication and addition are associative for rational numbers because when any three rational numbers are added or multiplied, the result so obtained will remain the same irrespective of the change in their order. i.e. $$a + (b + c) = (a + b) + c$$
    $$a\times (b\times c) = (a\times b)\times c$$.
  • Question 5
    1 / -0
    Which property is depicted by $$\dfrac {1}{2} \times \left (6\times \dfrac {4}{3}\right ) = \left (\dfrac {1}{2} \times 6 \right )\times \dfrac {4}{3}$$?
    Solution
    For any three rational numbers, their product remains the same irrespective of their orders. i.e. $$a\times (b\times c) = (a\times b)\times c$$.
    $$\therefore$$ Here, associative property is depicted.
  • Question 6
    1 / -0
    Find the missing value: $$-61 + ....... = \dfrac {2}{3} + (-61)$$
    Solution
    Addition is commutative for rational numbers. i.e. $$a + b = b + a.$$
    $$\therefore -61 + \dfrac {2}{3} = \dfrac {2}{3} + (-61)$$
  • Question 7
    1 / -0
    ................. are not associative for rational numbers.
    Solution
    Let us add three rational numbers $$\dfrac{-7}{5},\ \dfrac{2}{-11}$$ and $$\dfrac{-13}{25}$$

    Then we know $$ \displaystyle \frac{-7}{5} + \left(\displaystyle \frac{2}{-11} + \frac{-13}{25} \right) = \left(\displaystyle \dfrac{-7}{5} + \frac{2}{-11} \right) + \frac{-13}{25}$$

    So we can say that addition is associative for rational numbers. 

    Now let us multiply three rational numbers $$\dfrac  16,\ 6, \ \dfrac 43$$

    Then we get $$\displaystyle \frac{1}{3}\times \left ( 6 \times\frac{4}{3} \right )= \left ( \frac{1}{3} \times 6\right )\times \frac{4}{3}$$

    So we can say that multiplication is associative for rational numbers. 

    But when we divide three rational numbers in an order, the result so obtained will change if the order is changed. 

    For example: $$(81\div 9)\div 3\ne $$ $$81\div(9\div 3)$$

    And when we subtract three rational numbers, the result changes when we change the order of subtraction

    For example: $$5-(3-9)\ne (5-3)-2$$

    Therefore, subtraction and division are not associative for rational numbers.
  • Question 8
    1 / -0
    Simplify using commutative and associative property :
    $$\dfrac {2}{9} + \dfrac {-3}{5} + \dfrac {1}{3}$$
    Solution
    $$\dfrac {2}{9} + \dfrac {-3}{5} + \dfrac {1}{3} = \dfrac {2}{9} + \left (\dfrac {-3}{5} + \dfrac {1}{3}\right )$$

    $$= \dfrac {2}{9}  + \left (\dfrac {1}{3} + \dfrac {-3}{5}\right )$$ (commutative property)

    $$=\left (\dfrac {2}{9} + \dfrac {1}{3}\right ) + \dfrac {-3}{5}$$ (associative property)

    $$= \dfrac {2 + 3}{9} + \dfrac {-3}{5}$$

    $$= \dfrac {5}{9} + \dfrac {-3}{5}$$

    $$= \dfrac {25 - 27}{45}$$

    $$= \dfrac {-2}{45}$$
  • Question 9
    1 / -0
    ................. is the additive inverse of $$\dfrac {-p}{q}$$, where $$\dfrac {-p}{q}$$ is a rational number.
    Solution
    If $$\left (\dfrac {-p}{q}\right )$$ is a rational number, then its negative $$\left [ - \left (\dfrac {-p}{q}\right ) = \dfrac {p}{q}\right ]$$ is called the additive inverse of $$\dfrac {-p}{q}$$.
    Also addition of 
    $$\left (\dfrac {-p}{q}\right )$$ and $$\left (\dfrac {p}{q}\right )$$ results zero.
  • Question 10
    1 / -0
    For any integer $$a$$, its additive inverse is ..........
    Solution
    The additive inverse of a number $$a$$ is the number that, when added to $$a$$ yields zero. 

    This number is also known as the negative, or negation. 

    If $$a$$ is an integer, then its negative or additive inverse is $$(-a)$$
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