Playing with Numbers Test

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Playing with Numbers Test - 15

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Weekly Quiz Competition

Question 1
1 / -0

Find the number that should be added to $$98137432$$ to make it exactly divisible by $$10$$?

A
$$12$$

B
$$13$$

C
$$8$$

D
$$4$$

Solution

When we divide $$98137432$$ by $$10$$, we get a remainder $$2$$.
In order to make the number completely divisible by $$10$$, we need to add $$8$$ to it.
So, option C is correct.
Question 2
1 / -0

What is the number should be added to $$65328$$ to make it exactly divisible by $$10$$?

A
$$0$$

B
$$2$$

C
$$6$$

D
$$8$$

Solution

When the number $$65328$$ is divided by $$10$$, we get a remainder $$8$$.
So, in order to make the number completely divisible by $$10$$, we must add $$2$$ to it.
So, option B is correct.
Question 3
1 / -0

How many numbers are divisible by $$10$$?
$$290, 397, 375, 100, 1970, 280, 350, 409, 710$$

A
$$5$$

B
$$6$$

C
$$7$$

D
$$8$$

Solution

We know the divisibility rule for $$10$$: The last digit is $$0$$
Here $$290, 100, 1970, 280, 350$$ and $$710$$ are divisible by $$10$$.
Since the last digit is $$0$$.
Therefore, option B is correct.
Question 4
1 / -0

Which number is divisible by $$3$$?

A
$$68$$

B
$$45$$

C
$$20$$

D
$$65$$

Solution

$${\textbf{Step  -  1 : Describe the rules of divisibility test of 3}}{\text{.}}$$

$${\text{As per the rule , any number can divisible by 3 if and only if}}$$
$${\text{ the last sum of the digits of this number is a multiple of 3,itself}}{\text{.}}$$

$${\textbf{Step  -  2 : Check with divisibility test for the options}}{\text{. }}$$

$${\text{For option A, The sum of digits of 68 is}}=6+8=14{\text{.}}$$

                      $${\text{So obviously 14 is not a multiple of 3.So 68 is not divisible by 3.}}$$

$${\text{For option B, The sum of digits of 45 is}}=4+5=9{\text{.}}$$

                      $${\text{So 9 ist a multiple of 3.So 45 is divisible by 3.}}$$

$${\text{For option C, The sum of digits of 20 is}}=2+0=2{\text{.}}$$

                      $${\text{So obviously 2 is not a multiple of 3.So 20 is not divisible by 3.}}$$

   $${\text{For option D, The sum of digits of 65 is}}=6+5=11{\text{.}}$$

                      $${\text{So obviously 11 is not a multiple of 3.So 65 is not divisible by 3.}}$$

$${\textbf{Hence, The number which is divisible by 3 is 45(B)}}{\text{.}}$$
Question 5
1 / -0

What is the number that should be added to $$27549$$ to make it exactly divisible by $$3$$?

A
$$0$$

B
$$2$$

C
$$4$$

D
$$5$$

Solution

If sum of digits of a number is divisible by $$3$$ then that number is also divisible by $$3$$.
Here, $$2 + 7 + 5 + 4 + 9 = 27$$, which is a multiple of $$3$$.
Hence, no addition is required to make this number to be divisible by $$3$$.

So, option A is correct.
Question 6
1 / -0

How many numbers are divisible by $$10$$?
$$210, 457, 455, 650, 1000, 3982, 290, 101, 370$$

A
$$5$$

B
$$4$$

C
$$3$$

D
$$2$$

Solution

We know the divisibility rule for $$10$$: The last digit is $$0$$.
Here, $$210, 650, 1000, 290$$ and $$370$$ is divisible by $$10$$.
Therefore, there are $$5$$ numbers divisible by $$10$$.

So, option A is correct.
Question 7
1 / -0

Which of the following number should be added to $$75329$$ to make it exactly divisible by $$10$$?

A
$$4$$

B
$$3$$

C
$$2$$

D
$$1$$

Solution

When we divide $$75329$$ by $$10$$, we get a remainder $$9$$.
Hence, we need to add $$1$$ to the given number in order to make it divisible by $$10$$.
So, option D is correct.
Question 8
1 / -0

What is the value of $$B$$?
$$ 2 \ B$$
x $$6$$
______
$$1 B \ 0$$

A
$$3$$

B
$$4$$

C
$$5$$

D
$$6$$

Solution

$$2 B$$
x $$6$$
______
$$1 B \ 0$$

The multiplication of $$B$$ and $$6$$ is giving $$0$$ i.e., $$B \times 6 = 0$$
The above condition is possible only when digit $$B$$ is $$5$$, because $$5 \times 6 = 30$$.
Ones digit will be $$0$$. $$3$$ will be carry for the next step to get the value as $$15$$.
Therefore, the multiplication is as follows:
3
$$2 5$$
X $$6$$
____
$$15 0$$

So, option $$C$$ is correct.
Question 9
1 / -0

Find the value of $$A$$:
$$2 \ A$$
x $$ A$$
_______
$$15 A$$

A
$$5$$

B
$$6$$

C
$$7$$

D
$$8$$

Solution

$$2 \ A$$
x $$A$$
____
$$15\ A$$
The multiplication of $$A$$ and $$A$$ is giving $$A$$ i.e., $$A \times A = A$$
The above condition is possible only when digit $$A$$ is $$6$$, because $$6 \times 6 = 36$$.
Ones digit will be $$6$$. $$3$$ will be carry for the next step to get the value as $$15$$.
Therefore, the multiplication is as follows:
3
$$2 6$$
X $$ 6$$
____
$$15 6$$
So, the value of $$A$$ is $$6$$.
Question 10
1 / -0

What is the largest $$3$$ digit number exactly divisible by $$3$$?

A
$$972$$

B
$$990$$

C
$$996$$

D
$$993$$

Solution

We know the divisibility rule for $$3$$:
If the sum of the digits of a number is divisible by $$3$$, then the number is also divisible by $$3$$.
Here, $$9 + 9 + 6 = 24$$ is multiple of $$3$$.
So, $$996$$ is the largest number divisible by $$3$$.

So, option C is correct.

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Re-Attempt Weekly Quiz Competition

Playing with Numbers Test - 15

Result

Playing with Numbers Test - 15

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SHARING IS CARING

Question 1

$$12$$

$$13$$

$$8$$

$$4$$

Solution

Question 2

$$0$$

$$2$$

$$6$$

$$8$$

Solution

Question 3

$$5$$

$$6$$

$$7$$

$$8$$

Solution

Question 4

$$68$$

$$45$$

$$20$$

$$65$$

Solution

Question 5

$$0$$

$$2$$

$$4$$

$$5$$

Solution

Question 6

$$5$$

$$4$$

$$3$$

$$2$$

Solution

Question 7

$$4$$

$$3$$

$$2$$

$$1$$

Solution

Question 8

$$3$$

$$4$$

$$5$$

$$6$$

Solution

Question 9

$$5$$

$$6$$

$$7$$

$$8$$

Solution

Question 10

$$972$$

$$990$$

$$996$$

$$993$$

Solution

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