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Exponents and Powers Test - 16

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Exponents and Powers Test - 16
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following has a negative index?
    Solution
    $$\dfrac{1}{x^3}=x^{-3}$$ . Index of $$x$$ is  $$(-3)$$, which is negative.

    Hence, option $$D$$ is correct.
  • Question 2
    1 / -0
    Which of the following has a negative index?
    Solution
    $$\dfrac{1}{x} = x^{-1}$$. Index of $$x$$ is $$(-1)$$, which is negative.

    Hence, option $$B$$ is correct
  • Question 3
    1 / -0
    $$\left \{ \left (\dfrac {3}{4}\right )^{-1} - \left (\dfrac {1}{4}\right )^{-1}\right \}^{-1} = ?$$
    Solution
    We need to find value of $$\left \{ \left (\dfrac {3}{4}\right )^{-1} - \left (\dfrac {1}{4}\right )^{-1}\right \}^{-1} $$
    It can be written as $$\left (\dfrac {4}{3} - 4\right)^{-1}$$ $$=$$ $$\left (\dfrac {-8}{3}\right)^{-1}$$ $$=$$ $$-\dfrac {3}{8}$$
  • Question 4
    1 / -0
    Which of the following has a negative index?
    Solution
    $$\dfrac { 1 }{ { x }^{ 2 } } $$ = $${ x }^{ -2 }$$
    Thus $${ x }^{ -2 }$$ has a negative index
    Therefore option $$A$$ is the correct answer.
  • Question 5
    1 / -0
    Which of the following has a negative index?
    Solution
    Option A has positive index i.e. $$\dfrac {1}{4}$$.
    Option B also has positive index i.e., $$\dfrac {2}{3}$$
    In option C, $$\dfrac{1}{x^2} = x^{-2}$$.  
    Index of $$x$$ is $$(-2)$$, which is negative.
    Hence, option C is correct
  • Question 6
    1 / -0
    Simplify:
    $$\left(\dfrac{27}{125}\right)^{-1}=$$
    Solution
    $${\left(\dfrac{125}{27}\right)}^{1}$$ using $$\dfrac{1}{{a}^{m}}={a}^{-m}$$
    $$=\dfrac{{5}^{3}}{{3}^{3}}$$
    $$={\left(\dfrac{5}{3}\right)}^{3}$$
  • Question 7
    1 / -0
    Choose the correct answer from the given four options:
    $$\bigg(-\dfrac{3}{2}\bigg)^{-1}$$ is equal

    Solution
    $$\bigg(-\dfrac{3}{2}\bigg)^{-1} =-\dfrac{2}{3}$$
  • Question 8
    1 / -0
    Fill in the blanks:
    $$0.000008$$ _______ $$0.000016$$
  • Question 9
    1 / -0
    Difference of the greatest $$7$$ digit number and the smallest $$ 5$$ digit number is
    Solution
    $$\textbf{Step-1: Find greatest 7 digit number and smallest 5 digit number}$$
                    $$\text{We know greatest n digit number is= 9999..n times }$$
                    $$\text{And smallest n digit number is= 10000..(n-1) times }$$
                   $$\text{ So 7- digit greatest number}$$$$=99,99,999$$
                    $$\text{And 5-digit smallest number}$$ $$=10,000$$

    $$\textbf{Step-2: Find Difference}$$
                    $$\text{Difference}$$ $$=99,99,999-10,000=99,89,999$$

    $$\textbf{Hence Option B is correct.}$$
  • Question 10
    1 / -0
    Fill in blank with an appropriate comparison symbol. 
    $$0.00000998$$ ______ $$0.0000116$$
    Solution
    $$\displaystyle 0\cdot 00000998= 9\cdot 89\times 10^{-6}$$
    $$\displaystyle 0\cdot 0000116= 1\cdot 16\times 10^{-5}$$
    Thus $$\displaystyle 9\cdot 89\times 10^{-6}< 1\cdot 16\times 10^{-5}$$
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