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Mensuration Test - 34

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Mensuration Test - 34
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The diameter of the base of a right circular cylinder is $$21\mathrm { cm }$$ and its height is $$10\ \mathrm { cm }$$ . What is the area of the curved surface? 
    Solution
    $$Diameter =21\ cm$$
    $$Radius=\dfrac{21}{2}\ cm$$
    $$Height=10\ cm$$
    We know that the curved surface area of the cylinder
    $$=2\pi r h$$
    $$=2\times \dfrac{22}{7}\times \dfrac{21}{2}\times 10$$
    $$=220\times 3$$
    $$=660\ cm^2$$
  • Question 2
    1 / -0
    The diameter of a cylinder is $$28$$cm and its height is $$20$$cm find the curved surface area.
    Solution
    Diameter of the cylinder $$=28$$cm

    $$\therefore$$ Radius of the cylinder $$=\dfrac{28}{2}$$
                                         $$=14$$cm

    Height of the cylinder $$=20$$cm

    $$\text{Curved surface area}=2\pi rh\\=2\times \dfrac{22}{7}\times 14\times 20\\=1760\ sq.cm$$
  • Question 3
    1 / -0
    The diameter of a cylinder is $$28$$cm and its height is $$20$$cm find the total surface area.
    Solution
    Diameter of the cylinder$$=28$$cm

    $$\therefore$$ Radius of the cylinder$$=r=\dfrac{28}{2}=14$$cm

    Height of the cylinder$$=h=20$$cm

    Total surface area $$=2\pi r\left(r+h\right)$$

    $$=2\times\dfrac{22}{7}\times 14\times\left(14+20\right)$$

    $$=2992$$sq.cm
  • Question 4
    1 / -0
    The area of trapezium $$ABCD$$ is 

    Solution
    Area of a trapezium$$=\dfrac{1}{2}\times$$(Sum of parallel sides)$$\times$$distance between them.
    $$=\dfrac{1}{2}\times\left(6+8\right)\times 4$$
    $$=14\times 2\\=28\ sq.cm$$
    $$\therefore$$Area of a trapezium$$=28$$sq.cms
  • Question 5
    1 / -0
    The area of given trapezium is 

    Solution

  • Question 6
    1 / -0
    Volume of a rectangular box (cuboid) with length $$=2ab,$$ breadth $$=3ac$$ and height $$=2ac$$ is 
    Solution
    Given

    Length $$=2ab$$

    Breadth $$=3ac$$

    Height $$=2ac$$

    Volume of cuboid $$=$$ length $$\times$$ breadth $$\times$$ height

    $$=2ab\times 3ac\times 2ac$$

    $$=12a^3bc^2$$

    $$\therefore$$ Hence the correct answer is $$12a^3bc^2$$.
  • Question 7
    1 / -0
    Find the total surface area of the cuboids of length, breadth and height 
    $$12 \mathrm { cm } , 10 \mathrm { cm } , 5 \mathrm { cm }$$ respectively.
    Solution

  • Question 8
    1 / -0
    Mark the correct alternative of the following.
    The number of surfaces of a hollow cylindrical object is?
    Solution
    The hollow cylinder has a total of 4 surfaces,  inner and outer curved surfaces and the ring lies at the base of the cylinder and the top of the cylinder

  • Question 9
    1 / -0
    Mark the correct alternative of the following.
    A cylinder with radius $$r$$ and height $$h$$ is closed on the top and bottom. Which of the following expressions represents the total surface area of this cylinder?
    Solution
    Let $$S$$ be the total surface area of the closed cylinder with radius $$r$$ and height $$h$$, then,
    Total surface area of this cylinder $$(S)= 2πrh  + πr^2+ πr^2$$
    $$\Rightarrow$$  $$S=2\pi r^2+2\pi r h$$
    $$\Rightarrow$$  $$S=2\pi r(r+h)$$
  • Question 10
    1 / -0
    A right circular cylindrical tunnel of diameter $$2$$m and length $$40$$m is to be constructed from a sheet of iron. The area of the iron sheet required in $$m^2$$, is?
    Solution
    Let $$r$$ be the radius of the cylinder and $$h$$be its height.
    It is given that,
    $$d=2\,m$$
    Then, $$r=\dfrac{2m}{2}=1\,m$$
    $$h=40\,m$$
    $$\therefore$$  Total surface area of sheet required is:
    $$\Rightarrow$$  $$S=2\pi rh$$
              $$=2\pi\times 1\times 40$$
              $$=80\pi \,m^2$$
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