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Mensuration Test - 13

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Mensuration Test - 13
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  • Question 1
    1 / -0
    If the curved surface area of a cylinder is $$1760$$ sq.cm and its base radius is $$14$$ cm, then its height is:
    Solution

    Given, curved surface varea of cone $$=1760$$ sq.cm and radius $$=14$$ cm

    Curved surface area of a cylinder of radius "$$R$$" and height "$$h$$" $$ = 2\pi Rh$$

    Hence, curved surface area of the given cylinder $$ = 2\times \dfrac {22}{7} \times 14\times h =  1760 $$sq.cm

    $$ \therefore  h = 20 $$ cm

  • Question 2
    1 / -0
    Find the surface area of a cube whose edge is $$15\ cm$$
    Solution
    The edge of the cube$$=15cm$$ i.e., $$a=15cm$$
    Surface area of the cube $$=6{a}^{2}=6\times {(15)}^{2}=1350{cm}^{2}$$
  • Question 3
    1 / -0
    If $$l = 150 cm, b = 1 m$$ and $$h = 2 m$$ then, the volume of the cuboid is
    Solution
    Volume of a cuboid with dimensions as $$l,\ b,\ and\ h=lbh$$
    Converting all the given dimensions to centimeters.
    Hence, volume of the given cuboid $$=150 \times 100 \times 200 =30,00,000$$ cu.cm
  • Question 4
    1 / -0
    The radius of the cylinder whose lateral surface area is $$704{cm}^{2}$$ and height $$8$$ cm is:
    Solution

    Curved surface area of a cylinder of radius "$$R$$" and height "$$h$$" $$ = 2\pi Rh$$
    Hence, Curved surface area of the given cylinder $$ = 2\times \dfrac {22}{7} \times r \times  8 =  704  $$

    $$ \therefore  r = 14 $$ cm

    Radius of the base of the cylinder is $$ 14  $$ cm

  • Question 5
    1 / -0
    The volume of a solid is the measurement of the portion of the space occupied by it.
    State True or False.
    Solution
    The volume of a solid is defined as the space occupied by the solid shape in 3-dimensional region.

    For example: Let us say that there is a glass of water; The amount of water the glass can hold is called volume of the glass.
  • Question 6
    1 / -0
    The total surface area of a solid right cylinder of radius $$r$$ and height $$h$$ is $$2\pi r(h+r)$$
    Solution
    The curved surface area for a cylinder is $$2(\pi)rh$$
    Total surface area = curved surface area +area of the two circles$$= 2(\pi)rh+2(\pi)r^2$$
    $$=2(\pi)r(r+h)$$

  • Question 7
    1 / -0
    The surface area of a cube of side is $$27\ \text{cm}$$ is:
    Solution

    Surface area of a cube of side $$a$$ is given by, $$S=6\ a^2$$

    The side of cube is given , $$a=27\ \mathrm{cm}$$

    Total surface area of given cube of side $$a = 6{a}^{2}=6\times 27^2\ \mathrm{cm}^2 $$
                                                                           $$= 4374\ \mathrm{cm}^{2} $$

  • Question 8
    1 / -0
    Volume of a cuboid whose $$l=3.5$$ m, $$b =2.5$$ m and $$h =1.5$$ m is
    Solution
    Since, volume of cuboid $$=$$ length $$\times$$ breadth $$\times$$ height

    Here, length $$=$$ $$3.5$$ m, breadth $$=$$ $$2.5$$ m and height $$=$$ $$1.5$$ m

    $$\therefore$$ Volume of cuboid $$=$$ $$3.5\times 2.5\times 1.5 = 13.125 m^3 $$
  • Question 9
    1 / -0
    $$l \times b \times h$$ is formula of---
    Solution
    Correct answer is C.
  • Question 10
    1 / -0
    A reservoir is 3 m long, 2 m wide and 1 deep. Its capacity in litres is
    Solution
    Volume of the reservoir = l x b x h=3 x 2 x 1=6 cu m
    $$\displaystyle \left ( \because 1 cu\,  m = 1000 litre \right )$$
    ($$\displaystyle \because $$ Capacity of the reservoir =6 x 1000 =6000 litre.
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