Mensuration Test

Result

Mensuration Test - 33

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following is the formula for the volume of the cubiod

A
$$V=lbh$$

B
$$V=lh$$

C
$$V=lb$$

D
$$V=l^2bh$$

Solution

We know,
Volume of cuboid = $$length \times breadth \times height$$
Therefore, $$V=lbh$$
Hence, option A is correct.
Question 2
1 / -0

Mohit painted the outside of a box of length $$2.5m$$, breadth $$2m$$ and height $$1m$$. How much area did he cover, if he painted all except the bottom of the box?

A
$$20m^2$$

B
$$16m^2$$

C
$$54m^2$$

D
$$14m^2$$

Solution

Area Mohit painted $$= 2(2.5\times 2+2\times 1+2.5\times 1)-(2.5\times 2)$$
$$=2(5+2+2.5)-(5)$$
$$=2(9.5)-5$$
$$=19-5$$
$$=14m^{2}$$
Question 3
1 / -0

An aquarium is in the form of a cuboid whose external measures are $$80cm\times 30cm\times 40cm$$. The base side faces and back face are to be covered with a coloured paper. Find the area of the paper needed?

A
$$3000cm^2$$

B
$$5000cm^2$$

C
$$8000cm^2$$

D
$$7000cm^2$$

Solution

Area of paper required $$=$$ area of base $$+$$ 2 area of side $$+$$ area of back
$$ =(80 \times 30) + 2(30 \times 40)+(80 \times 40) $$
$$=2400+2400+3200 $$
$$=8000cm^{2}$$
Question 4
1 / -0

The two parallel sides of a trapezium are $$1.5m$$ and $$2.5m$$ respectively. If the perpendicular distance between them is $$6.5$$ metres, the area of the trapezium is:

A
$$10{m}^{2}$$

B
$$13{m}^{2}$$

C
$$20{m}^{2}$$

D
$$26{m}^{2}$$

Solution

Area of trapezium $$=\dfrac{h}{2}$$ (sum of parallel sides)
$$=\dfrac{6.5}{2}(1.5+2.5)= \dfrac{6.5}{2}\times 4$$
$$= 13m^{2}$$
Question 5
1 / -0

The ratio of the length of the parallel sides of a trapezium is $$5:3$$ and the distance between them is $$16 cm$$. If the area of the trapezium is $$960 cm^2$$, find the length of the parallel sides.

A
$$45cm$$ and $$65cm$$

B
$$35cm$$ and $$75cm$$

C
$$45cm$$ and $$75cm$$

D
$$55cm$$ and $$75cm$$

Solution

Let the sides be $$5x$$ and $$3x$$
Given
$$h=16\ cm$$
$$A=960\ cm^2$$
Now, Area is given as
$$960=\dfrac{1}{2}\times16\times(5x+3x)$$
$$960=8\times8x$$
$$64x=960$$
$$x=15$$
$$5x=5\times15=75$$
$$3x=3\times15=45$$
Therefore, the parallel sides are 45 cm and 75 cm.
Question 6
1 / -0

The curved surface area of a cylinder of the base radius $$7\text{ cm}$$ and height $$25\text{ cm}$$.

A
$$1100\text{ cm}^3$$

B
$$1100\text{ cm}^2$$

C
$$1408\text{ cm}^3$$

D
$$1408\text{ cm}^2$$

Solution

$$\because$$ Curved Surface area of cylinder $$=2\pi rh$$
Given:
$$r=$$ radius $$=7\text{ cm}$$
$$h=$$ height $$=25\text{ cm}$$
$$\therefore$$ Curved Surface Area $$=2\times \cfrac{22}{7}\times 7\times 25$$ $$\text{cm}^{2}$$
$$=50\times 22$$ $$\text{cm}^{2}$$
$$\therefore$$ Curved Surface Area of cylinder $$=1100\text{ cm}^{2}$$
Question 7
1 / -0

If the length of the parallel sides of a trapezium are $$8\ cm, 9\ cm$$ and the distance between the parallel sides is $$6\ cm$$, then its area is

A
$$51\ cm^{2}$$

B
$$68\ cm^{2}$$

C
$$34\ cm^{2}$$

D
$$72\ cm^{2}$$

Solution

Length of parallel sides$$=8$$ cm, $$9$$ cm
Distance between parallel sides$$=6$$ cm
Area $$=\cfrac { 1 }{ 2 } $$ (distance between parallel sides)$$\times$$ (sum of parallel sides)
$$=\cfrac { 1 }{ 2 } \times 6\times (8+9)\\ =3\times 17=51$$
Question 8
1 / -0

A water tank is 1.4m long, 1m wide and 0.7m deep, then the volume of the tank in litres

A
780 Litres

B
860 Litres

C
980 Litres

D
none of these

Solution

Water tank is $$1.4m$$ long, $$1m$$ wide and $$0.7m$$ deep
Volume of tank $$=1.4\times 1\times 0.7$$
$$=0.98{ m }^{ 3 }$$
$$=0.98\times 1000$$ litres
$$=980$$ litres
Answer (C)
Question 9
1 / -0

The perimeter of a trapezium is $$72\ cm$$ an its non-parallel sides are $$12\ cm$$ each. If its height is $$16\ cm$$, the area will

A
$$384\ cm^{2}$$

B
$$288\ cm^{2}$$

C
$$576\ cm^{2}$$

D
$$768\ cm^{2}$$

Solution
Question 10
1 / -0

The perimeter of the trepezium is 52 cm and its each non-parallel side is equal to 10 cm with its height 8 cm . Its area is

A
$$124c{m^2}$$

B
$$118c{m^2}$$

C
$$128c{m^2}$$

D
$$112c{m^2}$$

Solution

Using pythagoras theorem, we have
$$x=\sqrt{10^{2}-8^{2}}$$
= 6 cm
$$\therefore y+10+10+x+y+x=52$$
$$2y+20+12=52\Rightarrow 2y=20$$
y = 10 cm
Area = $$\frac{1}{2}\times (y+x+y+x)\times 8= 16\times 8$$
$$ = 128 cm^{2}$$

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Re-Attempt Weekly Quiz Competition

Mensuration Test - 33

Result

Mensuration Test - 33

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SHARING IS CARING

Question 1

$$V=lbh$$

$$V=lh$$

$$V=lb$$

$$V=l^2bh$$

Solution

Question 2

$$20m^2$$

$$16m^2$$

$$54m^2$$

$$14m^2$$

Solution

Question 3

$$3000cm^2$$

$$5000cm^2$$

$$8000cm^2$$

$$7000cm^2$$

Solution

Question 4

$$10{m}^{2}$$

$$13{m}^{2}$$

$$20{m}^{2}$$

$$26{m}^{2}$$

Solution

Question 5

$$45cm$$ and $$65cm$$

$$35cm$$ and $$75cm$$

$$45cm$$ and $$75cm$$

$$55cm$$ and $$75cm$$

Solution

Question 6

$$1100\text{ cm}^3$$

$$1100\text{ cm}^2$$

$$1408\text{ cm}^3$$

$$1408\text{ cm}^2$$

Solution

Question 7

$$51\ cm^{2}$$

$$68\ cm^{2}$$

$$34\ cm^{2}$$

$$72\ cm^{2}$$

Solution

Question 8

780 Litres

860 Litres

980 Litres

none of these

Solution

Question 9

$$384\ cm^{2}$$

$$288\ cm^{2}$$

$$576\ cm^{2}$$

$$768\ cm^{2}$$

Solution

Question 10

$$124c{m^2}$$

$$118c{m^2}$$

$$128c{m^2}$$

$$112c{m^2}$$

Solution

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